(apply(cbind(v1,v2),1,function(x) x[order(x)]
#found to be faster
# user system elapsed
# 2.693 0.072 2.857
identical(res1,res3)
#[1] TRUE
A.K.
- Original Message -
From: Emmanuel Levy
To: R-help Mailing List
Cc:
Sent: Thursday, December 27, 2012 3:30 PM
Subject: [
Yep. There are methods for:
> methods(unique)
[1] unique.array unique.data.frame unique.default
[4] unique.matrix unique.numeric_version unique.POSIXlt
and for the matrix and data.frame methods, unique rows will be returned by
default. For array and matrix obje
I did not know that unique worked on entire rows!
That is great, thank you very much!
Emmanuel
On 27 December 2012 22:39, Marc Schwartz wrote:
> unique(t(apply(cbind(v1, v2), 1, sort)))
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On Dec 27, 2012, at 2:30 PM, Emmanuel Levy wrote:
> Hi,
>
> I've had this problem for a while and tackled it is a quite dirty way
> so I'm wondering is a better solution exists:
>
> If we have two vectors:
>
> v1 = c(0,1,2,3,4)
> v2 = c(5,3,2,1,0)
>
> How to remove one instance of the "3,1"
Hi,
I've had this problem for a while and tackled it is a quite dirty way
so I'm wondering is a better solution exists:
If we have two vectors:
v1 = c(0,1,2,3,4)
v2 = c(5,3,2,1,0)
How to remove one instance of the "3,1" / "1,3" double?
At the moment I'm using the following solution, which is q
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