Ummm... rather vague, and I certainly have no clue. But if you haven't
already done so, have a look here:
https://cran.r-project.org/web/views/
And of course, you should always try googling, e.g. on "supply chain
optimization using R" , etc.
Bert Gunter
"The trouble with having an open mind is
R-Help Forum
Anyone ever perform supply chain optimization, operations optimization or
sales optimization in R? If so what packages should I look to?
Sincerely
Jeff Reichman
(314) 457-1966
[[alternative HTML version deleted]]
___
Hello,
If groups are factors, pass the level you want to annotate.
This works, note the 'x' value:
ggplot(iris, aes(Species, Petal.Length)) +
geom_boxplot() +
annotate(geom = "text", x = "versicolor", y = 6, label = "16 u")
Hope this helps,
Rui Barradas
Às 20:26 de 19/02/20, Thomas Subi
Since factor levels (groups) are coded by integers, you can use 1, 2, 3
etc. as your x values. If you want to annotate in between you can simply
pick values in between 1, 2, 3, etc.
On Wed, Feb 19, 2020, 13:26 Thomas Subia, wrote:
> Colleagues,
>
> To add an annotation using ggplot, I've used
>
Colleagues,
To add an annotation using ggplot, I've used
annotate("text",x=17,y=2130,label="16 u").
However, this does not work when trying to annotate box plots by groups since
groups are factors.
Any advice would be appreciated.
Thomas Subia
ASQ CQE
IMG Companies
225 Mountain Vista Parkw
Sorry there were some errors in my email. Use this instead.
Assuming that they both cover the same period of time then
if you are willing to throw away some points then
consider using only these 256 elements from the 305 series
round(seq(1, 305, length = 256))
## [1] 1 2 3 5
That is
Assuming that they both cover the same period of time then
if you are willing to throw away some points then
consider using only these 256 elements from the 305 series
round(seq(1, 305, length = 50))
## [1] 1 7 13 20 26 32 38 44 ...etc...
That is use the 1st ,7th, 13th, etc. point i
Thanks. Yes. I did that, it also has a verbose mode so that I could see what
it was doing. What I needed was not just escaping but strict escaping. My
memory forma number of years back was that I had issues with urlencode from
base not being strict. And of course you don't what to encode t
Use cumsum(logicalVector) to increment a counter at the TRUE positions in
logicalVector. . E.g.,
> d <- c(NA, 0, 0, 0, 8, 0, 577, 69, 0)
> is_true <- function(x) !is.na(x) & x
> 1 + cumsum( is_true(d >= 15) )
[1] 1 1 1 1 1 1 2 3 3
Some packages have the equivalent of that is_true function, which
Hi,
Perhaps you could test it out by using httr::GET() with and without
escaping using xml2::url_escape()?
https://www.rdocumentation.org/packages/xml2/versions/1.2.2/topics/url_escape
Cheers,
Ben
On Tue, Feb 18, 2020 at 1:29 PM Roy Mendelssohn - NOAA Federal via
R-help wrote:
>
> Hi All:
>
>
Dear all,
Could you please help me how to get the output as I described in the following
example?
x<-c(543, 543, 543, 543, 551 , 551 ,1128 ,1197, 1197)
diff<-x-lag(x)
diff
[1] NA 0 0 0 8 0 577 69 0
How to index the occasions in x repeatedly if the diff<15? if diff>=15, it will
You should read about statistical imputation and decide what approach is
appropriate for your data. This mailing list is for questions about R, not
about statistics. Once you know what algorithm you need to apply, look up R
functions that implement that algorithm using Google or the CRAN Task Vi
Dear All,
I want to convert irregular time series daily data in to ts objects. For
some years I have 305 days data and some years I have 256 days.
I need your suggestion regarding the same.
I have read tutorial on the same but not able to find solutions.
With regards,
Upananda
[[altern
Hello,
Yes, or even simpler is to assume that the first group starts at the
first element of x, a reasonable assumption.
cumsum(c(TRUE, diff(x) > 15))
Hope this helps,
Rui Barradas
Às 10:36 de 19/02/20, PIKAL Petr escreveu:
Hi
You could get similar result with using diff function Rui sug
Hi
You could get similar result with using diff function Rui suggested
c(1,cumsum((diff(x)>15))+1)
[1] 1 1 1 1 1 1 2 3 3
Cheers
Petr
> -Original Message-
> From: R-help On Behalf Of Rui Barradas
> Sent: Wednesday, February 19, 2020 8:13 AM
> To: Lijun Zhao ; r-help@r-project.org
> Subj
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