://cran.r-project.org/web/packages/fOptions/fOptions.pdf
-rex
--
"The market can remain irrational longer than you can remain solvent."
-- John Maynard Keynes
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://st
tuvwxyz",
"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789",
paste("12345678901234567890123456789012345678901234567890123456789012",
"34567890123456 ..." ... [TRUNCATED]
[...]
HTH,
-rex
--
"...I paid a visit to Schrodinger in his
pe character is '^]'.
But it's probably expecting TLS, and sendmailR doesn't support it.
Please let me know if we have some solution for this.
If you want to use sendmailR, you need to find a mail server that
does not require TLS. This may mean running your own mail serve
Prof Brian Ripley [2013-06-09 00:22]:
On 09/06/2013 08:05, rex wrote:
Typo. Actually, I downloaded 0.72. Later, I found 0.73 here:
http://cran.r-project.org/src/contrib/Archive/CGIwithR/
But see http://cran.r-project.org/package=CGIwithR for the current host.
I did; that's where I
Prof Brian Ripley [2013-06-08 23:23]:
On 08/06/2013 23:27, rex wrote:
CGIwithR apparently is not available on CRAN for R 2.15.x, so I
It is not hosted on CRAN. You should ask its maintainer (and package
installation problems most often belong on the R-devel list).
Actually it is, but not
rex [2013-06-08 18:05]:
CGIwithR apparently is not available on CRAN for R 2.15.x, so I
downloaded the source (0.73) and tried:
~/Downloads$ R CMD INSTALL CGIwithR
Typo. Actually, I downloaded 0.72. Later, I found 0.73 here:
http://cran.r-project.org/src/contrib/Archive/CGIwithR/
D/L 0.73
Hello,
CGIwithR apparently is not available on CRAN for R 2.15.x, so I
downloaded the source (0.73) and tried:
~/Downloads$ R CMD INSTALL CGIwithR
* installing to library ‘/home/rex/R/x86_64-pc-linux-gnu-library/2.15’
* installing *source* package ‘CGIwithR’ ...
configure: creating
Hello,
I have written a version of the Kohenen Self Organizing Map (in R) and wish
to use ggplot2 for the visualization. My results are RGB values in a matrix
[x,y,1:3] where x and y comprise the first two dimensions and the third
dimension is the RGB vector.
I am not sure whether to use geom_ti
another
software package.)
Thanks,
Rex
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained
Thanks for the replies! The answer is that barplot() returns the x
coordinates of the bars.
On Fri, Jan 15, 2010 at 12:01 PM, Rex C. Eastbourne <
rex.eastbou...@gmail.com> wrote:
> How can I write text inside a bar of a barplot? I tried using text(), but I
> am only able to specify t
(e.g.
counties). Picture: http://drop.io/hjcodjj/asset/capture-png
I would like to put in a label inside each sub-bar (e.g. indicating the name
of the county represented by that sub-bar).
Rex
p.s.: In case anyone finds this visualization useful I'll share my code
afterward, but just need to get
Thanks Jim! I followed the instructions in the FAQ and wrapped print()
around my function calls. The images are now properly generated.
Rex
On Thu, Jan 14, 2010 at 4:38 PM, jim holtman wrote:
> If you are using lattice, check out FAQ 7.22
>
> On Thu, Jan 14, 2010 at 5:15 PM, Rex C. E
and searched the mailing list archives and the web, but haven't
figured out how to get this working. Any help would be appreciated.
Thanks,
Rex
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.
On Thu, Jan 14, 2010 at 2:15 PM, Rex C. Eastbourne wrote:
> I am encountering problems using the png() function to save around 20
> charts to separate files.
>
> My script is conceptually structured as follows:
>
> ###
> png("Image %03d.png")
>
> # th
re
> often a good alternative). "
>
> The result of setting origin is more sensible:
> require(lattice)
> da <- expand.grid(A=c("a","b"), x=1:4)
> da$y <- c(1,5,6,3,2,0,6,0)
>
> barchart(y~x|A, data=da, horizontal=FALSE)
>
> barchart(y
ark, those bars appear to represent
higher numeric values. Is there a way to make the length of the bar
proportional to the data value, so that people looking at my chart are not
misled?
Thanks,
Rex
[[alternative HTML version deleted]]
_
ist(cum.tot, width))
>text(cum.tot + width/2, heights/2 + cum.heights, x$County)
> }, split.dat, cum.widths, widths)
>
> axis(1, (widths / 2 + cum.widths), names(split.dat))
>
>
>
> Hope this helps,
> Simon Knapp
>
This is great, Simon! I'm going to tweak
On Tue, Jan 12, 2010 at 5:26 PM, Rex C. Eastbourne wrote:
> Let's say I have data in the following schema that describes the number of
> purchases a company has received from each County in the US:
>
> State | County | Purchases
> ---
>
Let's say I have data in the following schema that describes the number of
purchases a company has received from each County in the US:
State | County | Purchases
---
NJ | Mercer | 550
CA | Orange | 23
I would like to visualize what states contribute the m
Hi,
I have two separate questions relating to the KernSmooth package. I am
using the dpik function from the KernSmooth package and receive the error
Warning message:
In kappam * Gcounts :
longer object length is not a multiple of shorter object length
I saw an earlier post , bu
20 matches
Mail list logo
