Indeed, it seems that the author of zipfR has neither been aware
that the (scaled / aka regularized) incomplete gamma (and beta,
for that matter!) functions have been part of R all along.
...
... well , inspecting his code reveals he did know it.
But why then on earth provide all the n
RV> I would be very grateful if you could help me with:
RV> Given the regularized gamma function Reg=int_0^r
RV> (x^(k-1)e^(-x))dx/int_0^Inf (x^(k-1)e^(-x))dx ; 0 (which is eventually the ratio of the Incomplete gamma
RV> function by the gamma function),
and which is exactly what
2009 11:13 AM
To: r-help@R-project.org
Subject: [R] Regularized gamma function/ incomplete gamma function
Dear all,
I would be very grateful if you could help me with:
Given the regularized gamma function Reg=int_0^r (x^(k-1)e^(-x))dx/int_0^Inf
(x^(k-1)e^(-x))dx ; 0https://stat.ethz.ch/mailman/listinfo/r
I would be very grateful if you could help me with:
Given the regularized gamma function Reg=int_0^r (x^(k-1)e^(-x))dx/
int_0^Inf (x^(k-1)e^(-x))dx ; 0of the
Incomplete gamma function by the gamma function), does anyone know
of a package in R that would evaluate the derivative of the inverse
Dear all,
I would be very grateful if you could help me with:
Given the regularized gamma function Reg=int_0^r (x^(k-1)e^(-x))dx/int_0^Inf
(x^(k-1)e^(-x))dx ; 0https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide
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