> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Alisa Wade
> Sent: Wednesday, October 13, 2010 2:11 PM
> To: r-help@r-project.org
> Subject: [R] Matrix subscripting to wrap around from end to start of
> row
>
>
Hi:
This isn't particularly elegant, but I think it works:
# The function to be applied:
f <- function(x, idx) {
n <- length(x)
if(idx[1] < idx[2]) {idx <- seq(idx[1], idx[2])
} else { idx <- c(seq(idx[1], n), seq(1, idx[2])) }
mean(x[idx])
}
# tests
> month.data = matrix(c(3,
On Oct 13, 2010, at 4:54 PM, Alisa Wade wrote:
Thanks, David for the response.
Unfortunately, that only works for the case where I happen to only
want the last and first month "wrap".
But it doesn't work for any other case, e.g., say I want months
start.month = 4, end.month = 2.
Now
woul
Thanks, David for the response.
Unfortunately, that only works for the case where I happen to only want the
last and first month "wrap".
But it doesn't work for any other case, e.g., say I want months start.month
= 4, end.month = 2.
Now
start=4; end=2; year.avg = apply(month.data[, c(start,end)],
On Oct 13, 2010, at 4:10 PM, Alisa Wade wrote:
Perhaps it is just that I don't even know the correct term to search
for,
but I can find nothing that explains how to wrap around from the end
to a
start of a row in a matrix.
For example, you have a matrix of 2 years of data, where rows are
Perhaps it is just that I don't even know the correct term to search for,
but I can find nothing that explains how to wrap around from the end to a
start of a row in a matrix.
For example, you have a matrix of 2 years of data, where rows are years, and
columns are months.
month.data = matrix(c(3,4
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