Dear R users,
I was wondering how I can replace the values of a vector with the values from
in another vector in the same row
For example, how can I replace the value of x below with NA when the value of Z
in the same row is NA?
x <-1:20
z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27,
25, 27, 12, 28, 16,17, NA, 12, 10)
Many thanks
Mintewab
Från: Mintewab Bezabih
Skickat: den 15 maj 2012 15:53
Till: r-help@r-project.org
Kopia: r-help@r-project.org
Ämne: missing observations
Dear R users,
I have missing observations in my data that I rem
Dear R users,
I have missing observations in my data that I remove in my analysis. I am able
to run my codes alright but I want the non missing values to be correctly
identified and therefore want to tag my id vector along in my results. Since
the vector of ids has no role in the analysis, I d
Thanks Mike and Micheal for suggestions. It now worked!
Many thanks
Mintewab
Från: Michael Sumner [mdsum...@gmail.com]
Skickat: den 11 maj 2012 01:20
Till: Mintewab Bezabih
Kopia: r-help@r-project.org
Ämne: Re: [R] converting raster image
You should
Dear R users,
I was wondering how I can convert a raster image (that made R through
interpolation) into an ascii or csv format?
this is the last line of my command
p <- interpolate(r, tpsfit)
So p is my raster file which I want to convert into ascii or csv
Many thanks
Regards
Mintewab
Dear R-users,
I am working on interpolating the station level temperature data to farm level
data. I have z vector consisting of station level temperature observations and
my x and y are latitude and longitude corresponding to a farm. My understanding
is I can use raster combined with tps.
Dear R-users,
I am working on interpolating the station level temperature data to farm level
data. I have z vector consisting of station level temperature observations and
my x and y are latitude and longitude corresponding to a farm. My understanding
is I can use raster combined with tps.
Från: R. Michael Weylandt [michael.weyla...@gmail.com]
Skickat: den 15 mars 2012 19:45
Till: Mintewab Bezabih
Kopia: r-help@R-project.org
Ämne: Re: [R] handling missing values
Try adding na.action = na.exclude to your call to gam.
Michael
On Thu, Mar 15, 2012 at 1:00 PM
Dear R users,
I have problems handling missing values. THe problem is that after running my
codes the result I get just skips the missing values. What I want is for the
missing values to appear in my results as well. I have put a workable example
below and as you could see the missing value in
Thanks so much Sarah. Everything worked now!
Mintewab
Från: Sarah Goslee [sarah.gos...@gmail.com]
Skickat: den 13 december 2011 17:36
Till: Mintewab Bezabih
Kopia: r-help@r-project.org
Ämne: Re: [R] shorter way of coding
In exactly the same way:
y.gam
ata=dat)
vis.gam(b)
fitted(b)
Many thanks once again.
Mintewab
Från: Sarah Goslee [sarah.gos...@gmail.com]
Skickat: den 12 december 2011 17:36
Till: Mintewab Bezabih
Kopia: r-help@r-project.org
Ämne: Re: [R] shorter way of coding
That's not a reproducible
Från: Paul Hiemstra [paul.hiems...@knmi.nl]
Skickat: den 12 december 2011 14:42
Till: Mintewab Bezabih
Kopia: r-help@r-project.org
Ämne: Re: [R] shorter way of coding
On 12/12/2011 01:16 PM, Mintewab Bezabih wrote:
> Dear R users,
>
> I am using the code below to generate a fit
Från: Paul Hiemstra [paul.hiems...@knmi.nl]
Skickat: den 12 december 2011 14:42
Till: Mintewab Bezabih
Kopia: r-help@r-project.org
Ämne: Re: [R] shorter way of coding
On 12/12/2011 01:16 PM, Mintewab Bezabih wrote:
> Dear R users,
>
> I am using the code below to generate a fit
Dear R users,
I am using the code below to generate a fitted value of b. I have about 300
different values for for y (y1, y2, ...y300) which means I will have to write
the code below 300 times to generate the 300 different fitted values for y. Is
there a short way of doing that ?
Many thanks
THanks so much Gene,
it worked
mintewab
Från: gley...@gmail.com [gley...@gmail.com] för Gene Leynes
[gleyne...@gmail.com]
Skickat: den 7 december 2011 18:43
Till: Mintewab Bezabih
Kopia: r-help@r-project.org
Ämne: Re: [R] curve fitted ... how to retreive
Dear R users,
I have now managed to fit the curve using the thin plate spline as follows:
library(mgcv)
b <- gam(y~s(x1,x2,k=100),data =dat)
vis.gam(b)
What I want now is to get the fitted data for y and copy it so that I use it
for further analysis.
Many thanks in advance
mintewab
398.00 370.0 768.00
626 277.50 416.0 693.50
627 289.25 416.0 705.25
628 491.00 741.0 1232.00
629 515.00 1136.0 1651.00
Fr?n: R. Michael Weylandt
[michael.weyla...@gmail.com]
Skickat: den 5 december 2011 14:04
Till: Mintewab Bezabih
Kopia: Jeff
__
Från: R. Michael Weylandt
[michael.weyla...@gmail.com]
Skickat: den 5 december 2011 14:04
Till: Mintewab Bezabih
Kopia: Jeff Newmiller; Sarah Goslee; r-help@r-project.org
Ämne: Re: [R] problems using the thin plate spline method
Your data was scrubbed by the server. Use dput() to create a p
ab="x2", zlab="y", xlim=c(0,1), ylim=c(0,1),
zlim=range(zf), ticktype="detailed", scale=F, main="gcv fitting")
Many thanks once again.
regards
mintewab
Från: Jeff Newmiller [jdnew...@dcn.davis.ca.us]
Skickat: den 5 december 2011 12:39
Till: Mintewa
ter that command.
I followed the r tutorial guide to read my data and I am following the r
tutorial to guide me to apply the thin plate spline method.
Regards,
Mintewab
____
Från: Sarah Goslee [sarah.gos...@gmail.com]
Skickat: den 4 december 2011 15:21
Till:
..@dcn.davis.ca.us]
Skickat: den 3 december 2011 17:45
Till: Mintewab Bezabih; r-help@r-project.org
Ämne: Re: [R] problems using the thin plate spline method
I can tell that you are puzzled and confused. Unfortunately, I am not psychic,
so I cannot tell what you did, and therefore cannot tell where y
Dear R users,
I am a beginner in R trying to apply the thin plate spline method to my climate
data. I used the example in R to do so, and the lines seem to run fine ( I am
not getting errors) but I am not getting any output in the form of graph or
anything. I got a warning message saying that
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