On 25 Feb 2016, at 22:43 , Ben Tupper wrote:
> Hi,
>
> Using your example (note I called the list 'z')...
>
> z <-list(a = seq(1:5), b = seq(10:20))
>
> I picture lapply as extracting each element of z like this z[[i]] - the `[[`
> extracts the ith value from the context of residing in a lis
Hi,
Using your example (note I called the list 'z')...
z <-list(a = seq(1:5), b = seq(10:20))
I picture lapply as extracting each element of z like this z[[i]] - the `[[`
extracts the ith value from the context of residing in a list - hence it's name
is 'lost' in the new context. That's diffe
Why don't you simply use names(c) to get the names of all objects? If, for
your purposes, you still want the "names" function inside lapply, you can
use the following:
unlist(lapply(1:length(c), function(x) names(c[x])))
This will produce exactly same output as names(c) would. When you use
lapply(c
On 26/02/16 11:37, Huzefa Khalil wrote:
If you want the object names, you should use lapply over the names:
lapply(names(c), function(x) {c[[x]]})
This makes no sense at all to me; you get the same result simply by
typing "c".
If the OP's message is interpreted literally, all he needs to do
If you want the object names, you should use lapply over the names:
lapply(names(c), function(x) {c[[x]]})
On Thu, Feb 25, 2016 at 5:25 PM, Uwe Ligges wrote:
>
>
> On 25.02.2016 22:27, Mohammad Tanvir Ahamed via R-help wrote:
>
>> Hello,
>>
>> I want to get object name of a list inside lapply
>
On 25.02.2016 22:27, Mohammad Tanvir Ahamed via R-help wrote:
Hello,
I want to get object name of a list inside lapply
c<-list(a=seq(1:5),b=seq(10:20))
lapply(c,names)
$a
NULL
$b
NULL
Why NULL ?
Why should it? seq(1:5) has no names, nor has seq(10:20).
Best,
Uwe Ligges
but i am
Posting in HTML makes it much harder for people to figure out your code.
Maybe this will help:
> c<-list(a=seq(1:5),b=seq(10:20))
> c[[1]]
[1] 1 2 3 4 5
> c[[2]]
[1] 1 2 3 4 5 6 7 8 9 10 11
> names(c[[1]])
NULL
> names(c[[2]])
NULL
On Thu, Feb 25, 2016 at 4:15 PM, Mohammad Tanvir Aha
Hello,
I want to get object name of a list inside lapply
> c<-list(a=seq(1:5),b=seq(10:20))
> lapply(c,names)
$a
NULL
$b
NULL
Why NULL ?
but i am expecting the names of object . Any help will be appreciated .
I want to grab the names of object inside lapply for further process.
Th
Hello,
I want to get object name of a list inside lapply
> c<-list(a=seq(1:5),b=seq(10:20))> lapply(c,names)$aNULL
$bNULL
Why NULL ?
but i am expecting the names of object . Any help will be appreciated .
I want to grab the names of object inside lapply for further process.
Thanks .
Tanvir A
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