imitri
>
>
> On Mon, Apr 13, 2009 at 6:22 PM, Liaw, Andy
> wrote:
> > Apologies: that should have been sum(residual^2)!
> >
> >> -Original Message-
> >> From: Dimitri Liakhovitski [mailto:ld7...@gmail.com]
> >> Sent: Monday, April 13, 2009 4
es: that should have been sum(residual^2)!
>
>> -Original Message-
>> From: Dimitri Liakhovitski [mailto:ld7...@gmail.com]
>> Sent: Monday, April 13, 2009 4:35 PM
>> To: Liaw, Andy
>> Cc: R-Help List
>> Subject: Re: [R] Random Forests: Question about
Apologies: that should have been sum(residual^2)!
> -Original Message-
> From: Dimitri Liakhovitski [mailto:ld7...@gmail.com]
> Sent: Monday, April 13, 2009 4:35 PM
> To: Liaw, Andy
> Cc: R-Help List
> Subject: Re: [R] Random Forests: Question about R^2
>
> And
Andy,
thank you very much!
One clarification question:
If MSE = sum(residuals) / n, then
in the formula (1 - mse / Var(y)) - shouldn't one square mse before
dividing by variance?
Dimitri
On Mon, Apr 13, 2009 at 10:52 AM, Liaw, Andy wrote:
> MSE is the mean squared residuals. For the training
MSE is the mean squared residuals. For the training data, the OOB
estimate is used (i.e., residual = data - OOB prediction, MSE =
sum(residuals) / n, OOB prediction is the mean of predictions from all
trees for which the case is OOB). It is _not_ the average OOB MSE of
trees in the forest.
I hop
Dear Random Forests gurus,
I have a question about R^2 provided by randomForest (for regression).
I don't succeed in finding this information.
In the help file for randomForest under "Value" it says:
rsq: (regression only) - "pseudo R-squared'': 1 - mse / Var(y).
Could someone please explain in
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