Hello!
I want to calculate simultaneous confidence intervals for a nominal variable
with three categories: "yes", "no", "partially" and I expect that far more than
5 samples fall into each category.
I have read that Glaz & Sison's method is only appropriate for variables with 7
or more categorie
Hello!
I think there is a major statistical error or at least an inaccuracy
in ggerrorplot and I don't know where to report this problem.
When using ggerrorplot, you can choose the argument desc_statby=sd or
desc_statby= se. Where sd is described as "standard deviation of the
mean".
and s
Hello,
I am using ezAnova for the first time and I am a bit lost.
My data "epindata" looks like this:
studno faculty epin smoker
1 16 2
2 2 16 1
3 2 18 2
4 2 24 1
5 3 15 2
6
gth
And I haven't the faintest idea what they mean in this context.
I would be very grateful if somebody could help me.
Best regards
Claudia Paladini
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Hello,
I took my first steps in dynamic reports with Gnu R and used sweave().
I therefore run Sweave() with an example of Friedrich Leisch, starting
like this:
\ documentclass [ a4paper ]{ article }
\ title { Sweave Example 1}
\ author { Friedrich Leisch }
\ begin { document }
\ maketitle
an
Hi Jim,
that is exactly what I was looking for. Thanks a lot! I can even
choose how to label the countries e.g. Italy or just IT.
Have a nice day and thank you for helping me again
Claudia
Zitat von Jim Lemon :
Hi Claudia,
You're right, when the map is maximized the coordinates of the obj
Hi Jim,
thanks again for your help! Yes I am using the "rworldmap" package.
identifyCountries() works.
But I am not entirley happy with this solution. You have to click on
all 27 countries and when your position is not perfect you get e.g.
"Vatican" or "Monaco" instead of "Italy" and you have
Hello,
I have problems to label countries in my map.
I use the following code to draw the map:
epimap=joinCountryData2Map(epidata,joinCode="NAME",nameCountryColumn="Country",nameJoinColumn="Country")
mapCountryData(epimap, nameColumnToPlot="EPI.2.0" ,mapRegion="europe",
oceanCol="slateblue1",
Hello,
I use the following code to draw a map of Europe. The colour of the
countries depends on a value called "EPI2.0" in a data frame called
epidata.
epimap=joinCountryData2Map(epidata,joinCode="NAME",nameCountryColumn="Country",nameJoinColumn="Country")
mapCountryData(epimap, nameColumnTo
Thank you very much!
I used indeed rgl.
The problem was apperently that I used text3d() in the wrong way.
When I use it this way:
plot3d(x, y, z,xlab="PC1", ylab="PC2", zlab="PC3", size=5)
text3d(x=x,y=y,z=z,texts=names, col=4)
It workes the way I wanted.
So thanks again and have a nice w
Hello,
I want to draw 3D plot. The coordinates should be inticated with a
red point and additional I want to label them with a name.
I tried this:
plot3d(x, y, z,xlab="PC1", ylab="PC2", zlab="PC3",main="Country
score resemblance (Stoxx600 rated by
Vigeo)",text3d(x=x,y=y,z=z,texts=name
Hi Jean,
nevertheless this page "R-bloggers" looks realy interesting so I'll
work through the tutorial.
Thanks again for recommanding this web-site.
Best regards
Claudia
Zitat von "Adams, Jean" :
Claudia,
I have not worked through the example myself. Since you seem to be getting
errors,
Hi Jim,
that works nice.
Thanks again!
Have a nice weekend, best regards
Claudia
Zitat von Jim Lemon :
On 10/31/2013 03:04 AM, palad...@trustindata.de wrote:
Hi Jim,
thats the second time that you helped me in a short while so thanks a lot!
But it seems to me quite laborious and error-pron
Hi Jean,
thanks again for your response. As I told you I did the downloads and
double checked if I selected the right directory.
But I noticed right now what happend:
The command in the example is :
eurMap <- readShapePoly(fn="NUTS_2010_60M_SH/Shape/data/NUTS_RG_60M_2010")
But it should be :
Hi Jim,
thats the second time that you helped me in a short while so thanks a lot!
But it seems to me quite laborious and error-prone to first select
all the relevant countries in this long list and then to create a
color vector.
But perhaps I get it all wrong.
For the color vector I fi
Hello,
I would like to draw a map of Europe. Each country should be colored
depending on how it scores in an index called GPIndex.
Say a dark red for real bad countries a light red for those which are
not so bad, light blue for the fairly good ones and so on up to the
really good ones in a d
Hello,
I did some nice grafics using plot 3d and scatter3d. Is there a,
hopefully not too complicated way, to transform these dynamic,
three-dimensional and interactive grafics in a kind of
executable file? I want to show and send them via e-mail to projekt
partners who don`t use GNU R and w
Hello,
I have got a data frame looking like this:
Country Sector m-value
USA Banks 38.5
USA Media 17
USA hospitals 2.3
Germany Banks 56
Germany real estate 1
ItalyBanks 34
ItalyMedia
Hello everybody,
I have got a data set with about 400 companies. Each company has a
score for its enviroment comportment between 0 and 100. These companies
belong to about 15 different countries. I have e.g. 70 companies from
UK and 5 from Luxembourg,- so the data set is pretty unbalanced and
Hello !
I have a rather mathematical than statistical question. I have a
formula: P=R*T/(v-b) -a/(sqrt(T)*V*(V+b)) and I want to solve the
equation for V , in terms of V= . Is this possible with R or have I
to use another program perhaps octave?
thanking you in anticipation
Claudia
__
Hello!
I have got a dataframe with 10 columns and 100 rows. The seventh column
consists of a lot of country names.
When I use newdata=subset(data, data[, 7]=="United Kingdom"|data[,
7]=="Germany") I get just the rows where the country name is UK or
Germany.
But the level information doesn`t cha
ct some days, month or years from a date?
thanking you in anticipation
Claudia Paladini
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and pr
Hello everbody,
I want to generate different subsets of my data-set and safe this
subsets with names listet in a vector. Because in reality I have got
about 70 subsets I want to realize this in a loop
Somehow like this:
names=c("nam1",
"nam2","nam3","nam4","nam5","nam6","nam7","nam8","nam9",
Hello everbody,
I want to generate different subsets of my data-set and safe this
subsets with names listet in a vector. Because in reality I have got
about 70 subsets I want to realize this in a loop
Somehow like this:
names=c("nam1",
"nam2","nam3","nam4","nam5","nam6","nam7","nam8","nam9",
Hello everybody,
I've got a problem concerning the function unique. I have got a
data.frame "shopdata" with 1000 shop which were evaluated at different
points in time.
With function subset I chose those shops with more then 10 employee and
store it in data.frame "bigshopdata" with 700 shops.
Hallo,
I have a question concerning the function "correlogram" from
library(corrgram).
Is it possible do write the variable names not in the diagonal but on
the left and at the buttom of the graphic?
I searched the manual and tried a lot but didn't get it.
Thank you very much and best regar
Hello,
are there fixed threshold values for the changes between different
shades of blue in the corrgram?
Or is a chang relative depending on the data?
I didnt get it in manual.
Thank you very much, best regards
Claudia
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Hello,
when I convert a factor like this a=01.10.2009
into a date using b=strptime(a, format="%d. %m. %Y").
It works very well.
But when I try to convert c = 2009/10 into a date using
d=strptime(c, format="%Y/%m")
it doesnt work at all. I get d=NA.
What did I do wrong?
Thank you very much for you
Hello,
I want to do a cluster analysis with my data. The problem is, that the
variables dont't consist of single value but the entries are pairs of
values.
That lokks like this:
Variable 1:Variable2: Variable3: ...
(1,2) (1,5) (4,2)
(7,8) (3,88)
Dear R-users,
I used x.out=sign1(data,makeplot=TRUE) from the package mvoutlier to detect
multivariate outliers.
I would like to label the points in the resulting plot with the row names of
my data set. But none of my attempts does lead to a result. Can anybody help
me, please?
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