Ah, that's exactly what I'm looking for. Thanks a lot.
On Sat, Jul 11, 2009 at 11:23 AM, jim holtman wrote:
> ?combn
>
>> combn(10,2)
> [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12]
> [,13] [,14] [,15] [,16] [,17]
> [1,] 1 1 1 1 1 1 1 1 1 2
?combn
> combn(10,2)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12]
[,13] [,14] [,15] [,16] [,17]
[1,]111111111 2 2 2
2 2 2 2 2
[2,]23456789 10 3 4 5
6 7 8
Hello my R buddies,
I'm trying to generate a bivariate data.frame with the elements of
first row greater than the second row. The more complicated method
that I can think of is:
n <- 10
temp <- expand.grid(1:n,1:n)
temp<-temp[temp[,1]>temp[,2],]
However, I guess there must be some easie
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