Hi:
Following the lead of others, here's a reproducible example that I
believe achieves what you want.
# Q1:
L <- lapply(1:3, function(n)
data.frame(x = rnorm(6), y = rnorm(6), g = rep(1:2, each = 3)))
# Using David's suggestion:
L1 <- lapply(L, function(d) subset(d, g == 1L))
L2 <- lapply(L
On Oct 14, 2011, at 9:26 AM, Weidong Gu wrote:
It would be nice if you could provide a sample.
That is certainly true.
However, if the data
in the list have the same colnames, you can combine them by
df<-do.call('rbind',your_list_data_frame)
Then you can do what you want on the dataframe
Comments inline:
On Fri, Oct 14, 2011 at 9:06 AM, Juliet Ndukum wrote:
> I have a list of dataframes i.e. each list element is a dataframe with three
> columns and differing number of rows. The third column takes on only two
> values. I wish to split the list into two sublists based on the valu
It would be nice if you could provide a sample. However, if the data
in the list have the same colnames, you can combine them by
df<-do.call('rbind',your_list_data_frame)
Then you can do what you want on the dataframe instead of a list
HTH
Weidong Gu
On Fri, Oct 14, 2011 at 9:06 AM, Juliet Nd
I have a list of dataframes i.e. each list element is a dataframe with three
columns and differing number of rows. The third column takes on only two
values. I wish to split the list into two sublists based on the value of the
third column of the list element.
Second issue with lists as well. I
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