On 09/07/2021 3:37 p.m., Laurent Rhelp wrote:
Very effective solution, I hope I remember that for the nex time.
The key things to remember are that in R a "list" object is a vector
whose elements are R objects, and that matrices are just vectors with
dimension attributes.
Those two ideas a
Very effective solution, I hope I remember that for the nex time.
Thank you
Le 09/07/2021 à 19:50, David Winsemius a écrit :
On 7/9/21 10:40 AM, Laurent Rhelp wrote:
Dear R-Help-list,
I have a list init_l containing 16 dataframes and I want to create
a matrix 4 x 4 from this list with a
You are right, this extra level disturbed me.
Very impressive this solution, thank you very much.
Le 09/07/2021 à 19:50, Bill Dunlap a écrit :
> Try
> matrix(init_l, nrow=4, ncol=4,
> dimnames=list(c("X1","X2","X3","X4"),c("X1","X2","X3","X4")))
> It doesn't give exactly what your code does
On 7/9/21 10:40 AM, Laurent Rhelp wrote:
Dear R-Help-list,
I have a list init_l containing 16 dataframes and I want to create a
matrix 4 x 4 from this list with a dataframe in every cell of the
matrix. I succeeded to do that but my loop is very uggly (cf. below).
Could somebody help me to
Try
matrix(init_l, nrow=4, ncol=4,
dimnames=list(c("X1","X2","X3","X4"),c("X1","X2","X3","X4")))
It doesn't give exactly what your code does, but your code introduces an
extra level of "list", which you may not want.
-Bill
On Fri, Jul 9, 2021 at 10:40 AM Laurent Rhelp wrote:
> Dear R-Help-li
Dear R-Help-list,
I have a list init_l containing 16 dataframes and I want to create a
matrix 4 x 4 from this list with a dataframe in every cell of the
matrix. I succeeded to do that but my loop is very uggly (cf. below).
Could somebody help me to write nice R code to do this loop ?
Thank
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