Below.
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sat, Jul 30, 2016 at 11:38 AM, Neal H. Walfield wrote:
> On Sat, 30 Jul 2016 20:35:40 +0200,
> Jeff Newm
On Sat, 30 Jul 2016 20:35:40 +0200,
Jeff Newmiller wrote:
>
> >> [1] TRUE FALSE TRUE FALSE ## NOT c(T,F,T,F)
> >
> >I'm not sure what you mean by NOT here. You get the same answer as I
> >do, as far as I can see.
> >
>
> # valid R
> T <- FALSE
> # invalid R
> TRUE <- FALSE
>
> It is much muc
>> [1] TRUE FALSE TRUE FALSE ## NOT c(T,F,T,F)
>
>I'm not sure what you mean by NOT here. You get the same answer as I
>do, as far as I can see.
>
# valid R
T <- FALSE
# invalid R
TRUE <- FALSE
It is much much safer and clearer to use TRUE/FALSE than T/F. So
c( TRUE, FALSE, TRUE, FALSE ) ma
Hello,
I don't have a solution but see the difference between the two loops below.
for(j in 1:2)
for(i in 1:2){
cat(y[i,j], "\n")
cat(x[i,j][[1]], "\n")
cat(y[i,j] %in% x[i,j], "\n", "\n")
}
for(j in 1:2)
for(i in 1:2){
cat(y[i,j], "\n")
cat(x[
On Sat, 30 Jul 2016 19:28:42 +0200,
Bert Gunter wrote:
> Bottom line: No, I dont see any vectorized way to do this.
>
> However, the following may offer some slight improvement over your approach.
>
> 1. Why do you need to store these as arrays, which are merely vectors
> with a "dim" attribute?
Bottom line: No, I dont see any vectorized way to do this.
However, the following may offer some slight improvement over your approach.
1. Why do you need to store these as arrays, which are merely vectors
with a "dim" attribute?
## convert to vectors (a list is also a vector):
dim(x) <- NULL;
I have a matrix of lists. Something along the lists of (but much
bigger than):
x = array(dim=c(2, 2), data=list())
x[1,1] = list(1:5)
x[2,1] = list(6:9)
x[1,2] = list(10:13)
x[2,2] = list(14:16)
Each list contains a number of observations/ground truth for a
particular state. That is,
7 matches
Mail list logo