On Mon, Mar 19, 2012 at 12:47:12PM +, Dajiang Liu wrote:
>
> Thanks a lot for the clarification. I just find it very bizarre that if you
> run a=0.1*(1:9);which(a==0.4)
> it returns the right answer. Anyway, I will pay attention next time. Thanks a
> lot.
Hi.
Yes, these things are bizarr
On 19-Mar-2012 Dajiang Liu wrote:
> Thanks a lot for the clarification. I just find it very bizarre
> that if you run
> a=0.1*(1:9);which(a==0.4)
> it returns the right answer. Anyway, I will pay attention next time.
> Thanks a > lot.
The basic explanation is that, for an integer r (0
Date: 19-Ma
1*(1:4)
> a - 0.4
[1] -0.3 -0.2 -0.1 0.0
>
Berend
>> Date: Mon, 19 Mar 2012 08:59:59 +0100
>> From: rainer.schuerm...@gmx.net
>> Subject: Re: [R] a very simple question
>> To: ldjst...@hotmail.com; r-help@r-project.org
>>
>> As to the reasons, David as g
0.6 0.7 0.8 0.9
> > which( a == 0.3 )
> [1] 3
>
> Rgds,
> Rainer
>
>
> Original-Nachricht
> > Datum: Sun, 18 Mar 2012 21:43:54 +0000
> > Von: Dajiang Liu
> > An: r-help@r-project.org
> > Betreff: [R] a very simple question
>
On Sun, Mar 18, 2012 at 09:43:54PM +, Dajiang Liu wrote:
>
> Dear All,
> I have a seemingly very simple question, but I just cannot figure out the
> answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns
> integer(0). But obviously, the third element of a is equal to 0
18 Mar 2012 21:43:54 +
> Von: Dajiang Liu
> An: r-help@r-project.org
> Betreff: [R] a very simple question
>
> Dear All,
> I have a seemingly very simple question, but I just cannot figure out the
> answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it
On Mar 18, 2012, at 4:43 PM, Dajiang Liu wrote:
Dear All,
I have a seemingly very simple question, but I just cannot figure
out the answer. I attempted to run the
following:a=0.1*(1:9);which(a==0.3);it returns integer(0). But
obviously, the third element of a is equal to 0.3.
I must have
Dear All,
I have a seemingly very simple question, but I just cannot figure out the
answer. I attempted to run the following:a=0.1*(1:9);which(a==0.3);it returns
integer(0). But obviously, the third element of a is equal to 0.3.
I must have missed something. Can someone kindly explain why? Than
There have been several solutions like:
k[k != 3]
The more general form of this idea is:
k[!(k %in% 3)]
Sticking closer to the original form would be:
out <- which(k == 3)
if(length(out)) k[-out] else k
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S
Or
> k <- c(1,1,1,2,2,1,1)
> k[!(k==3)]
[1] 1 1 1 2 2 1 1
>
On Wed, May 14, 2008 at 1:59 PM, Julian Burgos
<[EMAIL PROTECTED]> wrote:
> Try this:
>
> k=c(1,1,1,2,2,1,1,1)
>
>> k[(k!=1)]
> [1] 2 2
>
>> k[(k!=2)]
> [1] 1 1 1 1 1 1
>
>> k[(k!=3)]
> [1] 1 1 1 2 2 1 1 1
>
> Julian
>
>
> Shubha Vishwa
Try this:
k=c(1,1,1,2,2,1,1,1)
> k[(k!=1)]
[1] 2 2
> k[(k!=2)]
[1] 1 1 1 1 1 1
> k[(k!=3)]
[1] 1 1 1 2 2 1 1 1
Julian
Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
(801) 408-8111
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Shubha
> Vishwanath Karanth
> Sent: Wednesday, May 14, 2008 9:16 AM
> To: [EMAIL PROTECTED]
> Subject: [R] A very simple question
>
> Hi R,
>
>
>
> Suppose
&
l[!l==3]
On 14 May 2008, at 17:16, Shubha Vishwanath Karanth wrote:
> Hi R,
>
>
>
> Suppose
>
> l=c(1,1,1,2,2,1,1,1)
>
>
>
> k[-which(k==1)]
>
> [1] 2 2
>
>
>
> k[-which(k==2)]
>
> [1] 1 1 1 1 1 1
>
>
>
> But,
>
>
>
> k[-which(k==3)]
>
> numeric(0)
>
>
>
> I do not want this numeric(0), instead t
On 5/14/2008 11:16 AM, Shubha Vishwanath Karanth wrote:
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How
esday, May 14, 2008 11:16 AM
> To: [EMAIL PROTECTED]
> Subject: [R] A very simple question
>
> Hi R,
>
>
>
> Suppose
>
> l=c(1,1,1,2,2,1,1,1)
>
>
>
> k[-which(k==1)]
>
> [1] 2 2
>
>
>
> k[-which(k==2)]
>
> [1] 1 1 1 1 1 1
Hi R,
Suppose
l=c(1,1,1,2,2,1,1,1)
k[-which(k==1)]
[1] 2 2
k[-which(k==2)]
[1] 1 1 1 1 1 1
But,
k[-which(k==3)]
numeric(0)
I do not want this numeric(0), instead the whole k itself should be my
result... How do I do this?
Thanks,
Shubha
This e-mail may contai
See
?scale
HTH,
Giovanni
> Date: Tue, 13 May 2008 23:27:59 +0900
> From: Yukihiro Ishii <[EMAIL PROTECTED]>
> Sender: [EMAIL PROTECTED]
> Precedence: list
> DomainKey-Signature: a=rsa-sha1; q=dns; c=nofws; s=ybb20050223; d=ybb.ne.jp;
>
> Hi Rusers!
>
> I am ashed of asking such a simple quest
?sweep
-Original Message-
From: "Yukihiro Ishii" <[EMAIL PROTECTED]>
To: "r-help@r-project.org"
Sent: 5/13/08 8:30 AM
Subject: [R] A Very Simple Question
Hi Rusers!
I am ashed of asking such a simple question.
X<-matrix(rnorm(24), 4)
X0<-apply(X,2,mean
On 5/13/2008 10:27 AM, Yukihiro Ishii wrote:
Hi Rusers!
I am ashed of asking such a simple question.
X<-matrix(rnorm(24), 4)
X0<-apply(X,2,mean)
What I want is a matrix which consists of colums such as X[,1]--X0[1].
X-X0 doesn't work.
Perhaps apply function?
scale(X, scale=FALSE)
?scale
Hi Rusers!
I am ashed of asking such a simple question.
X<-matrix(rnorm(24), 4)
X0<-apply(X,2,mean)
What I want is a matrix which consists of colums such as X[,1]--X0[1].
X-X0 doesn't work.
Perhaps apply function?
Thanks in advance.
Yukihiro Ishii
2-3-28 Tsurumakiminami, Hadano, 250-0002 Jap
It sound like you have been loading an existing
workspace in 2.5.0 when you started up R each time.
I don't know much about this but you might want to see
if you have some kind of .Rdata file in the 2.5.0
installation that is doing this.
Otherwise did you make any changes to your Rprofile in
2
?save.image
?load
HTH.
tc
On 10/23/07, David Kaplan <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> My apologies for a very simple question. I just downloaded
> R 2.6.0. I want to bring in all of the objects from 2.5.0
> that I see when I type ls(). I have no idea how to do that.
>
> Thanks in advan
Hi all,
My apologies for a very simple question. I just downloaded
R 2.6.0. I want to bring in all of the objects from 2.5.0
that I see when I type ls(). I have no idea how to do that.
Thanks in advance.
David
--
===
Dav
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