> 2. The answer will be wrong. The reason is that the censoring occurs on a
> time scale, not a $ scale: you don't stop observing someone because
> total cost hits a threshold, but because calendar time does. The KM routines
> assume that the censoring process and the event process are on the
> 2. The answer will be wrong. The reason is that the censoring occurs on a
> time scale, not a $ scale: you don't stop observing someone because
> total cost hits a threshold, but because calendar time does. The KM routines
> assume that the censoring process and the event process are on the
--- begin included message --
I have some data which is censored and I want to determine the median.
Its actually cost data for a cohort of patients, many of whom are still
on treatment and so are censored.
I can do the same sort of analysis for a survival curve and get the
median survival... ...b
DURHAM AND DARLINGTON NHS FOUNDATION TRUST)
Sent: Monday, October 31, 2011 1:29 PM
To: r-help@r-project.org
Subject: [R] Kaplan Meier - not for dates
I have some data which is censored and I want to determine the median. Its
actually cost data for a cohort of patients, many of whom are still on
do:
myFit = survfit(mySurv~my_data$severity)
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Polwart Calum (COUNTY DURHAM AND DARLINGTON NHS FOUNDATION TRUST)
Sent: Monday, October 31, 2011 1:29 PM
To: r-help@r-project.org
Subje
I have some data which is censored and I want to determine the median. Its
actually cost data for a cohort of patients, many of whom are still on
treatment and so are censored.
I can do the same sort of analysis for a survival curve and get the median
survival... ...but can I just use the surv
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