gt;col=adjustcolor("yellow", 0.5),
>border = NA)
> lines(1:20, mean1,lty=1,lwd=2,col="blue")
> lines(1:20, mean2,lty=1,lwd=2,col="yellow")
>
>
> On 19-09-2023 09:16, Ivan Krylov wrote:
> > В Tue, 19 Sep 2023 13:21:08 +0900
> >
Thank you very much for the help. Turn out I can use 'density' to
differentiate the overlaid area.
On Tue, Sep 19, 2023, 16:16 Ivan Krylov wrote:
> В Tue, 19 Sep 2023 13:21:08 +0900
> ani jaya пишет:
>
> >
> polygon(c(1:20,20:1),c(mean1[1:20]+sd1[1:20]
Dear R-Help,
I try to overlay two standard deviations from two means. How to change
the overlaid area between two shaded areas into a specific color or
maybe a soft color in a plot?
> dput(mean1[1:20])
c(122.194495954369, 118.955256282505, 115.540991140893, 113.116216840647,
111.24053267553, 109.
ummy<-index[which(index1==i)]
C[,,i]<-apply(B[,,dummy],c(1,2), mean,na.rm=T)
}
The problem is when there is a month that doesnt meet the condition,
it will return 0 element.
apply(B[,,1],c(1,2), mean,na.rm=T) also produce an error.
Any solution and turnaround would be appreciate
quot;)
>
> after drawing the world map you will see the proportions.
>
> Jim
>
> On Fri, Jan 7, 2022 at 7:20 PM ani jaya wrote:
> >
> > Hi Jim,
> >
> > Thank you for the alternative. Absolutely will try it.
> > Can you explain a bit about "Maps draws
> box()
>
> should give you info how mar looks like before each step and which one is to
> blame.
>
> Jim gave you also some possible workaround.
>
> Cheers
> Petr
>
> > -Original Message-
> > From: ani jaya
> > Sent: Friday, January 7, 2022 9:
n approximately 2x1 plot. Maybe this:
>
> mappar<-par("usr")
> rect(mappar[1],mappar[3],mappar[2],mappar[4])
>
> Jim
>
> On Fri, Jan 7, 2022 at 6:25 PM ani jaya wrote:
> >
> > Dear R expert,
> >
> > I try to box a figure using box(). However
ld="name", lforce="n", ...)
>
> map function redefines mar so your first par is probably changed during
> plotting map and after you define it again box use new mar values.
>
> Cheers
> Petr
>
> > -Original Message-
> > From: R-help On Behal
Dear R expert,
I try to box a figure using box(). However it box the default margin,
not the specified margin.
#working as expected
barplot(1:20)
box()
#working as expected, the box follow the margin
par(mar=c(2, 6, 5, 4))
barplot(1:20)
box()
#not working
install.packages("maps")
library(maps)
one of my solution :
text(x,y,"\u00B0C", cex=1.1, font=2)
it will produce "°C"
text(x,y,"\u00B3C", cex=1.1, font=2)
it will produce "superscript(3)C"
so basically change the character after the "\u00B..." will produce
the superscript.
Best, Ani
On Wed, Dec 1, 2021 at 4:05 AM Rich Shepard wro
and yes I can sleep well now. Thank you, Jim.
ne<-rep(0,ne)
total<-c(neggg,posss,ne)
hist(total)
Best,
Ani Jaya
On Tue, Sep 7, 2021 at 9:38 AM ani jaya wrote:
>
> Hello Jim, thank you for your response. What I am trying to achieve is
> like this:
>
> #calculate the positiv
but not success yet. After that, I want to plot the histogram to
see the distribution of significant stations.
Any lead is appreciate. Thank you
Ani Jaya
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/
nd negative at the same
time. Is there any way to combine positive and negative significant
value and plot the histogram? or we can calculate the 0 station first
separately?
Any lead is really appreciated. Thank you.
Ani Jaya
__
R-help@r-project.org ma
%%12 + 1
>>
>> This changes the month numbering so that Dec becomes 1, Jan becomes 2, etc
>> Then your for loop does what you want.
>>
>> HTH,
>> Eric
>>
>>
>>
>>
>> On Wed, Apr 21, 2021 at 11:09 AM ani jaya wrote:
>>
>>
Dear r community,
I have a data frame that shows the month of occurrence of the maximum
value on let say 10 stations in 30 years. I want to make percentages
based on seasons (DJF, MAM, JJA, and SON). I can do that by the code
below but only when we put season by JFM, AMJ, ...(or 123; 456;
789;..)
:12],list(mon10$Group.1),which.max)
>
> Jim
>
> On Wed, Dec 16, 2020 at 4:55 PM ani jaya wrote:
> >
> > Dear R-Help,
> >
> > I have a data frame containing monthly maxima of rainfall in 10
> > locations for 30 year and want to look at a month where an annual
&
Dear R-Help,
I have a data frame containing monthly maxima of rainfall in 10
locations for 30 year and want to look at a month where an annual
maxima happens. I can get the annual maxima using aggregate. I try to
extract the month using the code below.
ann10<-aggregate(mon10[3:12],list(mon10$Grou
Dear r list,
I try to locate any local max value and location of data that follow 7
moving window condition, meaning that this data is largest and
centered in 7 values to the left and 7 values to the right. I can
solve it by using for and if function, like below:
dput(nordn)
c(`1` = 36.3167318892
Dear R community,
I found some missing x label when I saving this plot to tiff file:
justsample <- rnorm(n=1095*3,mean=100,sd=10)
justsample <- as.data.frame(matrix(justsample,ncol=3))
dd <- seq(from=as.Date("1985-01-01"), to =as.Date("1987-12-31"), by='day')
y <- data.frame(Year=substr(dd,1,4),
Maybe simply add:
points(station$Lon, station$Lat, col="red", pch=16, label="Your Country")
text(station$Lon, station$Lat,"Your Country",
col="black", pos=3, cex=1)
station$Lon and Lat in your coordinate position.
Regards,
Ani
On Tue, Mar 31, 2020 at 10:58 PM george brida wrote:
>
> Dea
> -- Bert
>
>
>
> On Mon, Jan 13, 2020 at 10:56 PM ani jaya wrote:
>>
>> Dear Jeff and Bert,
>>
>> Thank you very much for your correction and explanation.
>> And yes, I need to study about date format more.
>> Sorry for HTML mail, don't reali
phase amp
115 1986 4 25 -0.319090 -0.363030 2 0.483332
526 1987 6 10 1.662870 0.291632 5 1.688250
977 1988 9 3 -0.604950 -0.299850 1 0.675181
1374 198910 5 0.972298 -0.461030 4 1.076060
1760 199010 26 -1.183110 -1.589810 2 1.981730
mjo30[ date[1] == mjo30$Dt, ]
>
> or
>
> mjo30[ mjo30$Dt %in% date, ]
>
> but the subset function would not work in this case because you have two
> different objects (a column in mjo30 and a vector in your global environment)
> both referred to as 'date'.
>
> O
Good morning R-Help,
I have a dataframe with 7 columns and 1+ rows. I want to subset/extract
those data frame with specific date (not in order). Here the head of my
data frame:
head(mjo30) year month date rmm1 rmm2 phase amp
1 1986 11 -0.326480 -1.55895 2 1.59277
2 1
; # order the list by year-month
> inx_ym <- sapply(pon1, function(DF){
>format(DF[["Tanggal"]][1], "%Y-%m")
> })
> pon1 <- pon1[order(inx_ym)]
>
>
> # get the minimum and maximum of every "RR"
> min.RR <- sapply(pon1, function(DF) min
Dear R-Help,
I have 30 of year-based excel files and each file contain month sheets. I
have some problem here. My data is daily rainfall but there is extra 1 day
(first date of next month) for several sheets. My main goal is to get the
minimum value for every month.
First, how to extract those da
rix)
> boxed.labels(year,fin_month,month.abb[month],border=NA,cex=0.7)
>
> Jim
>
> On Thu, Nov 7, 2019 at 3:35 PM ani jaya wrote:
> >
> > Dear Jim,
> >
> > Thank you very much for nice suggestion and figure there. But what I
> need is the y axis start fro
t;n", type="l", ylab="Month", xlab="Year",
> main="Month of occurrence in year")
> axis(1,at=seq(1981,2014,3))
> library(plotrix)
> boxed.labels(year,month,month.abb[month],border=NA,cex=0.7)
>
> Jim
>
> On Thu, Nov 7, 2019 at 1:24 PM an
Dear R-Help,
I have 35 data that is month when the annual minima happened. So I want to
plot those data but the order of y axis is not from 1 to 12, but let say
start from 9,10,11,12,1,..8. The reason to do this is when 12 (Dec) meet 1
(Jan) in the following year the graph is not quite good (for m
s = "")
> })
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 02:38 de 18/10/19, ani jaya escreveu:
> > Dear R-Help,
> >
> > I have a list of data frame that I import from excel file using read.xlsx
> > command.
> >
> > sheets &
Thank you very much everyone. All fine now!!
On Fri, Oct 18, 2019 at 11:42 AM Rolf Turner
wrote:
>
> On 18/10/19 2:43 PM, ani jaya wrote:
>
> > Dear R-Help,
> >
> > I have a list of data frame that I import from excel file using read.xlsx
> > command.
> >
[1]123
> > is.na(x) <- x== ## rhs is an "index vector" of logicals
> > x
> [1] 1 2 3 NA
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along and
> sticking things into it."
> -
Dear R-Help,
I have a list of data frame that I import from excel file using read.xlsx
command.
sheets <- openxlsx::getSheetNames("rainfall.xlsx")
test <- lapply(sheets,function(i) read.xlsx("rainfall.xlsx", sheet=i,
startRow=8, cols=1:2))
names(test) <- sprintf("%i", 1986:2015)
And I got a dat
Dear R-Help,
I have a list of data frame that I import from excel file using read.xlsx
command.
sheets <- openxlsx::getSheetNames("rainfall.xlsx")
test <- lapply(sheets,function(i) read.xlsx("rainfall.xlsx", sheet=i,
startRow=8, cols=1:2))
names(test) <- sprintf("%i", 1986:2015)
And I got a data
ar(mfrow=c(3,3))
> for(i in seq_along(a)) {
> hist(a[[i]], xlab='x', main=sprintf("k = %i", (2:9)[i]))
> }
>
>
>
>
>
> On Thu, Apr 18, 2019 at 9:19 AM ani jaya wrote:
> >
> > Dear R community,
> >
> > I'm trying to create
Dear R community,
I'm trying to create a looping to see the effect of number of samples from
one dataset.
Lets say I have 10 values in a single data frame and I want to see the mean
of each sampling let say from 2-9 number of sampling. But I want to do the
repetition let say up to 100 for each num
36 matches
Mail list logo
