[R] help with if statement

Hi all, I had a dataset A like: TIME DV 0 0 1 10 520 24 30 36 80 48 60 72 15 I would like to add 24 to those values higher than 24 in the TIME column. I did the following: If (A$TIME>=24) { A$TIME <- A$TIME+24} It did not work. How should I do it? Thanks, -- View this messag

Re: [R] replacing random repeated numbers with a series of sequenced numbers

Hi Arun, Thanks, it works now. Hi Rui, Your code also works. Thanks, -- View this message in context: http://r.789695.n4.nabble.com/replacing-random-repeated-numbers-with-a-series-of-sequenced-numbers-tp4646559p4646609.html Sent from the R help mailing list archive at Nabble.com. __

Re: [R] replacing random repeated numbers with a series of sequenced numbers

Hi arun, Thanks, I used your code, however, there's error message "Error: could not find function "count"". Thanks, -- View this message in context: http://r.789695.n4.nabble.com/replacing-random-repeated-numbers-with-a-series-of-sequenced-numbers-tp4646559p4646562.html Sent from the R help

Re: [R] time extraction and normalization

Thanks, The code gives the numbers in "days", how can I adjust the code to directly get the numbers in "hours"? I tried units but it did not work. Thanks1 -- View this message in context: http://r.789695.n4.nabble.com/time-extraction-and-normalization-tp4646275p4646298.html Sent from the R

[R] time extraction and normalization

Dear all, I have a series of time variables such as: 04MAY2011:08:19:00 01JUN2011:09:44:00 28JUN2011:08:08:00 25JUL2011:07:44:00 How could I extract the time as a number, so that I can normalize the times by the first time variable? Thanks, -- View this message in context: http://r.78969

[R] extract number from a mixture of character and number

Hi, all, I have a column like the following: ID TIME sub_001 0 sub_001 24 sub_002 0 sub_00224 sub_003 0 sub_00324 sub_004

Re: [R] how to make a histogram with percentage on top of each bar?

Thank you all for the help, York -- View this message in context: http://r.789695.n4.nabble.com/how-to-make-a-histogram-with-percentage-on-top-of-each-bar-tp4634131p4634203.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-proj

[R] how to make a histogram with percentage on top of each bar?

I have a dataset like the following: ID DV 1 0.868576818 2 0.337120116 3 0.029233775 4 0.719783525 5 0.976631182 6 0.672941605 7 0.13239462 8 0.99936475 9 0.91540604 10 0.545686514 to get a histogram with y axis as percentage, I wrote

Re: [R] can not read a table

Thanks, sorry for my post being a little confusing. Jim's code works, I just need to change the last line to y <- read.table(file = fileName,header=TRUE) then, I got the dataframe that I needed. thank you all forl your help! -- View this message in context: http://r.789695.n4.nabble.com/ca

Re: [R] can not read a table

t;> >> # now read in the data > />* read.table(fileName, header = TRUE)*/ > > ID TIME > 1 13250 > 2 13250 > 3 13250 > 4 13250 > 5 13250 > 6 13250 > 7 13250 > 8 13250 >> >> > > > On

Re: [R] data normalization

Thanks for the help, it works very well. -- View this message in context: http://r.789695.n4.nabble.com/data-normalization-tp4633939p4633964.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://s

[R] can not read a table

I have a table like the following: TABLE NO. 1 ID TIME 13250 13250 . . . . . . TABLE NO. 1 ID TIME 13250 13250 . . . . . . TABLE NO. 1 ID TIME 13250 13250 . . . . . . TABLE NO. 1 ID

[R] data normalization

I have a dataframe such like the following: ID TIMEDV 1 0 0.880146038 1 1 0.88669051 1 3 0.610784702 1 5 0.75604 2 0 0.456263368 2 1 0.369991537 2 3 0.508798346 2 5 0.441037014 3 0

Re: [R] Help "deleting negative values in a matrix, and do statistic analysis"

Sorry, my mistake. it works very well!!! thanks, Rui Barradas wrote > > Hello, > > > york8866 wrote >> >> Hi, John, >> >> the code ran well. >> >> however, somehow, the means were not calculated correctly using the >> following

Re: [R] Help "deleting negative values in a matrix, and do statistic analysis"

Hi, John, the code ran well. however, somehow, the means were not calculated correctly using the following code. test <- read.csv("Rtestdataset.csv", as.is=T,header=T) test <- data.frame(test) test rowMeans(test) apply(test,1,function(y)mean(y>=0)) Is there anything wrong? thanks, -- View

Re: [R] Help "deleting negative values in a matrix, and do statistic analysis"

Hi, Rui, I tried your code. It did not work. thanks, -- View this message in context: http://r.789695.n4.nabble.com/Help-deleting-negative-values-in-a-matrix-and-do-statistic-analysis-tp4617792p4618080.html Sent from the R help mailing list archive at Nabble.com. _