iable.df, file=some.file)
Thanks!
Kavitha
On Sat, Mar 20, 2010 at 5:07 PM, Kavitha Venkatesan
wrote:
> Hi,
>
> I would like to do the following operations:
>
> variable.df is a character string that contains the name of the data
> frame that I want to do the following op
Hi,
I would like to do the following operations:
variable.df is a character string that contains the name of the data
frame that I want to do the following operations on:
variable.df <- data.frame();
# I can do the above command using
assign( variable.df, data.frame() )
How can I perform the as
I just realized my earlier post of my question below was not in
"Plain" Text mode, hence the repeat post...apologies!
Kavitha
On Thu, Oct 22, 2009 at 4:19 PM, Kavitha Venkatesan
wrote:
> Hi all,
>
> I would like to invoke a function that takes multiple arguments (some of
&g
Hi all,
I would like to invoke a function that takes multiple arguments (some of
which are specified columns in the data frame, and others that are
independent of the data frame) on split parts of a data frame, how do I do
this?
For example, let's say I have a data frame
>fitness_data
name heigh
t; > From: r-help-boun...@r-project.org
> > [mailto:r-help-boun...@r-project.org] On Behalf Of hadley wickham
> > Sent: Friday, October 02, 2009 6:07 AM
> > To: jim holtman
> > Cc: r-help@r-project.org; Kavitha Venkatesan
> > Subject: Re: [R] split-apply quest
Hi,
I have a data frame that looks like this:
>x
x1 x2 x3
A 11.5
B 20.9
B 32.7
C 71.8
D 71.3
I want to "group" by the x1 column and in the case of multiple x$x1 values
(e.g., "B")d, return rows that have the smallest values of x2. In the case
of rows with only on
onding x values.
>
> Hope this helps,
>
> --
> Gregory (Greg) L. Snow Ph.D.
> Statistical Data Center
> Intermountain Healthcare
> greg.s...@imail.org
> 801.408.8111
>
>
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
>>
I have some data fit to a smooth.spline object as follows: (x=vector of data
for the predictor variable, y=vector of data for the response variable)
fit <- smooth.spline(x,y)
Now, given a spline fit point y_new, I want to be able to find out what
value of x_new yielded this fit value. How to do s
; mylist<-list(x=1:25, y=runif(n=25))
> plot(mylist, type="n")
> points(mylist, type="p", col=mylist$x)
> Hth,
>
> miltinho
>
>
>
> On Sun, Jun 28, 2009 at 1:03 AM, Kavitha Venkatesan <
> kavitha.venkate...@gmail.com> wrote:
&g
Hi,
I have a set of (x,y) coordinate pairs that are stored as a list
> my_list
$x
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25
$y
[1] -8.0866819 -7.3876052 -6.6849311 -5.9837693 -5.2967432 -4.6525466
[7] -4.0999453 -3.6556190 -3.3076102 -3.0360780 -2.8220465
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