matrix, over 365
days.
hope i am clear in my statement.
eliza botto
>
>
> > From: eliza_bo...@hotmail.com
> > To: ruipbarra...@sapo.pt
> > Date: Mon, 4 Jun 2012 22:13:10 +
> > CC: r-help@r-project.org
> > Subject: Re: [R] Spliting Lists into matrices
> &
gt; To: ruipbarra...@sapo.pt
> Date: Mon, 4 Jun 2012 22:13:10 +
> CC: r-help@r-project.org
> Subject: Re: [R] Spliting Lists into matrices
>
>
>
>
>
>
> dear rui,
> lots of hugs for you.
> thnkyou very much 4 your support.
> eliza
>
> > Da
dear rui,
lots of hugs for you.
thnkyou very much 4 your support.
eliza
> Date: Mon, 4 Jun 2012 22:58:12 +0100
> From: ruipbarra...@sapo.pt
> To: eliza_bo...@hotmail.com
> CC: r-help@r-project.org
> Subject: Re: Spliting Lists into matrices
>
> Hello,
>
> Try
>
> # 'x' is your list
> xlen
Hello,
Try
# 'x' is your list
xlen <- sapply(x, length)
i1 <- which(xlen == 365)
i2 <- which(xlen == 366)
mat365 <- matrix(unlist(x[i1]), nrow=365)
mat366 <- matrix(unlist(x[i2]), nrow=366)
Hope this helps,
Rui Barradas
Em 04-06-2012 22:46, eliza botto escreveu:
i realy appreciate your con
i realy appreciate your concern..
here is a small piece of my data. if you see the first and last part data, they
contain 366 entries but the middle one has 365 entries. i want to put first and
last entries is one matrix.
list(c(0.86, 0.86, 0.86, 0.86, 0.86, 1.08, 1.08, 1.08, 1.08,
1.08, 1.08,
Hello,
I'm glad it helped.
To answer to this new question, we need to see what your data looks like.
When you say 'list' are you refering to the type of R data structure
'list'? Or to data.frames?
For us to see the best way is to use function dput. Example:
df1 <- data.frame(A=rnorm(10), B=r
Dear Rui Barradas, Mackay and all R Users,
Thankyou
very much for your reply. You helped me a lot. I got what I wanted. I just want
one more favor from you, if you could.
Suppose
I have certain number of lists of data frame, say 50. Each list has yearly data
in it. Of-course, some lists have
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