0-500"
colnames(bins) <- c("bins", "count")
> bins
bins count
1 0-100 3
2 100-200 4
3 200-300 1
4 300-400 1
5 400-500 1
--Martin
-
- Original Message -
From: Kathryn B Walters-Conte
To: "r-help@r-project.org"
Cc:
Sen
- Original Message -
From: arun
To: Kathryn B Walters-Conte
Cc: R help
Sent: Monday, June 11, 2012 10:04 PM
Subject: Re: [R] Simple Binning of Values
Hi Kat,
Try this:
x1<-c(123, 48, 342, 442, 43, 232, 32, 129, 191, 147)
res<-cut(x1,breaks=seq(0,500,by=100))
library(reshap
1
4 (300,400] 1
5 (400,500] 1
I am trying to figure out how to get rid of the brackets. Otherwise, the
results looks fine.
A.K.
- Original Message -
From: Kathryn B Walters-Conte
To: "r-help@r-project.org"
Cc:
Sent: Monday, June 11, 2012 5:22 PM
Subject: [R] S
Hi Kat,
Something along the lines of the following might work:
x <- c(123, 48, 342, 442, 43, 232, 32, 129, 191, 147)
table(cut(x, c(0, 100, 200, 300, 400, 500)))
See ?cut and ?table for more details.
Best,
Jorge.-
On Mon, Jun 11, 2012 at 5:22 PM, Kathryn B Walters-Conte <> wrote:
> Hello
>
>
Hello
I am very new to R. I have an R task to complete that I have not been able to
find a straightforward answer to as of yet. I have a list of values. I would
like to count the number of values that are in one bin, the number that fall in
the next bin, etc.
For example
My input file is:
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