Jim
Yes that is helpful. Everything goes inside the function
Jeff
-Original Message-
From: Jim Lemon
Sent: Wednesday, August 30, 2023 10:54 PM
To: Jeff Reichman
Cc: r-help@r-project.org
Subject: Re: [R] How to create an R input
HI Jeff,
This might give you a start.
add_stuff
R Help
Trying to figure out how to create a simple program that will as the user
from a value input and simply add 5 units to that value then ask the user
for another value and add 45 units to it and on and on. Then how does one
exit the loop of program?
# Create a function called `add_fi
r-help
Trying to install Spark (Windows 11) and R gives me the following error:
spark_install(version = "3.4")
Error in validVersions[with(validVersions, order(hadoop, decreasing =
TRUE)), :
subscript out of bounds
Any idea what the error is telling me. I guess I can load it manua
which seemed to work
I do appreciate your time and assistance.
Jeff
-Original Message-
From: avi.e.gr...@gmail.com
Sent: Monday, June 5, 2023 7:55 PM
To: 'Jeff Reichman' ; r-help@r-project.org
Subject: RE: [R] Adding a numeric class to a data.frame
Jeff,
I wish I could give
Named num [1:6964] 0.001157 0.000927 0.008162 0.001545 0.00092 ...
- attr(*, "names")= chr [1:6964] "1" "2" "3" "5" ...
>
Jeff
-Original Message-
From: avi.e.gr...@gmail.com
Sent: Sunday, June 4, 2023 9:58 PM
To: 'Jeff Reichman
lities and
original dataframe to be one.
-Original Message-
From: avi.e.gr...@gmail.com
Sent: Sunday, June 4, 2023 9:00 PM
To: 'Jeff Reichman' ; r-help@r-project.org
Subject: RE: [R] Adding a numeric class to a data.frame
Jeff R, it would be helpful if your intent was understood.
R-Help Community
How do I add a numeric class to a data .frame.
For example, I have calculated the following probabilities
123
0.0011566127 0.0009267028 0.0081623324
How would I add them back into my data.frame for example
My_df <- data.frame
Yea I can still retrieve it. Just curious if there was something to replace it
as it is quite old.
-Original Message-
From: David Winsemius
Sent: Friday, May 26, 2023 7:46 PM
To: Jeff Reichman
Cc: r-help@r-project.org
Subject: Re: [R] InformationValue package
If it was in CRAN you
R Help
There use to be a package called "InformationValue" which was used to
calculate the optimal probability cutoff for a ROC plot. That package was
archived some time ago and I was wondering if there is another function (in
another package) that would perform the calculation. I can alwa
Ah the zoo package! I was trying with lubridate package.
-Original Message-
From: Rui Barradas
Sent: Tuesday, May 16, 2023 5:04 PM
To: Jeff Reichman ; r-help@r-project.org
Subject: Re: [R] Recombining Mon and Year values
Às 21:29 de 16/05/2023, Jeff Reichman escreveu:
> R H
2021 MarMar-2021
2021 Jan Jan-2021
2021 Apr Apr-2021
So do I need to convert the months back to an integer then recombine to
plot.
Jeff Reichman
[[alternative HTML version deleted]]
__
R-h
, vertex.label.dist = 0.5,
vertex.color = V(g)$color, vertex.label.color="cyan")
On Thu, Oct 27, 2022 at 1:52 AM Jeff Reichman wrote:
>
> Yes Rui that will work for my needs thank you
>
> -Original Message-
> From: Rui Barradas
> Sent: Wednesday, October 2
Yes Rui that will work for my needs thank you
-Original Message-
From: Rui Barradas
Sent: Wednesday, October 26, 2022 4:40 PM
To: reichm...@sbcglobal.net; R-help@r-project.org
Subject: Re: [R] Color Nodes
Às 21:37 de 26/10/2022, Jeff Reichman escreveu:
> R-Help
>
>
>
R-Help
For those of you who use igraph is there a way to highlight (color)
particular notes. For example if I want to color the "Peter" node red and
everything else blue or leave default) how would I do that or can I do
that. Seems as though I might create an attribute column - maybe??
Jef
unt, xout=1:7, method="constant", f=0)
$x
[1] 1 2 3 4 5 6 7
$y
[1] 4 7 7 3 5 5 2
-Bill
On Tue, Mar 29, 2022 at 7:47 PM Jeff Reichman mailto:reichm...@sbcglobal.net> > wrote:
R-help
Is there a R function that will insert missing sequence number(s) and then
fill a missing o
:51 PM
To: reichm...@sbcglobal.net; Jeff Reichman ; 'Tom
Woolman'
Cc: r-help@r-project.org
Subject: Re: [R] Combining data.frames
Then show your code so we can focus on what you haven't yet figured out. Have
you read the examples in the merge help page?
On March 19, 2022 6:
u can also do "SQL-like" joins in the tidyverse with dplyr.
On 2022-03-19 21:23, Jeff Reichman wrote:
> Evening Tom
>
> Yest I've been playing with the merge function. But haven't been able
> to achieve what I need. Could maybe the way to to and it might be my
&g
e", row.names = c(NA, -10L))
Hope this helps,
Rui Barradas
Às 00:56 de 12/01/22, Jeff Reichman escreveu:
> R-Help Forum
>
>
>
> Looking for a little guidance. Have an issue were I'm trying to
> determine the time between when Event A happened(In days) to when
0 0
0
7 0 1
3
8 1 1
0
9 0 0
0
10 0 1 2
Jeff Rei
Breathed in his "Bloom County" comic strip )
On Mon, Nov 8, 2021 at 10:25 AM Jeff Reichman wrote:
>
> R Help Forum
>
>
>
> Anyone know if there are Plotly issues ones need to be aware of. For
> example I quite often receive the following error "Error in
>
R Help Forum
Anyone know if there are Plotly issues ones need to be aware of. For example
I quite often receive the following error "Error in dirname(to) : path too
long." I find there is no one fix. Is there some sort of Windows /Plotly
naming restrictions???
# create a line chart displayi
want to save that connection and close it manually.
creditsub <- read.csv(con <- unz(here::here("Data.zip"), "creditcardsub.csv"))
; close(con)
I hope this helps!
On Sun, Oct 17, 2021 at 4:23 PM Jeff Reichman mailto:reichm...@sbcglobal.net> > wrote:
R-help
I have a R project that contains an R Notebook and I am trying to use the
"here" function to access a file. Before using R projects file I would set
the working dir in a R setup chunk and run the following command (for
example)
creditsub <- read.csv(unz(Data.zip", "creditcardsub.cs
t;The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sat, Sep 18, 2021 at 9:00 AM Jeff Reichman wrote:
>
> Anyone see what I might be doing wrong? Corrupted
Anyone see what I might be doing wrong? Corrupted rds file maybe. The error
would suggest I'm using an older version of R except I'm running both the
latest RStudio and R versions.
# Load in the tidyverse, raster, and sf packages
library(tidyverse)
library(raster)
library(sf)
# Read the climate d
already has a dim attribute of length 2 and dimnames' 2nd
member are the colnames, just coerce to df.
Hope this helps,
Rui Barradas
Às 14:18 de 24/07/21, Jeff Reichman escreveu:
> How does one convert a list into a data frame?
>
>
>
>> str(weight_chains)
>
> Lis
more efficient than dataframe methods, so if you
can work with the matrix without conversion, you'll often find things run a lot
faster.
Duncan Murdoch
On 24/07/2021 9:18 a.m., Jeff Reichman wrote:
> How does one convert a list into a data frame?
>
>
>
>> str(weight_ch
How does one convert a list into a data frame?
> str(weight_chains)
List of 1
$ : 'mcmc' num [1:10, 1:3] -105 -105 -105 -104 -103 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : NULL
.. ..$ : chr [1:3] "a" "b" "s"
..- attr(*, "mcpar")= num [1:3] 1001 101000 1
- attr(*, "class"
(region)
medal_counts_ctry$region <- factor(medal_counts_ctry$region,
levels = levs_medal)
# keep top 50 medal counts
top_count <- 50
medal_data <- medal_counts_ctry %>%
slice_max(order_by = Count, n = top_count)
Hope this helps,
Rui Barradas
is "Bloom County" comic strip )
On Sun, Jun 27, 2021 at 9:10 AM Jeff Reichman mailto:reichm...@sbcglobal.net> > wrote:
R-help Forum
I am attempting to create a stacked bar chart but I have to many categories
The following code works and I end up plotting all 134 countries but r
.. ..$ : int [1:3] 117 118 119
.. ..$ : int [1:3] 194 195 196
.. ..$ : int [1:3] 208 209 210
.. ..$ : int [1:3] 52 53 54
.. ..$ : int [1:3] 147 148 149
.. ..$ : int [1:3] 92 93 94
.. ..$ : int [1:3] 266 267 268
.. ..$ : int [1:3] 232 233 234
.. ..$ : int [1:3] 69 70 71
.. ..$ : int [
] Read fst files
Try using unzip(zipfile, files="desiredFile", exdir=tf<-tempfile()), not
unz(zipfile, "desiredFile"), to copy the desired file from the zip file to a
temporary location and use read_fst(tf) to read the desired file.
-Bill
On Wed, Jun 9, 2021 at
is a binary compressed format using a compression
method that is fast to read, compressing also to zip seems to defeat the
purpose of fst.
HTH,
Jan
On 09-06-2021 15:28, Duncan Murdoch wrote:
> On 09/06/2021 9:12 a.m., Jeff Reichman wrote:
>> Duncan
>>
>> Yea that will w
Re: [R] Read fst files
It looks as though read_fst wants a filename, not a connection.
You should do it in two steps:
unzip("Dataset.zip", files = "myFile.fst")
myObject <- read_fst("myFile.fst")
This is obviously untested; you didn't even say
To: reichm...@sbcglobal.net
Cc: R mailing list
Subject: Re: [R] Read fst files
You are missing the second closing parenthesis. This is what the error message
is telling you.
On Wed, Jun 9, 2021 at 2:44 AM Jeff Reichman mailto:reichm...@sbcglobal.net> > wrote:
R-Help Forum
Anyo
I often use similar code with *.csv files in a zipped folder. For example:
myObject <- read.csv(unz("Dataset.zip", filename = "filename.csv")), which
works just fine.
Jeff Reichman
[[alternative HTML version deleted]]
__
R-help
Never mind I figured out a working solution
- remove duplicate
- mutate a new column == 1
- spread the data from long to wide
- replace NA with 0's
Not sure it’s the most elegant but gets the gob done
-Original Message-
From: R-help On Behalf Of Jeff Reichman
Sent: Thu
R Help Forum
I am attempting to transform the data frame in Table 1 to the form shown in
Table 2. Any suggestions. I�ve started by removing duplicate rows
Jeff
Table 1
Taxon
Importer
Guarouba guarouba
AE
Acipenser gueldenstaedtii
AE
Caiman crocodilus fuscus
AE
Caiman croc
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Mon, Apr 26, 2021 at 11:26 AM Jeff Reichman mailto:reichm...@sbcglobal.net> > wrote:
r-help
Generally speaking is it better to convert date/time val
r-help
Generally speaking is it better to convert date/time values to "POSIXlt" and
"POSIXct" objects?
Jeff Reichman
[[alternative HTML version deleted]]
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> > df1 <- rbind(c(0,0), df)
> > cbind(df1, "diff"=c(0, diff(df1$Score)) )
> ID Score diff
> 1 0 00
> 2 1 88
> 3 2124
> 4 3164
> 5 4204
> 6 5244
> >
>
> HTH, Bill.
>
> W. Michel
many
<http://www.uni-giessen.de/eichner> http://www.uni-giessen.de/eichner
-
Am 24.03.2021 um 17:48 schrieb Jeff Reichman:
> r-help forum
>
>
>
> I'm trying to calculate the diff between two ro
r-help forum
I'm trying to calculate the diff between two rows and them mutate the
difference into a new column. I'm using the diff function but not giving me
what I want.
df <- data.frame(ID=1:5,Score=4*2:6)
What a want where
ID Score diff
1 1 8 8
2 212 4
3
Greg
Based upon you last email I suspect this is what you were looking for.
# create the data.frame
datetime <- c("2021-03-12 05:16:46","2021-03-12 09:17:02","2021-03-12
13:31:43","2021-03-12 22:00:32",
"2021-03-13 09:21:43","2021-03-13 13:51:12","2021-03-13
18:03:13","2021-
Gregory
myDat <- data.frame(datetime = c("2021-03-11 10:00:00","2021-03-11
14:17:00","2021-03-12 05:16:46","2021-03-12 09:17:02",
"2021-03-12 13:31:43","2021-03-12 22:00:32","2021-03-13
09:21:43","2021-03-13 13:51:12",
"2021-03-13 18:03:13","2021-03-13 22:20:28","2021-03-14
0
Kim
See plot.boxcox function which has main = NULL, sub = NULL arguments
Jeff
-Original Message-
From: R-help On Behalf Of DY Kim
Sent: Thursday, March 4, 2021 7:42 AM
To: r-help@r-project.org
Subject: [R] Adding a title to a plot
Greetings!
I am currently using R x64 4.0.4.
I used t
newdata = newd)
#[1] Yes
#Levels: No Yes
Hope this helps,
Rui Barradas
Às 14:42 de 27/02/21, Jeff Reichman escreveu:
> R User Forum
>
> Is there a better way than grabbing individual cell values from a
> model output to make predictions. For example the output from the
> follow
R User Forum
Is there a better way than grabbing individual cell values from a model
output to make predictions. For example the output from the following Naïve
Bayes model
library(e1071)
## Example of using a contingency table:
data(Titanic)
m <- naiveBayes(Survived ~ ., data = Titanic)
m
wi
r-help Forum
While read_csv will unzip and read a *.zip file will it read multiply files
in a *.zip file. For example
object <- read_csv(unz(description = "fileName.zip", filename =
"fiename1.csv")) where filename.zip contains two file fileName1.csv and
fileName2.csv (note this line of cod
t's not in yours) you
can add it temporarily using
Sys.setenv(PATH = paste(Sys.getenv("PATH"),
"gold/home/ndw003/reichmjs/MyDocs/R/rtools40/usr/bin", sep = ";"))
For a permanent addition you need to edit the system PATH setting. You should
probably ask an ad
not currently
installed.
Please download and install Rtools 4.0 from
https://cran.r-project.org/bin/windows/Rtools/.
I am assuming R isn't seeing Rtools
So can I run Rtools from the same profile location as R and RStudio? IF so
what do I need to do?
Jeff Re
characters and strip the right characters into their own
variables using one of the methods that can do that. Then pass it using
something like paste(left, "-", right).
On Tue, Nov 17, 2020, 2:43 PM Jeff Reichman mailto:reichm...@sbcglobal.net> > wrote:
R-Help
How does one
Boris
Yes in that case it works as you have assigned a character string to key. My
problem is I'm taking a string input from a shiny app and when I run the
function it only sees . How to assign - to a character string.
Jeff
-Original Message-
From: Boris Steipe
Sent: Tuesda
R-Help
How does one pass a character string containing a hyphen? I have a function
that accesses an api if I hard code the object, for example
key_key <- "-"
it works but when I pass the key code to the function (say something like
key_code <- code_input) it returns only
r-help Forum
Has anyone worked with puling ACLED (https://acleddata.com/#/dashboard) via
the ACLED API and R?
Jeff Reichman
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https
was generated.
% R CMD Rscript -e 'library(dplyr,warn.conflicts=FALSE);
data.frame(X=1:3,Y=c(11,13,17)) %>% summarize_all(list(sum=sum,prod=prod))'
X_sum Y_sum X_prod Y_prod
1 641 6 2431
On Thu, Oct 1, 2020 at 10:29 AM Jeff Reichman mailto:reichm...@sbcglobal.net>
ise(across(everything(), sum))
mtcars %>%
summarise_all(sum) # no need for `funs()`
Hope this helps,
Rui Barradas
Às 18:29 de 01/10/20, Jeff Reichman escreveu:
> r-help Forum
>
>
>
> I'm using the dplyr:: summarize_all(funs(sum)) function and am
> receiving a w
r-help Forum
I'm using the dplyr:: summarize_all(funs(sum)) function and am receiving a
warning message that the `funs()` is deprecated as of dplyr 0.8.0. Ok what
should I be using to summarize all columns by sum?
Jeff
[[alternative HTML version deleted]]
___
oks
https://bookdown.org/yihui/rmarkdown-cookbook/animation.html
On 9/18/20 8:26 AM, Jeff Reichman wrote:
> r-help forum
>
>
>
> Has anyone created an animations within a R-Notebook. I'm trying to
> create an animation within a R -Notebook and while my code works
> outside of a
t;./gganim_plot0001.png" "./gganim_plot0002.png"
"./gganim_plot0003.png" "./gganim_plot0004.png"
[5] "./gganim_plot0005.png" "./gganim_plot0006.png"
"./gganim_plot0007.png" "./gganim_plot0008.png"
[9] "./gganim_plo
/2010 2:30", "1/5/2010 10:32", "1/5/2010 12:03")
seq <- c(1,2,3)
dat <- data.frame(dtg, seq)
dat$dtg <- as.POSIXlt(dat$dtg, format = "%m/%d/%Y %H:%M")
dat.xts <- xts(x = dat[,-1], order.by = dat[,1])
head(dat.xts)
R-Help Forum
Starting to work with xts objects but can't figure out what I'm doing wrong
when converting *.csv file with a dtg variable to a *.xts object. When I'm
converting to an appropriate time object all I get are NA, so that's my
first issue.
dtg <- c("1/5/2010 2:30", "1/5/2010 10:32"
;,
Ytitle = "Cases")
return(i)
}
# create individual plots
atg <- plots("Antigua and Barbuda") # Antigua and Barbuda
arg <- plots("Argentina")# Argentina
brb <- plots("Barbados") # Barbados
blz <
So I am at a loss to figure out my error when the example gives me the same
error.
Sincerely
Jeff Reichman
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A B
A B C
A C B
A C B
A B C
A C C
Results
A,A,B 0.30
A,B,C 0.30
A,A,D0.10
A,C,B 0.20 etc
Sincerely
Jeff
Jeff Reichman would like to recall the message, "facets".
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PLEASE do read the posting guide http://www.R-project.org/posting-guid
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible cod
On 11/03/2020 7:46 a.m., Jeff Reichman wrote:
> R-Help
>
>
>
> Recently I've started receiving the following message when updating
> packages
> - "Do you want to install from sources the packages which need compilation."
> I generally click "
Why?
RStudio version: 1.2.5033
R version: 3.6.3
Sincerely
Jeff Reichman
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P
uot;The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Wed, Feb 19, 2020 at 7:14 PM Jeff Reichman mailto:reichm...@sbcglobal.net> > wrote:
R-Help
R-Help Forum
Anyone ever perform supply chain optimization, operations optimization or
sales optimization in R? If so what packages should I look to?
Sincerely
Jeff Reichman
(314) 457-1966
[[alternative HTML version deleted
nge <- seq(min(d), max(d), by = 1)
date_range[!date_range %in% d]
Sincerely
Jeff Reichman
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EMP-NORMAL",
startdate = start_date, enddate = end_date, limit=500)
data <- weather_data$data
data$year <- year(data$date)
data$month <- month(data$date)
data$day <- day(data$date)
# summarize to average daily temps
aggregate(value ~ year + mo
pattern A - 1 - aa occurs twice, and A - 2 - bb occurs once.
Presently I'm simply concatenating the columns and performing a group by,
and count. Which works but wonder if there were any packages that would
perform such (and maybe other) analytics.
Sincerely
Jeff Reichman
(314) 457
Eric
I will have to give that a try. Thanks.
For a "it works" method I used
start_time <- Sys.time()
insert code of interest
end_time <- Sys.time()
end_time - start_time
-Original Message-
From: R-help On Behalf Of Eric Berger
Sent: Wednesday, November 20, 2019 9:58 AM
R- Help
Is there a command or way to obtain the time it took R to execute a command?
Sincerely
Jeff Reichman
(314) 457-1966
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data.frame R errors out. I'm assuming
> it is because of the list(s). Don't know what to do with it (the
> list). I need the "favoriteValue (s)."
>
> Ultimate I want to run the arules package
>
> Jeff Reichman
>
> ___
RUE)[1:10]
## the 10 biggest
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sun, Oct 14, 2018 at 7:13 PM J
David L Carlson
Anthropology Department
Texas A&M University
_
From: R-help mailto:r-help-boun...@r-project.org> > on behalf of Jeff Reichman
Sent: Sunday, October 14, 2018 8:45:17 PM
To: r-help@r-project.org <mailto:r-help@r-project.org>
Subject: [R] Sc
R-Help Forum
I'm using the following code to reorder (from highest to lowest) my miRNA
counts. But there are 500 plus and I only need the first (say) 15-20. How
do I limit ggplot to only the first 20 miRNA counts
ggplot(data = corr.m, aes(x = reorder(miRNA, -value), y = value, fill =
variable))
R Forum
Is there a way to tell R to not import numbers as scientific notation
(read.csv). So that 1619052826499 will not be imported as 1.619053e+12.
Jeff Reichman
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https
pade1
f8c30bb5148.out': No such file or directory
>
> cspade> as(s1, "data.frame")
Error in .class1(object) : object 's1' not found
But if I run in R (alone) it works just fine. Any idea why I can' t seem to
run in RStudio or what I might have to do in RStudio?
ure my csv file?
A web example or RPubs link?
For example
Seq_1 {E,B}, {C}, {T}
Seq_2 (E,M}, {C}, {B,E,V,T}
Seq_3 {E},{C},{T}
Jeff Reichman
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ure my csv file?
A web example or RPubs link?
Jeff Reichman
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
a
control = list(verbose=F))
rules.sorted <- sort(rules, by="lift")
inspect(rules.sorted)
-Original Message-
From: R-help On Behalf Of Jeff Reichman
Sent: Sunday, September 23, 2018 5:18 PM
To: r-help@r-project.org
Subject: [R] Consequent sorting
r-help Forum
I'm using t
Bread} 0.1428571 1.000
1.167 1
Jeff Reichman
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PLEASE do read the pos
r-help
Is there a r-package that will construct a frequent-pattern (FP) tree ?
Jeff Reichman
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https://stat.ethz.ch/mailman
) +
geom_smooth(aes(group = launchOrDelivery, color= launchOrDelivery), se =
FALSE) +
xlab("timeline") +
ylab("Launches/Deliveries") +
ggtitle("Scatterplot of Launches vs. Deliveries")
On Thu, Aug 23, 2018 at 9:39 PM Jeff Reichman mailto:reichm...@sbcglobal.net
R-help
I want to add two smooth lines (geom_smooth()) for each scatter plot. How
do I do that?
ggplot() +
geom_point(data=data, aes(x=timeline, y=deliveries), color="blue") +
geom_point(data=data, aes(x=timeline, y=launches), color="red") +
xlab("Deliveries") +
ylab("Launches")
Please disregard I simply added a highlight variable and added
scale_fill_manual(values = c("Yes"="red", "No"="grey"))
-Original Message-
From: R-help On Behalf Of Jeff Reichman
Sent: Tuesday, August 21, 2018 8:44 PM
To: r-help@r-projec
R-Help Forum
While the following code works fine I need to change (highlight) specific
"bars" within plot 2 (p2). For example I want the bars to be (lets say)
red, on 1 Aug 2016 and 1 Aug 2017 . What do I need to do?
library(ggplot2)
library(reshape2)
library(scales)
library(egg)
#dat
: reichm...@sbcglobal.net
Cc: r-help@r-project.org
Subject: Re: [R] Converting chr to num
Hey there,
as.numeric(gsub(pattern = "%","","12.6%"))
On Sat, Aug 18, 2018 at 4:20 PM, Jeff Reichman mailto:reichm...@sbcglobal.net> > wrote:
R-Help Forum
How do
R-Help Forum
How do I convert a chr variable that contains percentages to an integer
Example 12.6% (chr) to 12.6 (int)
Jeff
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ht
28, 2018 7:57 PM
To: reichm...@sbcglobal.net; R-help@r-project.org
Subject: Re: [R] Plot Rect Transparency
On 28/06/2018 5:29 PM, Jeff Reichman wrote:
> R-Help
>
>
>
> Is there a way to make a rectangle transparent (alpha=0.1??)
>
>
>
>plot(c(100, 200), c(3
R-Help
Is there a way to make a rectangle transparent (alpha=0.1??)
plot(c(100, 200), c(300, 450), type= "n", xlab = "", ylab = "")
rect(110, 300, 175, 350, density = 5, border = "red")
Can't figure out how to take the changepoint function results and plot in
ggplot2 so I can just
R-help
Does R have a package or function that will convert Gregorian to Hijri
(Islamic) dates (time series)?
Jeff
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variables with the
smaller magnitudes.
David L. Carlson
Department of Anthropology
Texas A&M University
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Jeff
Reichman
Sent: Thursday, June 21, 2018 11:36 AM
To: R-help@r-project.org
Subject: [R] KNN
R-
R-Help
Does one need to normalize ones data is using the knn function within the
caret Library.
Jeff
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Marc
Thank you - that will save me some time.
Jeff
-Original Message-
From: Marc Schwartz
Sent: Thursday, June 14, 2018 4:07 PM
To: JEFFERY REICHMAN
Cc: R-help
Subject: Re: [R] Kendall tau a, b, or c
> On Jun 14, 2018, at 4:04 PM, JEFFERY REICHMAN
wrote:
>
> r-help Forum
>
> Is
Well that’s easy enough - thank you
-Original Message-
From: Jim Lemon
Sent: Monday, June 11, 2018 11:50 PM
To: Jeff Reichman
Cc: r-help mailing list
Subject: Re: [R] Changing selected columns to factor
Hi Jeff,
jrdf<-data.frame(A=rnorm(10),B=rnorm(10),C=rnorm(10),
D=rnorm(10
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