[R] Text search

2020-01-25 Thread Ashta
Hi all, >From one of the columns of the data frame I want to search and extract a text that contains Tall or Short and create new column that should contain these texts in a corresponding row. My example data and the desired output are shown below dat<-read.table(text="obs Year char 1 2001 T

Re: [R] remove a row

2019-11-28 Thread Ashta
ng along and > sticking things into it." > -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) > > > On Thu, Nov 28, 2019 at 3:17 PM Ashta wrote: >> >> Hi all, I want to remove a row based on a condition in one of the >> variables f

[R] remove a row

2019-11-28 Thread Ashta
Hi all, I want to remove a row based on a condition in one of the variables from a data frame. When we split this string it should be composed of 3-2- 5 format (3 digits numeric, 2 characters and 5 digits numeric). Like area code -region-numeric. The max length of the area code should be 3, the

Re: [R] Remove

2017-12-09 Thread Ashta
M$x >= GRmin[DM$GR] & DM$x <= GRmax[DM$GR], ] >GR x y > 1 A 25 125 > 2 A 23 135 > 5 B 45 321 > 6 B 47 512 > 9 C 61 521 > 10 C 68 235 > > > > > Bill Dunlap > TIBCO Software > wdunlap tibco.com > > On Sat, Dec 9, 2017

Re: [R] Remove

2017-12-08 Thread Ashta
will be A 25 125 A 23 135 B 45 321 B 47 512 C 61 521 C 68 235 Thank you On Wed, Dec 6, 2017 at 10:34 PM, David Winsemius wrote: > >> On Dec 6, 2017, at 4:27 PM, Ashta wrote: >> >> Thank you Ista! Worked fine. > > Here's another (possibly more direct in its

Re: [R] Remove

2017-12-06 Thread Ashta
Thank you Ista! Worked fine. On Wed, Dec 6, 2017 at 5:59 PM, Ista Zahn wrote: > Hi Ashta, > > There are many ways to do it. Here is one: > > vars <- sapply(split(DM$x, DM$GR), var) > DM[DM$GR %in% names(vars[vars > 0]), ] > > Best > Ista > > On Wed, Dec 6,

Re: [R] Remove

2017-12-06 Thread Ashta
( DM, "B" != x ) > > This is covered in the Introduction to R document that comes with R. > -- > Sent from my phone. Please excuse my brevity. > > On December 6, 2017 3:21:12 PM PST, David Winsemius > wrote: >> >>> On Dec 6, 2017, at 3:15 PM, Ashta wrote: &g

Re: [R] Remove

2017-12-06 Thread Ashta
Thank you David. This will not work. Tthis removes only duplicate records. DM[ !duplicated(DM$x) , ] My goal is to remove the group if all elements of x in that group have the same value. On Wed, Dec 6, 2017 at 5:21 PM, David Winsemius wrote: > >> On Dec 6, 2017, at 3:15 PM, Ash

[R] Remove

2017-12-06 Thread Ashta
Hi all, In a data set I have group(GR) and two variables x and y. I want to remove a group that have the same record for the x variable in each row. DM <- read.table( text='GR x y A 25 125 A 23 135 A 14 145 A 12 230 B 25 321 B 25 512 B 25 123 B 25 451 C 11 521 C 14 235 C 15 258 C 10 654',heade

Re: [R] reading data

2017-06-14 Thread Ashta
; '.txt' to your email to help with the problem. Also you did not state what > the differences that you are seeing. So help us out here. > > > Jim Holtman > Data Munger Guru > > What is the problem that you are trying to solve? > Tell me what you want to do, not

[R] reading data

2017-06-13 Thread Ashta
Hi all, I am using R to extract data on a regular basis. However, sometimes using the same script and the same data I am getting different observation. The library I am using and how I am reading it is as follows. library(stringr) namelist <- file("Adress1.txt",encoding="ISO-8859-1") Name <- re

Re: [R] Non date value

2017-04-15 Thread Ashta
Jeff, I am sorry for that. On Sat, Apr 15, 2017 at 12:04 AM, Jeff Newmiller wrote: > You don't follow instructions very well. Read the Posting Guide more > carefully. > -- > Sent from my phone. Please excuse my brevity. > > On April 14, 2017 9:39:30 PM PDT, Ashta wrote

Re: [R] Non date value

2017-04-14 Thread Ashta
It is not a data frame. > > -- Bert > > > > > On Fri, Apr 14, 2017 at 9:02 PM, Ashta wrote: >> Hi all, >> I am reading a field data that contains several variables. The sample >> of the data with the first two variables is shown below. I wanted to >&

[R] Non date value

2017-04-14 Thread Ashta
Hi all, I am reading a field data that contains several variables. The sample of the data with the first two variables is shown below. I wanted to know the minimum and maximum recording date However, I have some problem. Name Rdate V1 to V20 Alex101/03/2015 Alex201/03/2014

[R] combine

2017-03-25 Thread Ashta
Hi all, I have more than two files and merge by a single column and preserve the other columns. Here is an example of two files dat1 <- read.table(header=TRUE, text=' ID T1 T2 ID1125245 ID2141264 ID3133281') dat2 <- read.table(header=TRUE, text=' ID G1 G2 ID225 46

Re: [R] find and

2017-03-18 Thread Ashta
H > Ulrik > > > On Sat, 18 Mar 2017 at 15:17 Rui Barradas wrote: >> >> Hello, >> >> I believe this does it. >> >> >> sp <- split(DF4, DF4$city) >> want <- do.call(rbind, lapply(sp, function(x) >> if(length(unique

[R] find and

2017-03-18 Thread Ashta
Hi all, I am trying to find a city that do not have the same "var" value. Within city the var should be the same otherwise exclude the city from the final data set. Here is my sample data and my attempt. City1 and city4 should be excluded. DF4 <- read.table(header=TRUE, text=' city wk var city1

Re: [R] Repeat

2017-02-25 Thread Ashta
replacement has length zero On Sat, Feb 25, 2017 at 5:43 PM, David Winsemius wrote: > >> On Feb 25, 2017, at 10:45 AM, Ashta wrote: >> >> Thank you David. >> is it not possible to sort it by year and flag so that we can make '-' >> in the second row ? li

Re: [R] Repeat

2017-02-25 Thread Ashta
Thank you David. is it not possible to sort it by year and flag so that we can make '-' in the second row ? like this for that particular year. 2003 2 Z 2003 1 - On Sat, Feb 25, 2017 at 12:14 PM, David Winsemius wrote: > >> On Feb 25, 2017, at 8:09 AM, As

[R] Repeat

2017-02-25 Thread Ashta
I have a data set and I want to repeat a column value based on other column value, my data look like read.table(text = "Year month flag 2001 1 Z 2001 2 - 2001 4 X 2002 1 Z 2002 2 - 2003 1 - 2003 2 Z 2004 2 Z 2005 3 Z 2005 2 - 2005 3 -", header = TRUE) Within year If flag

[R] read

2016-11-28 Thread Ashta
Hi all, I have a script that reads a file (dat.csv) from several folders. However, in some folders the file name is (dat) with out csv and in other folders it is dat.csv. The format of data is the same(only the file name differs with and without "csv". Is it possible to read these files dep

Re: [R] difference

2016-10-28 Thread Ashta
gt; 1 2001 250 > 2 2001 75 50 > 3 2001 150 125 > 4 2002 300 > 5 2002 85 55 > 6 2002 95 65 > > > Philip > > > On 28/10/2016 3:20 PM, Ashta wrote: >> >> Hi all, >> >> I want to calculate the difference between successive ro

[R] difference

2016-10-27 Thread Ashta
Hi all, I want to calculate the difference between successive row values to the first row value within year. How do I get that? Here isthe sample of data Year Num 200125 200175 2001 150 200230 200285 200295 Desired output Year Num diff 200125 0 2001

[R] Subset and sumerize

2016-10-14 Thread Ashta
Hi all, I am trying to summarize big data set by selecting a row conditionally. and tried to do it in a loop Here is the sample of my data and my attempt dat<-read.table(text=" ID,x1,x2,y 1,a,b,15 1,x,z,21 1,x,b,16 1,x,k,25 2,d,z,31 2,x,z,28 2,g,t,41 3,h,e,32 3,x,z,38 3,x,g,45 ",sep=",",he

Re: [R] create variable

2016-10-12 Thread Ashta
point me the problem. Thank you in advance On Sun, Oct 9, 2016 at 11:16 AM, David Winsemius wrote: > >> On Oct 9, 2016, at 7:56 AM, Ashta wrote: >> >> I am trying to query data from Hive service and create a variable. >> >> >> dbGetQuery(hivecon,"sel

Re: [R] create variable

2016-10-09 Thread Ashta
Thank you so much David! Your suggestions worked for me. On Sun, Oct 9, 2016 at 11:16 AM, David Winsemius wrote: > >> On Oct 9, 2016, at 7:56 AM, Ashta wrote: >> >> I am trying to query data from Hive service and create a variable. >> >> >> dbGet

[R] create variable

2016-10-09 Thread Ashta
I am trying to query data from Hive service and create a variable. dbGetQuery(hivecon,"select date1, date2 from dateTable limit 10") date1, date2, Diif 4/5/1999, 6/14/2000 7/2/1999, 6/26/2000 8/14/1999, 8/19/2000 11/10/1999, 9/18/2000 8/25/2000, 6/5/2001 3/14/2012, 3/15/2004 Here is what I

Re: [R] Matrix

2016-07-16 Thread Ashta
t; > On 07/17/2016 01:39 AM, Duncan Murdoch wrote: >> >> On 16/07/2016 6:25 PM, Ashta wrote: >> > Hi all, >> > >> > I have a large square matrix (60 x 60) and found it hard to >> > visualize. Is it possible to change it as shown below? >>

[R] Matrix

2016-07-16 Thread Ashta
Hi all, I have a large square matrix (60 x 60) and found it hard to visualize. Is it possible to change it as shown below? Sample example (3 x 3) A B C A 3 4 5 B 4 7 8 C 5 8 9 Desired output A A 3 A B 4 A C 5 B B 7 B C 8 C C 9 Thank you in advance __

Re: [R] not common records

2016-06-03 Thread Ashta
Thank you Jeff. Solved. On Fri, Jun 3, 2016 at 12:47 AM, Jeff Newmiller wrote: > ?merge > > Pay attention to the all-whatever parameters. > -- > Sent from my phone. Please excuse my brevity. > > On June 2, 2016 7:04:47 PM PDT, Ashta wrote: >> >> I have 2

[R] not common records

2016-06-02 Thread Ashta
I have 2 data sets. File1 and File2. Some records are common to both data sets. For those common records I want get the difference between d_x1z1= z1-x1 and d_x2z2= z2-x2. File1<- data.frame(var = c(561,752,800,900), x1= c(23,35,40,15), x2= c(125,284,280,347)) File2<- data.frame(var = c(561,75

Re: [R] month and output

2016-05-07 Thread Ashta
Thank you David! On Sat, May 7, 2016 at 12:18 AM, David Winsemius wrote: > >> On May 6, 2016, at 5:15 PM, Ashta wrote: >> >> Thank you very much David. >> >> So there is no general formal that works year all round. >> >> The first one work onl

Re: [R] month and output

2016-05-06 Thread Ashta
) ) nextmo Many thanks On Fri, May 6, 2016 at 6:40 PM, David Winsemius wrote: > >> On May 6, 2016, at 4:30 PM, David Winsemius wrote: >> >> >>> On May 6, 2016, at 4:11 PM, Ashta wrote: >>> >>> Hi all, >>> >>> I am trying to ge get

[R] month and output

2016-05-06 Thread Ashta
Hi all, I am trying to ge get the next month of the year. today <- Sys.Date() xx<- format(today, format="%B%Y") I got "May2016", but I want Jun2016. How do I do that? My other question is that, I read a data and do some analysis and I want to send all the results of the analysis to a pdf f

Re: [R] flag a record

2016-02-28 Thread Ashta
Thank you very much Jim! It is working fine!! On Sun, Feb 28, 2016 at 1:46 AM, Jim Lemon wrote: > Hi Ashta, > This does not seem too difficult: > > DF$flag<-"n" > for(thisname in unique(DF$Name)) { > if(any(DF$year[DF$Name == thisname] %in% c(2014,2015) &

[R] flag a record

2016-02-27 Thread Ashta
Hi all, I have a data set represented by the following sample. I want flag records of an individual as "N", if if the tag column of an individual is equal to zero for the last two years. So in the following example, Alex1 records are flagged as "y", On the other hand Carla's records are fla

[R] Matrix summary

2016-02-12 Thread Ashta
hi all, I have a square matrix (1000 by 1000), 1. I want calculate mean, min and max values for each column and row. 2, I want pick the coordinate value of the matrix that has the max and min value for each row and column. This an example 4 by 4 square matrix

[R] LDheatmap

2016-02-03 Thread Ashta
Hi all, I am looking for an R package that calculates a pair wise LD (linkage disequilibrium) I came up with library(LDheatmap). has any one used this library? I would appreciate if I get a help how to use this library for my set of data.. My data set look like Geno file Name1 1 1 2 2 2 2 N

Re: [R] Conditional Random selection

2015-11-21 Thread Ashta
now how to form a data.frame. > > > tmp <- tapply(tab1$S1, tab1$time, function(x) length(unique(x))) > data.frame(time = names(tmp), S1 = tmp) > > Rui Barradas > > > Citando Ashta : > > Hi Rui , > > > > I tried that one before I send out my origin

Re: [R] Conditional Random selection

2015-11-21 Thread Ashta
llo, > > Try > > tapply(tab$S1, tab$time, function(x) length(unique(x))) > > Hope this helps, > > Rui Barradas > > > Citando Ashta : > > Hi Bert and all, > I have related question. In each time period there were different > locations where the s

Re: [R] Conditional Random selection

2015-11-21 Thread Ashta
TRUE) what I want is time S1 12 21 33 Thank you again. On Sat, Nov 21, 2015 at 1:30 PM, Ashta wrote: > Thank you Bert! > > What I want is at least 500 samples based on random sampling of time > period. This allows samples collected at the same t

Re: [R] Conditional Random selection

2015-11-21 Thread Ashta
; }),] > > Cheers, > Bert > > > Bert Gunter > > "Data is not information. Information is not knowledge. And knowledge > is certainly not wisdom." >-- Clifford Stoll > > > On Sat, Nov 21, 2015 at 10:56 AM, Ashta wrote: >> Thank you David! >

Re: [R] Conditional Random selection

2015-11-21 Thread Ashta
t; of times 6, 7, and 8 will never appear because the > sum of the values is 586. > > > David L. Carlson > Department of Anthropology > Texas A&M University > > -Original Message- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Ashta > Sent: Satur

[R] Conditional Random selection

2015-11-21 Thread Ashta
Hi all, I have a data set that contains samples collected over time. In each time period the total number of samples are given (X2) The goal is to select 500 random samples.The selection should be based on time (select time periods until I reach 500 samples). Also the time period should

Re: [R] Ranking

2015-11-14 Thread Ashta
gt; USA 1 2 3 > > I'll let you figure out how to get the last column. > > David L. Carlson > Department of Anthropology > Texas A&M University > > -Original Message- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Ashta > Sent: Saturday

[R] Ranking

2015-11-14 Thread Ashta
Hi all, I have the following raw data some records don't have the second variable. test <- read.table(textConnection(" Country STATUS USA USAW USAW GER GERW GERw GERW UNKW UNK UNKW FRA FRA FRAW FRAW FRAW SPA SPAW SPA "),header = TRUE, sep= "

Re: [R] Cleaning

2015-11-11 Thread Ashta
am I missing here? On Wed, Nov 11, 2015 at 7:54 PM, Sarah Goslee wrote: > On Wed, Nov 11, 2015 at 8:44 PM, Ashta wrote: > > Hi Sarah, > > > > I used the following to clean my data, the program crushed several times. > > > > test <- dat[dat$Var1 == "YYZ&

Re: [R] Cleaning

2015-11-11 Thread Ashta
t; Var1 %in% myvalues > > Sarah > > On Wed, Nov 11, 2015 at 7:10 PM, Ashta wrote: > > Thank you Sarah for your prompt response! > > > > I have the list of values of the variable Var1 it is around 20. > > How can I modify this one to include all the 20 valid valu

[R] Cleaning

2015-11-11 Thread Ashta
Hi all, I have a data frame with huge rows and columns. When I looked at the data, it has several garbage values need to be cleaned. For a sample I am showing you the frequency distribution of one variables Var1 Freq 1:3 2]6 3MSN 1040 4YYZ 300 5\\4 6+

Re: [R] curve

2010-12-13 Thread Ashta
Thanks Sarah, > 1. to shade or color (blue) the curve using the criterion that any values greater than 11,000 I think I was not clear in the above point. I want shade not the line but the area under the curve, and Your last line of code, segments(x0=mean(test1), y0=0, y1=curveheight) gave me th

[R] Survival

2010-03-20 Thread Ashta
Hi All, I was trying to find a function that handles Partially Linear Single-Index model in survival analysis, but was not lucky. Is thee a function in R for this type of analysis? Thanks A __ R-help@r-project.org mailing list https://stat.ethz.ch/m

[R] likelihood

2010-03-08 Thread Ashta
Hi all, Does any one know how to write the likelihood function for Poisson distribution in R when P(x=0). For normal case, it an be written as follows, n * log(lambda) - lambda * n * mean(dat) Any help is highly appreciated Ashta

[R] Histogram color

2010-03-04 Thread Ashta
In a histogram , is it possible to have different colors? Example. I generated x <- rnorm(100) hist(x) I want the histogram to have different colors based on the following condition mean(x)+sd(x) with red color and mean(x) - sd(x) with red color as well. The middle one with blue color.

[R] Step function

2010-01-29 Thread Ashta
Hi All, Does the step function work in this model? I tried to run the following model but no result obtained. The computer is hanging and I killed the job several times. Below is the code. library(survival) m.fit=clogit(y~x1+x2+x3+x4, data=ftest) summary(m.fit) final<- step(m.fit) Thanks in ad

Re: [R] output

2010-01-18 Thread Ashta
take ~ weight + season + weight*season, data = DF) > > On Mon, Jan 18, 2010 at 2:00 PM, Ashta wrote: >> Hi all, >> I am trying to interparete  the result of the following output from  lm; >> >> >> fit1 =lm(Feed _Intake ~ weight + season + weight*season)

[R] output

2010-01-18 Thread Ashta
Hi all, I am trying to interparete the result of the following output from lm; fit1 =lm(Feed _Intake ~ weight + season + weight*season) Season has three classes(x,y,z) Reults are Estimate (Intercept) 21.51559 weight 2.13051 factor(season)y

[R] PH Model assumption

2009-12-10 Thread Ashta
Hi all, I was trying to test the assumption of proportional hazards assumption, I used the cox.zph function >cox.zph(coxfit6) Results are: rhochisqp x1 -0.03961.397 2.37e-01 x2 0.11079.715 1.83e-03 x3 -0.08857.7435.39

Re: [R] Hazard ratio

2009-12-10 Thread Ashta
083921 0.431 0.6665 factor(y1)3 -0.510124 0.600421 0.088901 -5.738 9.57e-09 *** factor(x2)2 -0.510124 0.600421 0.088901 -5.738 9.57e-09 *** What are those values? Is it comparing in reference to the first class of each covariate? Thanks again. On Thu, Dec 10, 2009 at 8:33 AM,

[R] Hazard ratio

2009-12-10 Thread Ashta
Hi all, I want to calculate hazard ratio within each covariate Example, one covariate has 3 classes (1,2 and 3) and x2 has 2 classes I want to compare the relative risk ratio within each class of the covariate. How do I get this result ? . The other question is that how do I interpret the

[R] stepAIC function

2009-12-04 Thread Ashta
Hi All, I am trying to run the following script but have problem, coxm<- coxph(Surv(sdat$time, sdat$cens)~hd+nawtg+nwwg+ntpg+cy+nseas,data=sdat) coxm<-stepAIC(coxm,~.^2) The error message is Error: could not find function "stepAIC" I tried to install the package but I could not find it. Where

[R] look up and Missing

2009-11-08 Thread Ashta
HI R-Users Assume that I have a data frame 'temp' with several variables (v1,v2,v3,v4,v5.). v1 v2 v3 v4 v5 1 2 3 36 5 2 420 2 -9 5 43 6 2 1 34 1, I want to look at the entire row values of when v2 =-9 like 2 -9 5 43 I wrote

Re: [R] Frequency

2009-11-02 Thread Ashta
Thank you Jorge and > res <- table(unlist(x)) > res[order(res, decreasing = TRUE)] > # 10 4 6 3 5 7 9 18 > # 3 2 2 1 1 1 1 1 This one works fine for me. Is it possible to transpose it? I tried t(res[order(res, decreasing = TRUE)]), but it did not work! I want the result like this

[R] Inserting rows

2009-10-23 Thread Ashta
Hi all, I have the data set df with three varaibles, x1 x2 x3 1 2 5 2 4 1 5 6 0 1 1 2 I want to insert more rows ( eg, 3 rows with value filled with zeros) 1 2 5 2 4 1 5 6 6 1 1 2 0 0 0 0 0 0 0 0 0 Can any body help me out? Thanks __

[R] Wavelets

2009-10-23 Thread Ashta
Hi all, I am trying to do wavelets and I got an error message saying "The length of data is not a power of 2" Is there a way of handing that? or should the data length be exactly the power of 2? I am using R version 2.9.2 (2009-08-24) The is library(wavethresh). wds <- wd(ds$v,filter.numbe

Re: [R] Counting

2009-10-20 Thread Ashta
Hi Bill and all, On Tue, Oct 20, 2009 at 12:09 PM, William Dunlap wrote: >> From: r-help-boun...@r-project.org >> [mailto:r-help-boun...@r-project.org] On Behalf Of Peter Ehlers >> Sent: Tuesday, October 20, 2009 8:48 AM >> To: Ashta >> Cc: R help >> Subje

[R] Counting

2009-10-20 Thread Ashta
Hi All, Assume that I have the following data set  with two variables and I want count the number of observation with identical values  and number of time each factor changed from x1 to x2. x1  x2  1    1  1    0  0    1  0    1  0    0  1    1 0    1 The output should be x1  changed

[R] Spline

2009-10-19 Thread Ashta
Hi All, I am using R version 2.9.2 (2009-08-24) window version and I wanted to use the > library(spline) Error in library(spline) : there is no package called 'spline' I tried to install packages as well and it is not there either. Am I missing something there. Where can I get this library? Th

[R] Survival and nonparametric

2009-10-14 Thread Ashta
Hi all, Has any body the exprience to iclude a nonparametric component into the survival analysis using R package? *Can someone recommend *me * some ** references? * Thanks a lot Ashta [[alternative HTML version deleted]] __ R-help@r

[R] Counting

2009-10-13 Thread Ashta
*Hi all, * *Assume that I have the following data set with tow variables and I want count the number of observation with identical values * ** *x1 x2* * 1 1 * * 1 0 * * 0 1* * 0 1* * 0 0* * 1 1* * 0 1 * I want the following output ** * * *n1=3 # number of identical ob

[R] Random number

2009-10-11 Thread Ashta
Hi All, I have the matrix called 'X' with 200 rows and 12 variables. I want to create 2 new variables (V1 and V2) based on random number generator p1<-rnorm(200. mean=0, std=1) p2<-rnorm(200. mean=0, std=1) x <- cbind(x, v1=ifelse(x[,'p1'] > 0.4, 1, 0), v2=ifelse(x[,'p2'] > 0.6, 0, 1)) I found

Re: [R] Creating new variables

2009-10-10 Thread Ashta
dataframe, the following will work: > > x$v1 <- ifelse(x$p > 0.4, 1, 0) > x$v2 <- ifelse(x$p > 0.6, 1, 0) > > If it is matrix, try > > x <- cbind(x, v1=ifelse(x[,'p'] > 0.4, 1, 0), v2=ifelse(x[,'p'] > 0.6, 1, > 2)) > > If helps

[R] Creating new variables

2009-10-10 Thread Ashta
Hi all, I have a data set called x with200 rows and 12 columns. I want create two more columns based on probability. ie if p >0 .4 then v1 =1 else v1=0; if p >0 .6 then v2 =1 else v2=0; Finally x will have 14 variables. Can any one show me how to do that? Thanks

[R] Tabulation

2009-10-10 Thread Ashta
Hi all, I have a data set x1 x2 x3 1 2 1 1 2 3 2 1 2 1 2 1 3 1 1 I want to tabulate in the following way. 1 2 3 x13 2 1 x22 3 0 x33 1 1 It is just like frequency distribution Any help is highly appreciated [[alternative

Re: [R] row selection

2009-10-09 Thread Ashta
by=5), ] > > -Original Message- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] > On Behalf Of David Winsemius > Sent: Thursday, October 08, 2009 4:19 PM > To: Ashta > Cc: R help > Subject: Re: [R] row selection > > > On Oct 8, 2009

[R] row selection

2009-10-08 Thread Ashta
Hi all, I have a matrix named x with N by C I want to select every 5 th rrow from matrix x I used the following code n<- nrow(x) > for(i in 1: n){ + b <- a[i+5,] >b } Error: subscript out of bounds Can any body point out the problem? [[alternative HTML version deleted]] __

Re: [R] Plot

2009-10-06 Thread Ashta
gt; Generally this list is happy to help, but we like some evidence that the > querent has *tried* before inquiring. > > Sarah > > On Tue, Oct 6, 2009 at 10:05 AM, Ashta wrote: > > Hi All, > > > > > > Days <- matrix(c("Monday", "Tuesday"

[R] Plot

2009-10-06 Thread Ashta
Hi All, Days <- matrix(c("Monday", "Tuesday", "Wed", "Thu", "Fri", "Sat", "Sun"),7,1) Hum <-matrix(c(56,57,60,75,62,67,70), Temp<-matrix(c(76,77,81,95,82,77,83), Using the above information I want plot humidity and temperature on Y-axis and days on X-axis Any help is appreciated! [

[R] Legend

2009-10-02 Thread Ashta
I have more than three lines in one and I want to add a legend for each line abline( m1, col = 'red' ) ablime( m2, col = 'blue' ) abline( m3, col = 'purple' ) How can I add a legend? . Is it also possible to increase the thickness of the lines? Thanks [[alternative HTML version delete

[R] Color of graph

2009-10-01 Thread Ashta
I am trying to plot a line graph for 3 or more regression lines abline(m1) abline(m2) abline(m3) Can I change the color of each line? if so how? Thanks in advance Ashta [[alternative HTML version deleted]] __ R-help@r-project.org mailing

[R] Summary

2009-09-29 Thread Ashta
My data is called xc and has more than 15 variables. When I used summary(xc) it gave me the detail description of each variable. Summary(xc) Y1x1 x2 x3 .. Min. :0. Min. : 1.000 Min. : 1.000 Min. : 1.000 1st Qu

[R] SEa nd CI

2009-09-25 Thread Ashta
How can I get the the standard error and confidence interval for the prediction in a multiple regression model using the R command? for a simple regression I used *predict(xc, newdata=data.frame(var1=10.),se=T) where xc is the glm model using binomial and var1 is teh variable. * I can get the u

[R] Binomial

2009-09-25 Thread Ashta
the outcome. I want to fit a binomial model . How do I do that? I am guessing the response variable should be transformed but not sure which family of transformation to use. It is easy to do it in SAS but I just want to learn using R Any help is highly appreciated Ashta [[alternative HTML

[R] Modelling

2009-09-24 Thread Ashta
the outcome. I want to fit a binomial model in R . I want also to rder the factors based on their degree of influence the outcome. How do I do this in R. thanks in advance Ashta [[alternative HTML version deleted]] __ R-help@r-project.org

[R] Reading data

2009-09-23 Thread Ashta
Dear R-users, I am a new user for R. I am eager to lean about it. I wanted to read and summary of the a simple data file I used the following, rel <- read.table("C:/Documents and Settings/ashta/My Documents/R_data/rel.dat", quote="",header=FALSE,sep=&quo