Consider using sapply instead of a for loop, if the code in the sapply
call returns a vector, and every vector is the same length, then
sapply will automatically form it into a matrix for you.
On Sun, Feb 12, 2012 at 12:30 PM, jolo999 wrote:
> It seems to work. Simple and effective!
>
> Thanks!
>
It seems to work. Simple and effective!
Thanks!
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Hi,
You can initialize a counter and update it in the loop. An silly example
(unrelated to yours because it was not reproducible) of this technique is:
x <- matrix( , ncol = 2, nrow = 26)
n <- 0
for(i in letters) {
n <- n+1
x[n,] <- c(i, n)
}
Best,
Ista
On Sunday, February 12, 2012 07:
Dear all,
i have daily stock prices for more than 10 years and want to compute annual
volatilities for certain dates during this period. Since i have found no
"easy" way to work with time data, the data presents itself in the structure
TIme Index - Stock Price
1 - 15,6
2 - 17
...
...
2010 - 28
2
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