Dear R experts,
I have the following data.table:
dt<- data.table(A=rep(1:5), B=c(20:24), C=rep(30:34), target.name=c("A","B",
"C","B","A"), target.column=c(1,2,3,2,1), target.value=rep(NA,5))
Columns A, B and C are the variables of interest.
For each row, I want to get the value of the variable
Dear R experts,
I want to use numerical methods to solve a complex problem. Here is a very
simple example that gives an idea of what I would like to do. This example
could be solved by hand, but I am interested in finding a numerical
solution in R.
Let's say that I have the following equation:
Dear R experts,
I am trying to find all the solutions of an equation. Here is an example:
integrand1<- function(x){1/x*dnorm(x)}
integrand2<- function(x){1/(2*x-50)*dnorm(x)}
integrand3<- function(x,C){
cd<- 1/(x+C)
return(cd)
}
res<- function(C){
ce<-integrate(integrand1, lower=1, upper=
Dear R experts,
I am computing the following integral.
[image: \int_{1,100} \frac{1}{x+Max(x-50,0)} g(x)dx], where g is the
density of the standard normal, and [1,100] is the domain.
1) I use the following code which works fine:
integrand1<- function(x){1/x*dnorm(x)}
integrand2<- function(x){1/(2
of max(x-50,0), which returns a scalar.
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
> > -Original Message-
> > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf
> > Of Aurélien Philippot
>
Dear R experts,
I computed the same integral in two different ways, and find different
values in R.
The difference is due to the max function that is part of the integrand. In
the first case, I keep it as such, in the second case, I split it in two
depending on the values of the variable of integra
put function changes sign?
2013/12/17 David Winsemius
>
> On Dec 17, 2013, at 8:53 AM, Aurélien Philippot wrote:
>
> > Dear R experts,
> >
> > I am trying to find numerical solutions for an integral equation.
> >
> >
> > Here is an example:
&
Dear R experts,
I am trying to find numerical solutions for an integral equation.
Here is an example:
I started by defining the integrand, as a function of x and C, where x is
the variable of integration and C is the parameter I am interested in:
integrand<- function(C,x){-((10*x)^(-1)-(1
thanks for your suggestions, which work.
In addition, I updated Rstudio to the latest version and my old code works
again.
Best,
Aurelien
2012/3/14 Petr Savicky
> On Wed, Mar 14, 2012 at 03:07:19PM -0700, Aurélien PHILIPPOT wrote:
> > Dear R experts,
> > I have a dataframe impo
Dear R experts,
I have a dataframe imported from a csv file (with read.csv).
Here is an example:
mm<- c("19860228", "19860331","19860430","19860531")
id<-c("1","1","1","1")
re<- c("C","0.25", "0.98", "1.34")
mret<-data.frame(mm, id, re)
mret<-as.numeric(as.character(mret
> Would this go outside or inside the "center" block?
>
>> > \begin{sidewaystable}[ht]
>> >
>> > \begin{center}
>> >
>> > \begin{tabular}{ccc}
>
> Secondly, what combination of arguments is giving you LaTeX w
> \end{sidewaystable}
>
> Alternatively, since the size of the table is determined by the size of the
> text in the table, you can just tell LaTeX to use a smaller font, e.g.
>
> <>=
> print(outfile, include.rownames=F, floating.environment='sidewaystable',
> s
Dear R users,
I am new to Latex and I am using the R package xtable to generate tables.
I want to produce a table that is very long. in the landscape format, but
I would need to rescale the table so that it fits in the page. xtable
enables me to have the landscape format, but I cannot rescale it,
ornia, USA
> http://www.fws.gov/redbluff/rbdd_jsmp.aspx
>
> *From:* Aurélien PHILIPPOT
> *To:* R-help@r-project.org
> *Sent:* Sunday, December 4, 2011 12:32 PM
> *Subject:* [R] Group several variables and apply a function to the group
>
> Dear R-experts,
> I am struggli
Dear R-experts,
I am struggling with the following problem, and I am looking for advice
from more experienced R-users: I have a data frame with 2 identifying
variables (comn and mi), and an output variable (x). comn is a variable for
a company and mi is a variable for a month.
comn<-c("abc", "abc"
thanks Michael.
I played with your suggestion to get the output in the format I wanted, and
I found the following that works fine:
sub<-d[, which(colnames(d) %in% v) ]
Aurelien
2011/12/2 R. Michael Weylandt <
michael.weyla...@gmail.com>
> How about this?
>
> d[, v[v %in% colnames(d)]]
>
> Mich
I know there is at least one match
between the 2.
Initially, I tried something in the spirit:
sub<- subset(d, colnames(d) %in% v)
but I could not make it work properly.
Best,
Aurelien
2011/12/2 Paul Hiemstra
> On 12/02/2011 07:20 AM, Aurélien PHILIPPOT wrote:
> > Dear R-users,
&
Dear R-users,
-I am new to R, and I am struggling with the following problem.
-I am repeating the following operations hundreds of times, within a loop:
I want to subset a data frame by columns. I am interested in the columns
names that are given by the rows of another data frame that was built i
Dear all,
I am new in R and I have been faced with the following problem, that slows
me down a lot. I am short of ideas to circumvent it. So, any help would be
highly appreciated:
I have 2 dataframes x and y. x is very big (70 million observations),
whereas y is smaller (30 observations).
Al
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