"or an incompetent"
Such harsh words Peter. You're not making this a friendly environment for
people to ask questions. Is there a less competent attribute mailing list so
that some of us don't offend you with our questions?
On Aug 13, 2010, at 2:11 PM, Peter Dalgaard wrote:
Andrea Franceschini
why
I was asking and giving an alternative that would still use 5 degrees of
freedom.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-----
> From: TGS [mailto:cran.questi...@gmail.com]
> Sent: Friday
ov
is 1 line per term).
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-----
> From: TGS [mailto:cran.questi...@gmail.com]
> Sent: Friday, August 13, 2010 11:51 AM
> To: Greg
hcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of TGS
> Sent: Friday, August 13, 2010 11:22 AM
> To: David Winsemius
> Cc: r-help@r-project.org
> Subject: Re: [R] Dea
To clarify, I'd like to create a column of indicators for the respective
letters so that I could maybe do regression on indicators, etc.
For instance, "A" gets "1", "B" gets "2", and so on.
On Aug 13, 2010, at 10:19 AM, David Winsemius wrote:
On
# how would I code in R to look at the letter of the alphabet
# in the second column and create a indicator column for the
# corresponding letter?
data(InsectSprays)
InsectSprays$spray
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/li
I downloaded their Academic version and installed it on a Windows virtual
machine (as there is not a Mac version available).
I played around with it a little bit and wasn't overly impressed. I still like
my current configuration: textmate with R bundle on Mac OSX.
With textmate data entry is a
f2(x)
}
plot(x,f1(x), type = "l")
abline(h = -.1)
abline(v = uniroot(f = f3, interval = c(.2, .3))$root, lty = 'dotted')
points(x = uniroot(f = f3, interval = c(.2, .3))$root, y = -.1)
# Thanks David!
On Aug 12, 2010, at 1:33 PM, David Winsemius wrote:
On Aug 12, 2010, at 4:15 P
ee if it will solve this.
On Aug 12, 2010, at 1:00 PM, David Winsemius wrote:
On Aug 12, 2010, at 3:54 PM, TGS wrote:
> Actually I spoke too soon David.
>
> I'm looking for a function that will either tell me which point is the
> intersection so that I'd be able to plot a
y what the horizontal line is, for
instance in the case where y (is-not) 0?
On Aug 12, 2010, at 12:47 PM, David Winsemius wrote:
On Aug 12, 2010, at 3:43 PM, TGS wrote:
> I'd like to plot a point at the intersection of these two curves. Thanks
>
> x <- seq(.2, .3, by = .01)
> f <
Yes, I'm playing around with other things but the "points()" function is what I
was looking for. Thanks
On Aug 12, 2010, at 12:47 PM, David Winsemius wrote:
On Aug 12, 2010, at 3:43 PM, TGS wrote:
> I'd like to plot a point at the intersection of these two curves. Than
I'd like to plot a point at the intersection of these two curves. Thanks
x <- seq(.2, .3, by = .01)
f <- function(x){
x*cos(x)-2*x**2+3*x-1
}
plot(x,f(x), type = "l")
abline(h = 0)
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailm
Yes, please do as Erik said in the future but here's one way to do it.
(A <- matrix(data = rnorm(n = 9, mean = 0, sd = 1), nrow = 3, ncol = 3, byrow =
FALSE, dimnames = NULL))
matrix(rowSums(A))
On Aug 12, 2010, at 11:28 AM, Amit Patel wrote:
Hi
I am trying to calculate the row sums of a matr
I think I understand your question and the following would produce the result
you've posted.
(x <- matrix(c(1, 2, 2, 3, 1, 2, 1, 2, 3, 4), nrow=5, byrow=TRUE))
On Aug 12, 2010, at 5:41 AM, clips10 wrote:
Thanks for the help,
I tried to apply this to a vector with two columns, well I suppose i
the other side are the same with opposite sign.
>
> lo <- seq(0, 4.5, by = 1.5)
> hi <- seq(1.5, 6, by = 1.5)
> roots <- numeric(length(lo))
>
> for(i in seq_along(lo)) roots[i] <- uniroot(f, c(lo[i], hi[i]))$root
> roots
>
> See ?uniroot for other options
How would I numerically find the x value where the derivative of the function
below is zero?
x <- seq(1,2, by = .01)
y <- 5*cos(2*x)-2*x*sin(2*x)
plot(x,abs(y), type = "l", ylab = "|y|")
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman
I want to take this numerical methods course where the text is
http://www.amazon.com/Numerical-Methods-J-Douglas-Faires/dp/0534407617 . The
instructor recommends MATLAB, but states Fortran, C, Mathematica, or Maple will
also do the job.
Will R do the job as well?
If not, where do you think it
Dear R users,
I'm hoping to get a few suggestions about which books are good to follow along
and learn R.
I'm hoping to spend the summer going through a good R book as it is applied in
linear regression.
Thanks!
__
R-help@r-project.org mailing list
h
Is there a reference page indicating which packages or functions are available
in R for the filed of electrical engineering?
I'm not an EE but I've been doing some simulations regarding signals and noise
and I found the 'tuneR' to be useful. Are there any others?
Is there a way to find out what the computation duration time was to complete
executing a code chunk?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guid
20 matches
Mail list logo
