quot;a" "A" "f"
> [9,] "b" "B" "f"
> [10,] "c" "B" "f"
> [11,] "d" "B" "f"
> [12,] "a" "C" "f"
> [13,] "d" "C&q
t;
[6,] "c" "C" "e"
[7,] "b" "D" "e"
[8,] "a" "A" "f"
[9,] "b" "B" "f"
[10,] "c" "B" "f"
[11,] "d" "B" "f&qu
Hi Dennis,
Thanks for your answer, it works very well - clever way to sort the problem!
Cheers,
Pierre
2011/5/16 Dennis Murphy :
> Hi:
>
> Does it have to be an array? If all you're interested in is the
> dimnames, how about this?
>
> library(plyr)
> foo <- array(data = rnorm(32), dim = c(4,4,
Hi:
Does it have to be an array? If all you're interested in is the
dimnames, how about this?
library(plyr)
foo <- array(data = rnorm(32), dim = c(4,4,2),
dimnames=list(letters[1:4], LETTERS[1:4], letters[5:6]))
> foo
, , e
A B C D
a -0.2
Hi list,
In a function I am writing, I need to extract the dimension names of
an array. I know this can be acheived easily using dimnames() but my
problem is that I want my function to be robust when the number of
dimensions varies. Consider the following case:
foo <- array(data = rnorm(32), dim
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