Let's be a bit careful.
You'll probably need a regular expression. But maybe a regex can't work in
principle, so one can't just gloss over the details.
You said: "blah blah blah" can contain ANY text. If this is true, "blah blah
blah" could contain the delimiters. If that is the case, a regex i
What's the expected output for this sample?
How do _you_ define what should be counted?
> On Apr 26, 2017, at 8:33 AM, Dan Abner wrote:
>
> Hi all,
>
> I was not clearly enough in my example code. Please see below where "blah
> blah blah" can be ANY text or numbers: No predictable pattern
Hi all,
I was not clearly enough in my example code. Please see below where "blah
blah blah" can be ANY text or numbers: No predictable pattern at all to
what may or may not be written in place of "blah blah blah".
text1<-c("blah blah blah.
blah blah blah
1) blah blah blah 1
2) blah blah blah
10)
Thanks, Ista. I thought there might be a "tidy" way to do this, but I
hadn't use stringr.
-- Mike
On Tue, Apr 25, 2017 at 8:47 PM, Ista Zahn wrote:
> stringr::str_count (and stringi::stri_count that it wraps) interpret
> the pattern argument as a regular expression by default.
>
> Best,
> Ista
stringr::str_count (and stringi::stri_count that it wraps) interpret
the pattern argument as a regular expression by default.
Best,
Ista
On Tue, Apr 25, 2017 at 11:40 PM, Michael Hannon
wrote:
> I like Boris's "Hadley" solution. For the record, I've appended a
> version that uses regular expres
I like Boris's "Hadley" solution. For the record, I've appended a
version that uses regular expressions, the only benefit of which is
that it could be generalized to find more-complicated patterns.
-- Mike
counts <- sapply(text1, function(next_string) {
loc_example <- length(gregexpr("Exampl
I should add: there's a str_count() function in the stringr package.
library(stringr)
str_count(text1, "Example")
# [1] 5 5 5 5
I guess that would be the neater solution.
B.
> On Apr 25, 2017, at 8:23 PM, Boris Steipe wrote:
>
> How about:
>
> unlist(lapply(strsplit(text1, "Example"), func
How about:
unlist(lapply(strsplit(text1, "Example"), function(x) { length(x) - 1 } ))
Splitting your string on the five "Examples" in each gives six elements.
length(x) - 1 is the number of
matches. You can use any regex instead of "example" if you need to tweak what
you are looking for.
B.
Hi all,
I am looking for a streamlined way of counting the number of enumerated
items are each element of a character vector. For example:
text1<-c("This is an example.
List 1
1) Example 1
2) Example 2
10) Example 10
List 2
1) Example 1
2) Example 2
These have been examples.","This is another ex
9 matches
Mail list logo
