Thanks. Very informative.
I certainly missed this.
-- Bert
On Sat, Dec 3, 2022 at 3:49 PM Hervé Pagès
wrote:
> On 03/12/2022 07:21, Bert Gunter wrote:
> > Perhaps it is worth pointing out that looping constructs like lapply()
> can
> > be avoided and the procedure vectorized by mimicking Martin
This may be a fairly dumb and often asked question about some functions like
strsplit() that return a list of things, often a list of ONE thing that be
another list or a vector and needs to be made into something simpler..
The examples shown below have used various methods to convert the result
On 03/12/2022 07:21, Bert Gunter wrote:
Perhaps it is worth pointing out that looping constructs like lapply() can
be avoided and the procedure vectorized by mimicking Martin Morgan's
solution:
## s is the string to be searched.
diff(c(0,grep('b',strsplit(s,'')[[1]])))
However, Martin's solutio
Perhaps it is worth pointing out that looping constructs like lapply() can
be avoided and the procedure vectorized by mimicking Martin Morgan's
solution:
## s is the string to be searched.
diff(c(0,grep('b',strsplit(s,'')[[1]])))
However, Martin's solution is simpler and likely even faster as the
Às 17:18 de 02/12/2022, Evan Cooch escreveu:
Was wondering if there is an 'efficient/elegant' way to do the following
(without tidyverse). Take a string
abaaabbabaaab
Its easy enough to count the number of times the character 'b' shows up
in the string, but...what I'm looking for is outpu
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