Re: [R] Regex and gsub

2010-05-11 Thread arnaud Gaboury
TY for the two answers. Both work. > -Original Message- > From: Phil Spector [mailto:spec...@stat.berkeley.edu] > Sent: Tuesday, May 11, 2010 11:21 AM > To: arnaud Gaboury > Cc: r-help@r-project.org > Subject: Re: [R] Regex and gsub > > df3$DESCRIPTION = >

Re: [R] Regex and gsub

2010-05-11 Thread Phil Spector
df3$DESCRIPTION = sub(' [a-z]{3}/[0-9]{2}','',df3$DESCRIPTION,ignore.case=TRUE) - Phil Spector Statistical Computing Facility Department of Statistics

Re: [R] Regex and gsub

2010-05-11 Thread Bernd Weiss
Am 11.05.2010 10:37, schrieb arnaud Gaboury: > Dear group, > > Here is my df : > > df3 <- > structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10", > "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", > "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/1

[R] Regex and gsub

2010-05-11 Thread arnaud Gaboury
Dear group, Here is my df : df3 <- structure(list(DESCRIPTION = c("COPPER May/10", "COTTON NO.2 Jul/10", "CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10", "WHEAT Jul/10", "SPCL HIGH GRADE ZINC USD", "STANDARD LE