Okay, I can't help much with the ggplot stuff so forget the "lty="
argument for that is base graphics. However, you may get away with
ggtitle(paste0("COVID-19 Tests in Ohio \n(",date[length(date]),")"))+
I don't know whether the tidy* stuff handles indexing in the same way as base R.
Jim
On Wed
Dear Stephen, I reply you inline:
On 2020-08-18 11:09 -0700, Bert Gunter wrote:
| On Tue, Aug 18, 2020 at 10:10 AM Stephen P. Molnar
wrote:
| |
| | Thanks to the kind folks on this
| | list, this is an elegant replacement
| | for the clumsy R script that I that
| | I wrote.
| |
| |
| |
| |
1. Generally you should make your posts self-contained -- I see no line
14's or 33's or whatever. Note that you did not continue the old thread
either. I have no desire to go poking around in previous threads (others
certainly may!).
2. Re: max of dates.
max(as.Date(c("1976-04-07","1982-02-22"))
Thanks to the kind folks on this list, this is an elegant replacement
for the clumsy R script that I that I wrote.
However, I do have a few changes that I would like to make. The problem
is that while I know how to make changes in Python, I am still bumbling
around in R Code.
The day-to-d
Hi
Probably patternbar handles legend position in nonstandard way so
lebend.position does not work as expected.
Rotating % is done by axis.title.y ...
theme(axis.text.x = element_text(angle = 90),
axis.title.y = element_text(angle=0),
aspect.ratio= 0.4)
Legend has to be placed probably by legen
Hi
maybe
min(abs(outer(x,y, "-")))
If you want indices
mm <- min(abs(outer(x,y, "-")))
which(abs(outer(x,y, "-"))== mm, arr.ind=TRUE)
And in original vectors
x[which(abs(outer(x,y, "-"))== mm, arr.ind=TRUE)[1]]
y[which(abs(outer(x,y, "-"))== mm, arr.ind=TRUE)[2]]
Cheers
Petr
> -Origina
On 2020-08-18 16:36 +0200, Rasmus Liland wrote:
> On 2020-08-18 22:59 +0900, Joon-Taek Yoo wrote:
> | Dear Helpers,
> | I am trying to draw a map of East Asia
> | using the getNOAA.bathy ()
> | function(package marmap) in R. I'v got
> | a following error message.
> |
> | > dat <- getNOAA.bathy(
On 2020-08-18 22:59 +0900, Joon-Taek Yoo wrote:
| Dear Helpers,
| I am trying to draw a map of East Asia
| using the getNOAA.bathy ()
| function(package marmap) in R. I'v got
| a following error message.
|
| > dat <- getNOAA.bathy(110, 160, 20, 60, res=4, keep=T)
| Querying NOAA database ...
|
I think you are more likely to get a helpful reply on the R-sig-geo list
rather than here.
If all else fails, try contacting the maintainer ( ?maintainer) .
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka
Dear Helpers,
I am trying to draw a map of East Asia using the getNOAA.bathy ()
function(package marmap) in R. I'v got a following error message.
> dat <- getNOAA.bathy(110, 160, 20, 60, res=4, keep=T)
Querying NOAA database ...
This may take seconds to minutes, depending on grid size
Error in .lo
On 2020-08-18 11:02 +1200, Paul Murrell wrote:
| On 18/08/20 9:54 am, Bert Gunter wrote:
| | On Mon, Aug 17, 2020 at 2:14 PM wrote:
| | |
| | | Plotmath seems to be the right way
| | | to do it. But without reading
| | | plotmath I'd have gone with this:
| | |
| | | plot(y, main=paste("data",
On 2020-08-17 14:50 -0400, Duncan Murdoch wrote:
|
| Certainly you should be able to delete
| Pandoc if you have permissions to
| install it; that may break RMarkdown
| if you don't have another copy
| somewhere.)
I use Rmarkdown outside of Rstudio, just
with rmarkdown::render in an Rscript
This looks more like a code challenge than a real problem, but anyway Rcpp
seems unnecessary.
x <- (2:5)^2/3
y <- (1:6)+0.1
ad <- function( a, b ) {
abs( a - b )
}
M <- outer( x, y, FUN=ad )
which( M==min(M), arr.ind = TRUE )
On August 18, 2020 12:00:09 AM PDT, Dario Strbenac
wrote:
>Good da
Good day,
What is a fast and efficient way to calculate the minimum absolute difference
between two vectors of numbers? The two vectors have unequal length. I would
also like to know the index of the first vector and the second vector which
results in the minimum absolute difference. For exampl
Hi
You probably do not have date in your data. Or date in R sense. What
str(df_c_m) tells you about your date. I believe date is factor or character
variable, which need to be converted do Date variable by appropriate way -
e.g. strptime or as.Date.
BTW, "dput" result is useful for exchanging
15 matches
Mail list logo
