Christian Ritz wrote:
> Hi Peter,
>
> I think one option for what anova could do in the nonlinear case is to
> report the analysis of variance (or deviance) table obtained when
> doing a lack-of-fit test, that is comparing the nonlinear regression
> model to an appropriate ANOVA model. This is for
Hi Peter,
I think one option for what anova could do in the nonlinear case is to report the analysis
of variance (or deviance) table obtained when doing a lack-of-fit test, that is comparing
the nonlinear regression model to an appropriate ANOVA model. This is for example the use
of anova in t
Guru S wrote:
Hi,
I fitted tree growth data with Chapman-Richards growth function using nls.
summary(fit.nls)
Formula: HEIGHT ~ A * (1 - exp(-B * AGE))^C
Parameters:
Estimate Std. Error t value Pr(>|t|)
A 29.007627 0.270485 107.24 <2e-16 ***
B 0.030813 0.001095 28.13 <2e
Hi,
I fitted tree growth data with Chapman-Richards growth function using nls.
summary(fit.nls)
Formula: HEIGHT ~ A * (1 - exp(-B * AGE))^C
Parameters:
Estimate Std. Error t value Pr(>|t|)
A 29.007627 0.270485 107.24 <2e-16 ***
B 0.030813 0.001095 28.13 <2e-16 ***
C 1.84
Hi,
I fitted tree growth data with Chapman-Richards growth function using nls.
summary(fit.nls)
Formula: HEIGHT ~ A * (1 - exp(-B * AGE))^C
Parameters:
Estimate Std. Error t value Pr(>|t|)
A 29.007627 0.270485 107.24 <2e-16 ***
B 0.030813 0.001095 28.13 <2e-16 ***
C 1.8494
Hi,
I fitted tree growth data with Chapman-Richards growth function using nls.
summary(fit.nls)
Formula: HEIGHT ~ A * (1 - exp(-B * AGE))^C
Parameters:
Estimate Std. Error t value Pr(>|t|)
A 29.007627 0.270485 107.24 <2e-16 ***
B 0.030813 0.001095 28.13 <2e-16 ***
C 1.8494
6 matches
Mail list logo
