Just use vect_2_id as a subsetting index for vect_1, ie:
vect_2<-vect_1[vect_2_id]
Vincy Pyne wrote:
>
> Dear R helpers
>
> Suppose I have a vector as
>
> vect_1 = c("AAA", "AA", "A", "BBB", "BB", "B", "CCC")
>
> vect_1_id = c(1:length(vect_1))
>
> Through some process I obtain
>
> vect_2_
vect_1[vect_2_id]
and perhaps a readthrough of some of the very nice
intro to R materials available online.
Sarah
On Tue, Mar 15, 2011 at 3:41 PM, Vincy Pyne wrote:
> Dear R helpers
>
> Suppose I have a vector as
>
> vect_1 = c("AAA", "AA", "A", "BBB", "BB", "B", "CCC")
>
> vect_1_id = c(1:leng
Dear R helpers
Suppose I have a vector as
vect_1 = c("AAA", "AA", "A", "BBB", "BB", "B", "CCC")
vect_1_id = c(1:length(vect_1))
Through some process I obtain
vect_2_id = c(2, 3, 7), then I need a new vector say vect_2 which will give me
vect2 = ("AA", "A", "CCC") i.e. I need the subset of ve
3 matches
Mail list logo