Just discovered It doesn't do this when run in the latest release Rcmdr, yet
still does in JGR, RKward and R-Gui.
Confusing.
Thanks,
L.A.
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Thanks for the reply. Here is a sample.
library(R2HTML)
HTMLStart(outdir=Output, file="R2report",
extension="html", echo=FALSE, HTMLframe=TRUE)
HTML.title("Test Report 2011", HR=1)
HTML.title("Test-Title: Classification", HR=3)
HTMLhr()
HTMLStop()
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Hey Guys,
I'm having this same problem! I have searched and can't find anything.
I'm guessing that it must be simple as nobody replied here, but I'm at a
loss, Any help?
L.A.
R-2.13.2
XP 3
Ubuntu 11.10
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25% 50% 75% 90%
52 37255.72 117055.50 149314.00 196207.00 259288.60
Any suggestions?
Thanks,
L.A.
Don't know if this helps:
> str(PARCELS)
'by' int [1:3(1d)] 9053 578 52
- attr(*, "dimnames")=List of 1
..$ Property: chr [1:3] &quo
n="html", echo=FALSE, HTMLframe=TRUE)
HTML(srtype)
HTMLhr()
HTMLStop()
R outputParsalMC
9683.00 578.00 0.95 29.69
I just want to format the R2HTML output to produce this:
R outputParsalMC
9683 578 0.95 29.69
Thanks again to everyone.
L.A.
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ta
as code"?
The actual data is 17000 rows and 31 columns.
L.A.
Par<-by(Dataset[ , "ACCOUNTNO"], Dataset["TYPE"], length)
Sal<-by(Dataset[ , "ratio"], Dataset["TYPE"], length)
PRD<-with(Dataset, by(Dataset[ , "prdb"], TYPE, max))
COD&l
hods to produce this type of report?
Thanks,
L.A.
R version 2.10.0 XP
srtype<-cbind(Par,Sal,Median,COD,PRD,LowerCI,UpperCI)
srtype
Par SalMedian COD PRD LowerCI UpperCI
RES I 9683 578 0.9533 29.69 1.191 0.9382 0.9582
RES V4003 1
I've searched and tried several ideas (na.action. and other things), but I
can't see
to figure this out.
I'm guessing this is so simple I'll feel foolish for asking, but here goes.
Thanks,
L.A.
Dataset$Rcil=with(Dataset, ifelse(Rpr >= .95, Dataset[,"percentchgn
Well, a beginner just learning here, so
>ToYou<-"MERRY CHRISTMAS"
>print(ToYou)
L.A.
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Thanks, but that produces what I think is an estimated interval.
I really want to use the above formula. I just can't figure out how to
get it to run by the LEAID.
It does require 9 observations to produce an interval, but I was showing a
sample.
Thanks again.
L.A.
Matthew Dowle-3
y reading all I can find,
but I often can't seem understand it until I can actually see it in process.
Thanks,
L.A.
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__
2 .2022
7 8300 0.770 .
6 8300 0.830 .0600
Thanks,
L.A.
Ista Zahn wrote:
>
> Hi,
> I think you want
>
> by(TestData[ , "RATIO"], LEAID, median)
>
> -Ista
>
> On Tue, Dec 8, 2009 at 8:36 PM, L.A. wrote:
>>
>> I'
I'm just learning and this is probably very simple, but I'm stuck.
I'm trying to understand the by().
This works.
by(TestData, LEAID, summary)
But, This doesn't.
by(TestData, LEAID, median(RATIO))
ERROR: could not find function "FUN"
HELP!
Thanks,
LA
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