On Feb 4, 2014, at 11:54 AM, Francesca Pancotto wrote:
> Hello A. k.
> thanks for the suggestion.
>
> I tried this but it does not work. I probably use it in the wrong way.
> This is what it tells me,
>
>
> do.call(rbind,lapply(bank.list,function(x) x[x[,"p_made"]==406,]))
>
> Errore in mat
On 02/05/2014 06:54 AM, Francesca Pancotto wrote:
Hello A. k.
thanks for the suggestion.
I tried this but it does not work. I probably use it in the wrong way.
This is what it tells me,
do.call(rbind,lapply(bank.list,function(x) x[x[,"p_made"]==406,]))
Errore in match.names(clabs, names(xi)
Hi,
Looks like the colnames of list elements are not the same.
For e.g.
lst1 <- list(structure(list(bankname = structure(c(1L, 1L, 1L, 1L, 1L,
1L), .Label = "CIB", class = "factor"), date = structure(c(1L,
2L, 3L, 1L, 2L, 3L), .Label = c("10/02/06", "10/23/06", "11/22/06"
), class = "factor"), px
Hello A. k.
thanks for the suggestion.
I tried this but it does not work. I probably use it in the wrong way.
This is what it tells me,
do.call(rbind,lapply(bank.list,function(x) x[x[,"p_made"]==406,]))
Errore in match.names(clabs, names(xi)) :
names do not match previous names
What am I
Hi,
Try:
If `lst1` is the list:
do.call(rbind,lapply(lst1,function(x) x[x[,"p_made"]==406,]))
A.K.
On Tuesday, February 4, 2014 8:53 AM, Francesca
wrote:
Dear Contributors
sorry but the message was sent involuntary.
I am asking some advice on how to solve the following problem.
I have a list
Dear Contributors
sorry but the message was sent involuntary.
I am asking some advice on how to solve the following problem.
I have a list composed of 78 elements, each of which is a matrix of factors
and numbers, similar to the following
bank_name date px_last_CIB Q.Yp_made p_for
1
Dear Contributors
I am asking some advice on how to solve the following problem.
I have a list composed of 78 elements, each of which is a matrix of factors
and numbers, similar to the following
bank_name date px_last_CIB Q.Yp_made p_for
1 CIB 10/02/061.33 p406-q40640
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