Thank you very much, Dr. Ripley. The solution "ifelse()" you provided
is exactly what I want. I am so happy this morning for that I recieved
your email. Yesterday night I was trying to write a loop to substitute
NA. But now I learn that "ifelse()" does a much more efficient work.
Really appreciate
On Wed, 16 Apr 2008, Lu, Jiang wrote:
> Dear R helpers,
>
> I was doing a genetic project with two datasets X and Y. There are
> some IDs in both data sets, and others in either data set. I used
> "merge(x,y,by="ID",all=TRUE)". The data set Y contains a variable (a
> genotype) which is also in dat
Dear R helpers,
I was doing a genetic project with two datasets X and Y. There are
some IDs in both data sets, and others in either data set. I used
"merge(x,y,by="ID",all=TRUE)". The data set Y contains a variable (a
genotype) which is also in data X. When I merge X with Y, these two
variables we
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