Anna wrote:
Hi all,
I need to calculate a row median for every three columns of a
dataframe. I made it work using the following script, but not happy
with the script. Is there a simpler way for doing this?
To which Jim L responded:
Hi Anna,
I can't think of a simple way, but this fun
swizz-john wrote:
> Hi people,
>
> my task is to analyse data that is formatted like this.
>
>
date,bid,name,w1,w2,w3,m1,m2,m3,m4,m5,m6,m7,m8,m9,m10,m11,m12,debt2mkt,cds,equity
> 28jul2009,1,"ABN Amro",56.5,
> 29jul2009,1,"ABN Amro",56.5,
> 30jul2009,1,"ABN Amro",
Homework? The list has a no homework policy - but perhaps I'll be forgiven por
posting hints.
In general terms, this is how I appraoched the problem:
* Loop through the rows of stop_onoff - for (idx in ...someething...) {...
* For each row, find the first of "ref" in a suitably filtered subset of
s
On Fri, 29 Aug 2014 06:33:01 -0700 Jeff Newmiller
wrote
> One clue is the help file for "$"...
>
> ?" $"
>
> In particular there see the discussion of character indices and the "exact"
> argument.
>
<...snip...>
>
> On August 29, 2014 1:53:47 AM PDT, Angel Rodriguez
> wrote: >
> >Dear subsc
You could also try matplot(data_object[, 1], data_object[, -1], ...)
?matplot
Cheers.
On Thu, 21 Aug 2014 09:55:29 +1000 "Duncan Mackay"
wrote
> Hi
>
> Try something like (as you have not given a reproducible example)
>
> library(lattice)
>
> xyplot(y1 + y2+ y3 ... ~ x, data = your data.fram
On Tue, 5 Aug 2014 09:51:56 +0300 Lingyi Ma wrote
> My dataset:
>
> Item_IdYear_Month
> B65623262 201204
> B58279745 201204
> B33671102 201204
> B36630946 201204
> B63270151 201204
> B63270133 201204
>
>
>
> I have written my code to calculate one more c
I don't know about better or more elegant - but see inserts below...
Cheers.
On Fri, 25 Jul 2014 22:22:56 +1000 "Luke Hartigan"
wrote
> Dear all,
>
> I have an R function which returns a list of variables; however, within the
> body of the function I would like to incorporate a branch based on
On Tue, 6 May 2014 10:12:50 +0100 Dr Eberhard Lisse wrote
> Jeff
>
> It's in MySQL, at the moment roughly 1.8 GB, if I pull it into a
> dataframe it saves to 180MB. I work from the dataframe.
>
> But, it's not only a size issue it's also a speed issue and hence I
> don't care what I am going to
On Tue, 6 May 2014 09:07:55 + Babak Bastan wrote
> Hi experts
>
> I woul like to change my x-axis. Like this: 10,...,2,...,1
>
> I am using this code:
>
> r<-c(1:10)
> plot(r, axes=FALSE, frame.plot=TRUE,xlim=c(10,1))
> axis(1,at=10/seq(1:10))
> axis(2, at=axTicks(2), axTicks(2))
>
> but
On Sun, 13 Apr 2014 05:01:40 -0700 (PDT) "andre.zacha...@gmail.com"
wrote
> Thank you very much!!
>
..
..
> *De :* arun kirshna [via R]
> *Envoyé :* 13 avril 2014 11:23
> *À :* andre.zacha...@gmail.com
> *Objet :* Re: mean calculations from a dframe column
>
> Hi André,
>
> Your codes wer
I _do_ see this error - on R 3.0.3 / Win XP
however, not on R 2.11.1 / Linux.
(Same hardware, 2 x OS, 2 x R versions)
Maybe it's peculiar to to 'doze...
datetimesequenz <- seq.POSIXt(from=as.POSIXct("1960-01-01 00:00"),
to=as.POSIXct("2100-01-01 00:00"), by="1 hour")
levels(as.factor(strftime(dat
On Mon, 17 Mar 2014 15:18:50 -0700 Jinsong Zhao wrote
> Hi there,
>
> I hope to rotate the Y label of axis(4) with -90 degree. I can typeset
> the Y label using text() with srt = -90. However, I cannot get the
> coordinate of the position that mtext() used.
>
<...cut...>
locator(1) # Works
On Mon, 10 Mar 2014 18:26:38 + William Dunlap wrote
> You probably want to read the Introduction to R that comes with R
> (menu: Help>Manuals (in PDF)>Introduction to R).
>
>
When I first started using R I found it easier to work through some of the
contributed documentation. Have a look at
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