n(out1 >= out1[1])
There may be a better option, but this works and is fairly straight forward.
Hope it helps,
From: [EMAIL PROTECTED] on behalf of Park, Kyong H Mr ECBC
Sent: Thu 12/27/2007 11:47 AM
To: 'bogdan romocea'
Cc: [EMAIL PROTECTED]
Subje
Classification: UNCLASSIFIED
Caveats: NONE
Thanks for your quick response. The program you mentioned below available
from R is based on number of runs (up or down) not based on a longest length
of runs of same events. To be more specific, for example, from a series,
HHTHHHH, the number of r
2 matches
Mail list logo
