В Wed, 8 Nov 2023 16:03:15 +0530
Crown Flame пишет:
> for(i in 1:8)
> {
> LST_city <- extract(LST, c(lon[i],lat[i]), fun = mean, buffer =
> 1, na.rm = TRUE) #error
> }
Three things you might need to change:
1. You are trying to assign the output of extract() to the same
variable LST_cit
Good afternoon,
I have been working on my thesis project on the topic "Urban Heat Island
Pattern in India". To achieve the results I am applying a* two-dimensional
Gaussian fit* on an LST raster of 1 km spatial resolution but I am facing
two errors in the following code.
library(raster)
LST <- ras
Hi thanoon,
Well, you have generated a one column matrix of missing values (NA) and
then tried to use those values in a logical test...
Jim
On Wed, Nov 4, 2015 at 8:02 PM, thanoon younis
wrote:
> Dear R-Users
>
> After correct some errors in the code below i have only this error
>
> "Error in i
Dear R-Users
After correct some errors in the code below i have only this error
"Error in if (BZ[i] < 0.25) { : missing value where TRUE/FALSE needed"
how can i solve this problem please?
N<-200;P<-9 #Sample size
BZ=matrix(NA, nrow=N, ncol=1)
W=matrix(NA, nrow=N, ncol=
Hi thanoon,
The problem may lie in your definition of BZ (which I see Boris has also
noticed). Given your code, it will be a vector containing 200 zeros. Your
code will generate 200 ones as zero is less than 0.25. Try defining BZ as
follows:
BZ<-runif(200)
You should get something more interestin
Whatever -
just type:
W <- floor(BZ * 4) + 1
B.
On Nov 3, 2015, at 11:09 PM, Boris Steipe wrote:
> Are you telling me it contains only zeros? Or is it a vector of length zero?
>
> B.
>
>
> On Nov 3, 2015, at 11:07 PM, thanoon younis
> wrote:
>
>> BZ is hidden variable with zero values.
Are you telling me it contains only zeros? Or is it a vector of length zero?
B.
On Nov 3, 2015, at 11:07 PM, thanoon younis wrote:
> BZ is hidden variable with zero values.
>
> On 4 November 2015 at 07:02, Boris Steipe wrote:
> Your approach does not make sense.
>
> If you initialize a vect
Your approach does not make sense.
If you initialize a vector as say ...
BZ <- numeric(5)
... what do you _expect BZ contains?
Also: if you run a loop like you do
for (j in 1:1) {
print(j)
}
... what do you _expect_ will happen?
B.
On Nov 3, 2015, at 10:43 PM, thanoon younis wrote:
>
Thank you for your response
I have a vector of unknown values BZ which is defined already BZ=numeric(N)
and i want to transfer BZ to ordered categorical variable with 4
categories W but when i write this code
for(j in 1:1){
if(BZ[j] < 0.25){
W[j] = 1
}else if(BZ[j] >=0.25 &
Sorry, not round. floor()
B.
On Nov 3, 2015, at 10:35 PM, Boris Steipe wrote:
> Why don't you just multiply by four, round, and add one?
>
>
>
> B.
> On Nov 3, 2015, at 10:02 PM, thanoon younis
> wrote:
>
>> Dear R-users
>>
>> I have a problem in the code below, the problem is because i
Why don't you just multiply by four, round, and add one?
B.
On Nov 3, 2015, at 10:02 PM, thanoon younis wrote:
> Dear R-users
>
> I have a problem in the code below, the problem is because i want to change
> the variable BZ which is a vector with 200x1 dimension to the var. W which
> is categ
Dear R-users
I have a problem in the code below, the problem is because i want to change
the variable BZ which is a vector with 200x1 dimension to the var. W which
is categorical variable with same dimension of BZ but with categorical
values with 4 categories but i got on only zero values in w why
Wrong list. This is an R list not Bugs.
You may want to consult Bugs materials:
http://www2.mrc-bsu.cam.ac.uk/bugs/weblinks/webresource.shtml
On 8 May 2014 11:36, thanoon younis wrote:
> dear all members
>
> is there anyone explain to me the code below and how can i transfer this
> code to winbug
dear all members
is there anyone explain to me the code below and how can i transfer this
code to winbugs program.
q[i,1]=qnorm(runif(1,min=.5,max=1),0,1)
thanks in advance
thanoon
[[alternative HTML version deleted]]
__
R-help@r-project.org
14 matches
Mail list logo
