= 0.0438 and SD_2 = 0.0285, and
then the 95% CI for the difference?
Thanks
John
From: Thomas Lumley
To: Jason Connor
Cc: r-help@r-project.org
Sent: Wednesday, March 7, 2012 10:58 AM
Subject: Re: [R] Difference in Kaplan-Meier estimates plus CI
On Thu, Mar 8
On Fri, Mar 9, 2012 at 3:08 AM, Terry Therneau wrote:
> A note on standard errors: S(t) +- std is a terrible confidence
> interval. You will be much more accurate if you use log scale. (Some
> argue for logit or log-log, in truth they work well.) If n is large
> enough, however, you should b
--begin included message --
I thought this would be trivial, but I can't find a package or function
that does this.
I'm hoping someone can guide me to one.
Imagine a simple case with two survival curves (e.g. treatment &
control).
I just want to calculate the difference in KM estimates at a spec
Did you try the survival package?
On Wed, 07-Mar-2012 at 10:50AM -0500, Jason Connor wrote:
|> I thought this would be trivial, but I can't find a package or function
|> that does this.
|>
|> I'm hoping someone can guide me to one.
|>
|> Imagine a simple case with two survival curves (e.g. tr
On Thu, Mar 8, 2012 at 4:50 AM, Jason Connor wrote:
> I thought this would be trivial, but I can't find a package or function
> that does this.
>
> I'm hoping someone can guide me to one.
>
> Imagine a simple case with two survival curves (e.g. treatment & control).
>
> I just want to calculate th
I thought this would be trivial, but I can't find a package or function
that does this.
I'm hoping someone can guide me to one.
Imagine a simple case with two survival curves (e.g. treatment & control).
I just want to calculate the difference in KM estimates at a specific time
point (e.g. 1 year
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