Hello,
It seems to be right.
You have Chi-squared = 23.724, df = 8, p-value = 0.002549. So try the R
function ?pchisq:
pchisq(23.724, df = 8, lower = FALSE)
[1] 0.002549054
Hope this helps,
Rui Barradas
Em 23-05-2017 13:08, Dhivya Narayanasamy escreveu:
Hi,
I am working with bivariate tim
Hi,
I am working with bivariate time series data. I used VAR model to fit and
forecast.
But the "*p*" value from seria.test (Portmanteau Test) gives values *p<<
0.05*. Is that okay?
> var1 = VAR(datax.ts, p= 8)
> serial.test(var1, lags.pt=10, type = "PT.asymptotic")
Portmanteau Test (asymptotic
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