Hi Rui,
I use the code to fix my problem:
try$newcol <- gsub(" NA", "", try$newcol)
But, I'll try your solution later.
Thank you for your help.
Kai On Wednesday, June 2, 2021, 02:08:18 PM PDT, Kai Yang via R-help
wrote:
Hi List,
I use paste function to concatenate 3 character columns tog
Hello,
Something like this?
df1 <- read.table(text = "
NA NA NA
NA NA Adenocarcinoma
NA Other NA")
df1
apply(df1, 1, function(x){
if(all(is.na(x))){
NA_character_
}else{
paste(x[!is.na(x)], collapse = "")
}
})
And please configure your e-mail client not to post in HTML format.
Hi List,
I use paste function to concatenate 3 character columns together.
when I run table to see that, I found 3 categories. How can I write script to
trim NA in 2nd and 3rd group and set the first one as NA?
Thanks,
Kai
NA NA NA
NA NA Adenocarcinoma
NA Other NA
[[alternative HTML ver
elp-boun...@r-project.org] On Behalf Of Michael
> Dewey
> Sent: Monday, April 06, 2015 14:55
> To: Carlijn Wibbelink; r-help@r-project.org
> Subject: Re: [R] Trim and fill procedure
>
> Hello Carlijn
>
> Well the documentation for trimfill says they are added.
>
&g
Hello Carlijn
Well the documentation for trimfill says they are added.
library(metafor)
example(trimfill)
This now leaves you with
res
res.tf
By looking at these and seeing which vectors have grown you should be
able to extract the yi and vi which you want.
Wolfgang will doubtless be on the
Hi all,
I have a question concerning the trim and fill procedure in metafor. In STATA
it is possible to obtain the values of the added estimated effect sizes. I was
wondering if this is also possible in R and if so, how I can obtain the new
data with the added values.
I would really appreciate
On 05-12-2012, at 11:46, Vasilchenko Aleksander wrote:
> Hello,
> I have a dataframe
>
> 1 2006-11 NaN
> 2 2006-12 NaN
> 3 2006-10 0.1577647
> 4 2006-11 NaN
> 5 2006-12 NaN
> 6 2007-01 NaN
> 7 2007-02 NaN
> 8 2007-03 0.2956429
> 9 2007-01 NaN
> 10 2007-0
nal Message -
From: Rui Barradas
To: Vasilchenko Aleksander
Cc: r-help@r-project.org
Sent: Wednesday, December 5, 2012 7:59 AM
Subject: Re: [R] Trim
Hello,
Try the following.
dat <-
structure(list(V1 = structure(c(2L, 3L, 1L, 2L, 3L, 4L, 5L, 6L,
4L, 5L), .Label = c("2006-10", &qu
om: Vasilchenko Aleksander
To: r-help@r-project.org
Cc:
Sent: Wednesday, December 5, 2012 5:46 AM
Subject: [R] Trim
Hello,
I have a dataframe
1 2006-11 NaN
2 2006-12 NaN
3 2006-10 0.1577647
4 2006-11 NaN
5 2006-12 NaN
6 2007-01 NaN
7 2007-02 NaN
8 2007-03 0.2
Hello,
Try the following.
dat <-
structure(list(V1 = structure(c(2L, 3L, 1L, 2L, 3L, 4L, 5L, 6L,
4L, 5L), .Label = c("2006-10", "2006-11", "2006-12", "2007-01",
"2007-02", "2007-03"), class = "factor"), V2 = c(NaN, NaN, 0.1577647,
NaN, NaN, NaN, NaN, 0.2956429, NaN, NaN)), .Names = c("V1", "V2"
Hello,
I have a dataframe
1 2006-11 NaN
2 2006-12 NaN
3 2006-10 0.1577647
4 2006-11 NaN
5 2006-12 NaN
6 2007-01 NaN
7 2007-02 NaN
8 2007-03 0.2956429
9 2007-01 NaN
10 2007-02 NaN
I need to trim first and last NaN rows
Result -
1 2006-10 0.1577647
2 2
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