Try this:
mapply('[', lapply(mylist, as.data.frame), c(index, lapply(index,
`!`)), SIMPLIFY = FALSE)
On Tue, Apr 5, 2011 at 7:46 AM, Lars Bishop wrote:
> Dear R users,
>
> Let's say I have a list with components being 'm' matrices (as exemplified
> in the "mylist" object below). Now, I'd like t
Dear R users,
Let's say I have a list with components being 'm' matrices (as exemplified
in the "mylist" object below). Now, I'd like to subset this list based on an
index vector, which will partition each matrix 'm' in 2 sub-matrices. My
questions are:
1. Is there an elegant way to have the resu
2 matches
Mail list logo