Thanks all for the reply. I think I need to think of other ways to approach
the problem.
Hanna
2016-01-24 17:45 GMT-05:00 William Dunlap :
> > 28 PiB. Storing such a large matrix even on file is not possible.
>
> The ads for Amazon Red Shift say it is possible. E.g.,
> Amazon Redshift is
> 28 PiB. Storing such a large matrix even on file is not possible.
The ads for Amazon Red Shift say it is possible. E.g.,
Amazon Redshift is a fast, fully managed, petabyte-scale data
warehouse that makes it simple and cost-effective to analyze
all your data using your existing business i
FYI, the matrix you tried to allocate would hold
(3195*1290*495*35*35*35*15) * 3 = 3.936248e+15 values. Each value
would occupy 8 bytes of memory (for the double data type). In other
words, in order to keep this data matrix in memory you would require a
computer with at least 3.148998e+16 bytes o
Hey Hanna,
nrow and ncol in matrix() are integer-based, for the moment at least;
accordingly they have a maximum value. (3195*1290*495*35*35*35*15) is
actually larger than an integer can hold - you can test this with:
str((3195*1290*495*35*35*35*15))
Which shows that it's stored as a numeric val
Hi all,
I am doing some calculation with very large dimension. I need to create a
matrix
with three columns and a very large number of rows
(3195*1290*495*35*35*35*15=1.312083e+15) i
n order to allocate calculation result from a for loop.
R does not allow me to create such a matrix because of the
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