tion.
If there are any other ways to do this, please let me know.
Thomas Subia
On Thursday, September 7, 2023 at 10:31:27 AM PDT, Rui Barradas
wrote:
Às 14:23 de 07/09/2023, Thomas Subia via R-help escreveu:
>
> Colleagues
>
> Consider
> smokers <- c( 83,
004132
# trend test for proportions indicates proportions aretrending.
How does one identify the direction of trending?
# prop.test indicates that the proportions are unequal but doeslittle to
indicate trend direction.
All the best,
Thomas Subia
[[alternative HTML version d
Colleagues,
Your suggestions are elegant and greatly appreciated.
Thomas Subia
On Friday, August 11, 2023 at 11:08:42 PM PDT, Berwin A Turlach
wrote:
G'day Thomas,
On Sat, 12 Aug 2023 04:17:42 + (UTC)
Thomas Subia via R-help wrote:
> Here is my reproducible code for
int()+
geom_smooth(se=TRUE,fill="blue",color="black",linetype="dashed")+
theme_cowplot()
I'd like to add a black boundary around the shaded area. I suspect this can be
done with geom_ribbon but I cannot figure this out. Some advice wou
)))
Question 1:How can I save the plotly graph with a specific graph size?Using
ggsave, one can define the height, width and unit of measure, is there
something similar in plotly?Since I am creating the same gauge plot but with
different data, I'd like all the resulting graphs to have the
not sure why this occurs. Changing the statement to 56, results in the
> gauge reading 60. I'm not sure what needs to be changed in the script or the
> environment to stop rounding.
> On Jul 22, 2023, at 10:43, Boris Steipe wrote:
>
> What do you mean "Rounded&
Colleagues,
Thanks for the update.
My colleagues at work have run this script but the resulting graph output for
value is rounded. How can one turn this annoying feature off?
I've googled this but to no avail.
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e indicator color from green to some other color?
How can I change the typeface and font size of the speedometer tick mark font
size?
Thomas Subia
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-value = 0.004132
How can one determine the direction of the trend?
Thomas Subia
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PLEASE do re
Colleagues,
Thanks for the help!
Root cause of the problem was not to define z and x as factors!Now I know
better.
All the best,
Thomas Subia
On Monday, June 5, 2023 at 08:45:39 PM PDT, Richard M. Heiberger
wrote:
This works.
> d$zz <- factor(d$z, levels=c("low",&q
erator
I suspect that this error stems from read.table.
This graph is easily done with Excel but I'd rather use R
Any help would be appreciated.
Thanks
Thomas Subia
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3 1.000 1.000 -
4 0.119 0.093 0.124
Is there a way to generate a graph which illustrates the pairwise comparison of
proportions?
Thomas Subia
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://stackoverflow.com/questions/19513705/error-in-rstudiogd-shadow-graphics-device-error-r-error-4-r-code-execution
Hope this helps!
Thomas Subia
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.5, y=-.05, label="PT Not Done",size=5,fontface="bold")+
theme_cowplot()
The plot has the wrong date order.
What is desired is 12-29, 12-30 and 01-01.
Some feedback would be appreciated.
All the best,
Thomas Subia
"De quoi devenir chevre? Des donnees"
_
://support.minitab.com/en-us/minitab/20/media/pdfs/translate/Multiple_Comparisons_Method_Test_for_Equal_Variances.pdf
I was hoping that R had something similar.
I tried a Google search on this but to no avail.
Thomas Subia
On Sunday, October 30, 2022 at 03:44:54 PM PDT, Rui Barradas
wrote:
Às 21:47 de
group levels?
I can do this using Minitab but I'd prefer using R for this.
Thomas Subia
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PLEASE do read the posting guide http://
transform the
dataset into a normal distribution.
I suspect that this is as close as you can get to an automatic distribution
fitting.
Hope this helps!
Thomas Subia
-Original Message-
From: R-help On Behalf Of
r-help-requ...@r-project.org
Sent: Thursday, October 27, 2022 3:00 AM
To
er for your analyses.
Hope this helps!
Thomas Subia
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provid
Thanks Ivan!
This makes perfect sense now!
All the best,
Thomas Subia
Statistician
-Original Message-
From: Ivan Krylov
Sent: Wednesday, December 15, 2021 5:21 AM
To: Thomas Subia via R-help
Cc: Thomas Subia ; Thomas Subia
Subject: Re: [R] transformTukey
On Wed, 15 Dec 2021 05:11
er than 0.
Data set is heavily right skewed
> library(rcompanion)
> trans_data <- transformTukey(data)
Error in is.infinite(TRANS) :
default method not implemented for type 'list'
Why is this occurring?
Thomas Subia
__
R-hel
Colleagues,
Some co-workers are wondering about how secure R software is.
Is there any documentation on this which I can forward to them?
All the best,
Thomas Subia
Quality Engineer
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quot;J" "K"
Now from this reduced dataset, I can generate another random selection with
any size I choose.
One problem with this is that this is cumbersome when ones original dataset
is large or when one wants to subgroup the original dataset into many
different subg
sure that is the case, nevertheless, it's worth asking the
question.
Some guidance would be appreciated.
Thanks!
Thomas Subia
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PLEASE d
Colleagues,
Here is my code which plots sin(x) vs x, for angles between 0 and 180
degrees.
library(ggplot2)
library(REdaS)
copdat$degrees <- c(0,45,90,135,180)
copdat$radians <- deg2rad(copdat$degrees)
copdat$sin_x <- sin(copdat$radians)
ggplot(copdat,aes(x=degrees,y=sin_x))+
geom_point(size =
Ferri,
Radar Charts are often used to compare two or more items or groups on various
features or characteristics. However, as the number of groups increases, the
user has a harder time making comparisons between groups. As the number of
groups increase, the number of spokes of the radar chart in
E_14_2,"BUBBLE_14_2.txt")
After the text files have been created, I cut and paste each column of data
to Excel.
This has worked fine if the number of cells I am extracting from a file is
small.
If the number gets larger, this method is inefficient.
E_14_2,"BUBBLE_14_2.txt")
After the text files have been created, I cut and paste the contents of each
text file to Excel.
This has worked fine if the number of cells I am extracting from a file is
small.
If the number gets larger, this method is inefficient.
. Else Serial_test is a fail.
I'm at a loss to figure out how to do this in R.
Some guidance would be appreciated.
All the best,
Thomas Subia
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Colleagues,
To add an annotation using ggplot, I've used
annotate("text",x=17,y=2130,label="16 u").
However, this does not work when trying to annotate box plots by groups since
groups are factors.
Any advice would be appreciated.
Thomas Subia
ASQ CQE
IMG Comp
les(pattern="*.xls", full.names = TRUE)
# Extract part average from cell c6 for all Excel files
avgs <- lapply(files, read_excel, sheet="Flow Data", range=("c9"))
# Write data to text file
write.table(avgs ,"avgs.txt",sep="\t")
I'm not sure wher
he first lines of the dates.txt file.
"X43859"
"X43859.1"
"X43859.2"
"X43859.3"
"X43833"
In Excel, this is what is recorded.
1/29/2020
1/29/2020
1/29/2020
1/29/2020
1/3/2020
It appears that readxl is adding additional characters which are sig
reate your choice graphs with
whatever variables you choose without having to write any code.
Parenthetically, after creating the graph, the add in will display the code
which created your graph.
Pairing equisse with Chang's book will enable you to learn how to create graphs
using R more easily
Post.Date Pre.Hole
Pre.flowPre.Date
Any ideas on how to do this would be appreciated.
Thomas Subia
Statistician / Senior Quality Engineer
IMG Companies
225 Mountain Vista Parkway
Livermore, CA 94551
T. (925) 273-1106
F. (925) 273-
E. tsu...@imgprecision.com
here a way to have R extract parts common to both directories?
Thomas Subia
Statistician / Senior Quality Engineer
ASQ CQE
IMG Companies
225 Mountain Vista Parkway
Livermore, CA 94551
T. (925) 273-1106
F. (925) 273-
E. tsu...@imgprecision.com
Precision Manufacturing for Emerging Technolog
df <-as.data.frame(flow.datum)
myflow <- list(flowdf)
write.table(myflow,"myflow.txt",sep=",")
The problem with the dates.txt and the serials.txt is that they need to
associated with its 49 corresponding values in myflow.txt.
The objective is to create a text file having
-t(serial_df)
myserials <- list(trans_serial)
write.table(myserials,"myserials.txt",sep="\t")
R Output
""
"X96739.0027.1"
"X96739.0041.1"
"X96739.0044.1"
Original Excel Content
96739-0027/1
96739-0041/1
96739-0044/1
How can I amend my scri
Colleagues,
I've got several text files which contain data for each metric I need to report
on.One text file contains the serial number data. Another has customer and work
order number. Another has test data. All text files have the same number of
rows but all have different numbers of columns.
to 500.
I reran pdf_combine(files, output= "joined.pdf") and I didn't get a too many
open files warning.
Is there an R setting which I can change to allow more files to be read?
All the best
Thomas Subia
Statistician / Sr. Quality Engineer
IMG Companies
___
t;,lines)
# output for date looks like [1] 6 62 118 174 230 286 342 398
# These are exactly the line positions I need.
Now that I've got the desired lines, I don't know how to extract the data from
those lines.
Any advice would be appreciated.
All the best,
Thomas Subia
Statistici
hescript for this. Some
pointers would be appreciated.
All the best.
Thomas Subia
Statistician / Senior Quality Engineer
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re a way to format this to display the original data?
I'd like to extend this code to all of the pdf files in a directory and to
generate a table of all the serial, flatness, parallel1 and parallel2 data.
I'm not having a lot of success trying to build the script for this. Some
poin
Jim,
That works well!
Thanks again for your help!
Thomas Subia
-Original Message-
From: Jim Lemon
Sent: Wednesday, October 30, 2019 11:14 PM
To: Thomas Subia
Cc: r-help@r-project.org
Subject: Re: [R] Help for pdf conversion
Hi Thomas,
Perhaps you should be doing something like
=TRUE,col.names =FALSE) and examine the output, my output does
not match cat(txt[1]).
I suspect that sep= "\t",row.names =TRUE,col.names =FALSE) might be the error.
How can one output the contents of cat(txt[1]) and retain its format?
Thomas Subia
[[alternative HTML version
found using the equations in the
article.
All the best,
Thomas Subia
Quality Engineer / Statistician
Fresenius Medical Care North America
From: tgs...@yahoo.com
Sent: Tuesday, July 9, 2019 8:01 AM
To: Thomas Subia
Subject: [EXTERNAL EMAIL] Fw: [R] Sample size required to estimate population
m not sure whether the pwr
package does that.
On Thursday, July 4, 2019, 4:31:44 PM PDT, John wrote:
On Tue, 2 Jul 2019 22:23:18 +0000 (UTC)
Thomas Subia via R-help wrote:
> Colleagues,
> Can anyone suggest a package or code which might help me calculate
> the minimum samp
Colleagues,
Can anyone suggest a package or code which might help me calculate the minimum
sample size required to estimate the population variance? I can do this in
Minitab but I'd rather do this in R.
Thomas Subia
[[alternative HTML version de
Colleagues,
When using Levene's test, I can identify if there are any differences in
variance between factors. This is straight forward
Is there a way to do a post hoc test to identify variance differences between
factors? This is not so straight forward.
All the best
Thomas
s that they differ by some other location shift (and
the one-sided alternative "greater" is that A is shifted to the right of B).
You observed that the medians are different. While the medians may be
different, the test is dependent on ranks not
Javid wrote:
"I have two set of data in excel:
A column( 16.38, -31, -16.77, 127, -57, 23.44 and so on)
B column ( -12, -59.23, -44, 34.23, 55.5, -12.12 and so on)
I run the wilcox test as :
wilcox.test(A , B, data = mydata, paired = FALSE)
I got always the p value very high, like 0.60
Even I
t;Flow Data",range=("b9:c10"))
How can I do this for all my Excel files in the directory?
I can get the list of Excel files using: files =list.files(pattern="*.xls")
But I’m not sure where to go from here.
Some guidance would be appreciated.
All the best
Thomas
Hello all,
Zeki(?) reported:
> ggplot(data = mtcars, aes(x= wt, y= mpg)) + geom_line()
> Error: Found object is not a stat.
Using R v3.4.62 and R studio, I'm unable to reproduce this error.
All the best,
Thomas Subia
[[alternative HTML vers
Colleagues,
age_days <- difftime(Date,DOM,units="days")
date_vals$age_yrs <- age_days/365.242
I'm trying to calculate the number of years between DOM and Date.
The output reads
DOM Date age_yrs
1 2005-04-04 2015-05-13 10.10563 days
How doe
see your three outliers
myboxplot$out # it will print the values of the outliers
How does one amend this code to produce the outliers by a group?
All the best,
Thomas Subia
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