The row means **are** new variables and can be put wherever you like.
But all columns in a data frame **must** have the same number of rows,
so you'll have to fill in missing values as appropriate. That's where
you need to "adjust as necessary to your needs."
-- Bert
Bert Gunter
"The trouble w
Dear Bert,
Thank you very much.This works. I was wondering if the fact that I want to
create new variables (sorry for not stating that fact) makes any
difference? Thank you again.
Sincerely,
Milu
On Sun, Mar 25, 2018 at 10:05 PM, Bert Gunter
wrote:
> I am sure that this sort of thing has been
I am sure that this sort of thing has been asked and answered before,
so in case my suggestions don't work for you, just search the archives
a bit more.
I am also sure that it can be handled directly by numerous functions
in numerous packages, e.g. via time series methods or by calculating
running
There is no `value` column in the `dput` output shown in the
question so using `tmin` instead note that the `width=` argument
of `rollapply` can be a list containing a vector of offsets (-1 is prior
value, -2 is value before that, etc.) and that we can use `rollapplyr`
with an `r` on the end to ge
Dear all,
I have weekly data by city (variable citycode). I would like to take the
average of the previous two, three, four weeks (without the current week)
of the variable called value.
This is what I have tried to compute the average of the two previous weeks;
df = df %>%
mutate(value.lag1 =
5 matches
Mail list logo
