Thank you guys for your suggestions! Florent D - that probably is the way of
writing what I had in my head. The suggestion I took up was one of
JHoltman's which he put in an e-mail to me following his initial post but it
works well with the vectors in this question:
require(plyr)
x1.6 <- laply(1
>> I tried to be clever by trying get(paste(paste("x", 1:6, sep=""),
>> collapse="+")) but it didn't work.
Maybe you meant something like this:
sapply(paste("x", 1:6, sep=""), function(x)mean(get(x)))
On Mon, Dec 19, 2011 at 2:30 PM, David Winsemius wrote:
>
> On Dec 19, 2011, at 11:00 AM, Pab
On Dec 19, 2011, at 11:00 AM, Pablo wrote:
Suppose I have the following:
x1<-as.vector(rnorm(10))
x2<-as.vector(rnorm(10))
x3<-as.vector(rnorm(10))
x4<-as.vector(rnorm(10))
x5<-as.vector(rnorm(10))
x6<-as.vector(rnorm(10))
x7<-as.vector(rnorm(10))
x8<-as.vector(rnorm(10))
x9<-as.vector(rnorm(1
Not sure what you mean by mean of each position, so here are two
possibilities: rowMeans and colMeans:
> x1<-as.vector(rnorm(10))
> x2<-as.vector(rnorm(10))
> x3<-as.vector(rnorm(10))
> x4<-as.vector(rnorm(10))
> x5<-as.vector(rnorm(10))
> x6<-as.vector(rnorm(10))
> x7<-as.vector(rnorm(10))
> x8<-
Suppose I have the following:
x1<-as.vector(rnorm(10))
x2<-as.vector(rnorm(10))
x3<-as.vector(rnorm(10))
x4<-as.vector(rnorm(10))
x5<-as.vector(rnorm(10))
x6<-as.vector(rnorm(10))
x7<-as.vector(rnorm(10))
x8<-as.vector(rnorm(10))
x9<-as.vector(rnorm(10))
x10<-as.vector(rnorm(10))
I would like the
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