Thanks. Before I never used findInterval function. It seems very nice.
On Wed, Apr 6, 2011 at 11:20 PM, David Winsemius wrote:
>
> On Apr 6, 2011, at 9:46 AM, Fabrice Tourre wrote:
>
>> Dear Henrique Dallazuanna,
>>
>> Thank you very much for your suggestion.
>>
>> It is obvious that your method
On Apr 6, 2011, at 9:46 AM, Fabrice Tourre wrote:
Dear Henrique Dallazuanna,
Thank you very much for your suggestion.
It is obvious that your method is better than me.
Is it possible to use cut, table,by etc? Whether there is some
aggregate function in R can do this?
Thanks.
On Wed, Apr 6,
Dear Henrique Dallazuanna,
Thank you very much for your suggestion.
It is obvious that your method is better than me.
Is it possible to use cut, table,by etc? Whether there is some
aggregate function in R can do this?
Thanks.
On Wed, Apr 6, 2011 at 2:16 PM, Henrique Dallazuanna wrote:
> Try t
Try this:
fil <- sapply(ran, '<', e1 = dat[,1]) & sapply(ran[2:(length(ran) +
1)], '>=', e1 = dat[,1])
mm <- apply(fil, 2, function(idx)mean(dat[idx, 2]))
On Wed, Apr 6, 2011 at 5:48 AM, Fabrice Tourre wrote:
> Dear list,
>
> I have a dataframe with two column as fellow.
>
>> head(dat)
> V
Dear list,
I have a dataframe with two column as fellow.
> head(dat)
V1 V2
0.15624 0.94567
0.26039 0.66442
0.16629 0.97822
0.23474 0.72079
0.11037 0.83760
0.14969 0.91312
I want to get the column V2 mean value based on the bin of column of
V1. I write the code as fellow. It wor
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