> On Oct 9, 2017, at 6:08 PM, Georges Monette wrote:
>
> How about this (I'm showing it as a pipe because it's easier to read that
> way):
>
> library(magrittr)
> "f 147/1315/587 2820/1320/587 3624/1321/587 1852/1322/587" %>%
> strsplit(' ') %>%
> unlist %>%
> sub('^[^/]*/*','',.) %>%
>
How about this (I'm showing it as a pipe because it's easier to read
that way):
library(magrittr)
"f 147/1315/587 2820/1320/587 3624/1321/587 1852/1322/587" %>%
strsplit(' ') %>%
unlist %>%
sub('^[^/]*/*','',.) %>%
sub('^[^/]*/*','',.) %>%
paste(collapse = ' ')
Georges Monette
--
Geo
On 09/10/2017 12:06 PM, William Dunlap wrote:
"(^| +)([^/ ]*/?){0,2}", with the first "*" replaced by "+" would be a
bit better.
Thanks! I think I actually need the *, because theoretically the b part
of the word could be empty, i.e. "a//c" would be legal and should become
"c".
Duncan Murd
On 09/10/2017 11:23 AM, Ulrik Stervbo wrote:
Hi Duncan,
why not split on / and take the correct elements? It is not as elegant
as regex but could do the trick.
Thanks for the suggestion. There are likely many thousands of lines of
data like the two real examples (which had about 5000 and 60
"(^| +)([^/ ]*/?){0,2}", with the first "*" replaced by "+" would be a bit
better.
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Mon, Oct 9, 2017 at 8:50 AM, William Dunlap wrote:
> > x <- "f 147/1315/587 2820/1320/587 3624/1321/587 1852/1322/587"
> > gsub("(^| *)([^/ ]*/?){0,2}", "\\1", x)
>
> x <- "f 147/1315/587 2820/1320/587 3624/1321/587 1852/1322/587"
> gsub("(^| *)([^/ ]*/?){0,2}", "\\1", x)
[1] " 587 587 587 587"
> y <- "aa aa/ aa/bb aa/bb/ aa/bb/cc aa/bb/cc/ aa/bb/cc/dd aa/bb/cc/dd/"
> gsub("(^| *)([^/ ]*/?){0,2}", "\\1", y)
[1] "cc cc/ cc/dd cc/dd/"
Bill Dunlap
TIBCO Sof
> On 9 Oct 2017, at 17:02 , Duncan Murdoch wrote:
>
> I have a file containing "words" like
>
>
> a
>
> a/b
>
> a/b/c
>
> where there may be multiple words on a line (separated by spaces). The a, b,
> and c strings can contain non-space, non-slash characters. I'd like to use
> gsub() to
Hi Duncan,
You can try this:
library(readr)
f <- function(s) {
t <- unlist(readr::tokenize(paste0(gsub(" ",",",s),"\n",collapse="")))
i <- grep("[a-zA-Z0-9]*/[a-zA-Z0-9]*/",t)
u <- sub("[a-zA-Z0-9]*/[a-zA-Z0-9]*/","",t[i])
paste0(u,collapse=" ")
}
f("f 147/1315/587 2820/1320/587 3624/1321
Hi Duncan,
why not split on / and take the correct elements? It is not as elegant as
regex but could do the trick.
Best,
Ulrik
On Mon, 9 Oct 2017 at 17:03 Duncan Murdoch wrote:
> I have a file containing "words" like
>
>
> a
>
> a/b
>
> a/b/c
>
> where there may be multiple words on a line (se
I have a file containing "words" like
a
a/b
a/b/c
where there may be multiple words on a line (separated by spaces). The
a, b, and c strings can contain non-space, non-slash characters. I'd
like to use gsub() to extract the c strings (which should be empty if
there are none).
A real exa
Dear Enrico,
Many thanks and Best Regards,
Ashim.
On Thu, Jun 8, 2017 at 5:11 PM, Enrico Schumann
wrote:
>
> Zitat von Ashim Kapoor :
>
>
> Dear All,
>>
>> My query is:
>>
>> Do we always need to use perl = TRUE option when doing ignore.case=TRUE?
>>
>> A small example :
>>
>> my_text =
>> "RE
Zitat von Ashim Kapoor :
Dear All,
My query is:
Do we always need to use perl = TRUE option when doing ignore.case=TRUE?
A small example :
my_text =
"RECOVERY OFFICER-II\nDEBTS RECOVERY TRIBUNAL-III\n RC No. 162/2015\nSBI
VS RAMESH GUPTA.\nDated: 01.03.2016 Item no.01
Dear All,
My query is:
Do we always need to use perl = TRUE option when doing ignore.case=TRUE?
A small example :
my_text =
"RECOVERY OFFICER-II\nDEBTS RECOVERY TRIBUNAL-III\n RC No. 162/2015\nSBI
VS RAMESH GUPTA.\nDated: 01.03.2016 Item no.01\n
Present: Ms. Sonakshi, t
, 29 Jun 2014 13:16:26 -0700
> Subject: Re: [R] regular expression help
> To: bac...@hotmail.com
> CC: dwinsem...@comcast.net; r-help@r-project.org
>
>> what's the difference between [:space:]+ and[[:space:]]+ ?
>
> The pattern '[:space:]' matches any of
ace:]+ instead
> of [[:space:]]+
> what's the difference between [:space:]+ and[[:space:]]+ ?
>
> Thanks so much!
> Lin
>
>
>> From: wdun...@tibco.com
>> Date: Fri, 27 Jun 2014 02:35:54 -0700
>> Subje
ring you
> are testing
> so try this
>
> grep('[/]*\\[/]*',test)
>
> Duncan
>
> Duncan Mackay
> Department of Agronomy and Soil Science
> University of New England
> Armidale NSW 2351
> Email: home: mac...@northnet.com.au
>
> -Original Message
!
Lin
> From: wdun...@tibco.com
> Date: Fri, 27 Jun 2014 02:35:54 -0700
> Subject: Re: [R] regular expression help
> To: dwinsem...@comcast.net
> CC: bac...@hotmail.com; r-help@r-project.org
>
> You can use parentheses to factor out the common string in David's
>
ry this
>>>
>>> grep('[/]*\\[/]*',test)
>>>
>>> Duncan
>>>
>>> Duncan Mackay
>>> Department of Agronomy and Soil Science
>>> University of New England
>>> Armidale NSW 2351
>>> Email: home: mac...@northnet.com.a
D1$|^AARSD1', test)
> grepl('^AARSD1//$|^AARSD1 //$|^//AARSD1$|^AARSD1$', test)
[1] FALSE FALSE TRUE TRUE TRUE TRUE
--
David.
>
> Thanks,
> Lin
>
>
>> From: dulca...@bigpond.com
>> To: bac...@hotmail.co
7;//AARSD1','AARSD1');
I want to match only 'AARSD1//','AARSD1 //','//AARSD1','AARSD1'
Thanks,
Lin
----------------
> From: dulca...@bigpond.com
> To: bac...@hotmail.com; r-help@r-project.org
> Subject: RE: [R] r
al Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of C Lin
Sent: Friday, 27 June 2014 10:05
To: r-help@r-project.org
Subject: [R] regular expression help
Dear R users,
I need to match a string. It can be followed or preceded by whitespace or //
or no
Dear R users,
I need to match a string. It can be followed or preceded by whitespace or // or
nothing.
How do I code it in R?
For example:
test <- c('AARSD11','AARSD1-','AARSD1//','AARSD1 //','//AARSD1');
grep('AARSD1(\\s*//*)',test);
should return 3,4,5 and 6.
Thanks in advance for your help.
Thank you guys, both solutions work great! Seems I have two new
packages to investigate :)
Regards,
Tony Breyal
On 31 Mar, 14:20, Tony B wrote:
> Dear all,
>
> Lets say I have the following:
>
> > x <- c("Eve: Going to try something new today...", "Adam: Hey @Eve, how are
> > you finding R? #rs
On Wed, Mar 31, 2010 at 8:20 AM, Tony B wrote:
> Dear all,
>
> Lets say I have the following:
>
>> x <- c("Eve: Going to try something new today...", "Adam: Hey @Eve, how are
>> you finding R? #rstats", "Eve: @Adam, It's awesome, so much better at
>> statistics that #Excel ever was! @Cain & @Abl
strapply in gsubfn can extract matches based on content which seems to
be what you want:
library(gsubfn)
f <- function(...) sapply(list(...), paste, collapse = ", ")
DF <- data.frame(x,
Source = strapply(x, "^(\\w+):", c, simplify = f),
Mentions = strapply(x, "@(\\w+)", c, simpli
Dear all,
Lets say I have the following:
> x <- c("Eve: Going to try something new today...", "Adam: Hey @Eve, how are
> you finding R? #rstats", "Eve: @Adam, It's awesome, so much better at
> statistics that #Excel ever was! @Cain & @Able disagree though :(", "Adam:
> @Eve I'm sure they'll so
If I understand correctly you wish to extract strings of digits more
than 5 characters long:
s <- c("UV7C11-F9-E1 MCS#9831019", "MCS Lot #9512516")
library(gsubfn)
strapply(s, "\\d{6,}", c)
Depending on what you want to get back you might wish to add the
simplify=TRUE argument to strapply, as wel
Ramya -
Try
strings = c('UV7C11-F9-E1 MCS#9831019','MCS Lot #9512516')
sub('^.*?(\\d{5,}).*?$','\\1',strings,perl=TRUE)
[1] "9831019" "9512516"
The regular expression finds the first string of five or
more numbers in the strings. Since you said the numbers could
occur anywhere in the stri
On Dec 7, 2009, at 5:04 PM, Ramya wrote:
Hi there
I have a string like this i want to extract 9831019 from this string
i used
a regular expresion \d+ by which i can only make it to see 7 and
returns.
This type of number(9831019) appears in any part of the string and is
definitely more t
Hi there
I have a string like this i want to extract 9831019 from this string i used
a regular expresion \d+ by which i can only make it to see 7 and returns.
This type of number(9831019) appears in any part of the string and is
definitely more than 5 digits all the time and i want to give that
30 matches
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