Thank you!! Using lm.fit did the trick.
2012/2/23 R. Michael Weylandt
> It looks like what you are doing is reasonably efficient: I do think
> there's a residuals element to the object returned by lm() so you
> could just call that directly (which will be just a little more
> efficient).
>
> The
It looks like what you are doing is reasonably efficient: I do think
there's a residuals element to the object returned by lm() so you
could just call that directly (which will be just a little more
efficient).
The bulk of the time is probably being taken up in the lm() call,
which has alot of ove
Hello,
I'm very new to R so my apologies if I'm making an obvious mistake.
I have a data frame with ~170k rows and 14 numeric variables. The first 2
of those variables (let's call them group1 and group2) are used to define
groups: each unique pair of (group1,group2) is a group. There are roughly
5
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