Nobody else has asked the obvious question: why are the data squashed
together
like that in the first place? why not modify the process that generates the
data so that it does not do that? Jamming things together like that is not
common practice with CSV files, so what does the CSV file look lik
This is probably a suboptimal list for your message. If you have not
already done so, you should post it to R-package-devel and the
Bioconductor development list,
https://stat.ethz.ch/mailman/listinfo/bioc-devel .
Cheers,
Bert Gunter
"The trouble with having an open mind is that people keep co
Hey all,
I wanted to draw your attention to a new grants program we launched today
at the Chan Zuckerberg Initiative, aiming to fund *open source scientific
software* with significant adoption within the life sciences and biomedical
research communities.
We'd love to see applications from develop
My apologies. I negected to cc r-help. -- Bert
On Tue, Jun 18, 2019 at 11:21 AM Bert Gunter wrote:
>
> I assume that 2215 means year 2000, month 2, day 15.
> I also assume that you want maxes for the first 2 weeks of a month, the
> second 2 weeks, and any remaining days.
> I also assume th
I've been working on a fairly extensive R package for a few years with
ongoing testing with Travis CI. Today, though, I'm seeing an error in
installing the gsl package both at Travis and from the Windows GUI:
install.packages("gsl",repos = getOption("repos"), repo=NULL, type="source")
# gives the
Hi Bert and Jeff,
Thanks a lot for your response. I have been able to solve the problem with
pointers added from people who responded.
My original dataset was in the form of a vector, my desired goal is to convert
it into a data.frame. which I have been able to do.
Thanks again for all your hel
Thanks a lot Boris, I tried out your worked out solution and it works just
perfectly fine. No doubt I need a lot of practice with regexr and the pattern
stated by you - I will do that now. Thanks a lot for pointing me in the right
direction. Appreciate it a lot.
Sam.
On Monday, 17 June 2
A new package called APFr for threshold selection in large scale inference
problems using robust estimates of Average Power Function and Bayes FDR, is
available.
CRAN: https://cran.r-project.org/web/packages/APFr/index.html
An illustrative example can be found at:
https://www.researchgate.net/pub
Dear R community members, please find here a short presentation of our new
package.
We introduce GuessCompx, a new R package that makes an empirical guess on
the time and memory complexities of an algorithm or a function. It will
test multiple, increasing-sizes samples of the user’s data and try t
Hi,
I'm Aisyah..I have a problem to run my R coding. I want to select maximum value
according to week.
here is my data
Date O3_Conc
21010.033
21020.023
21030.025
21040.041
21050.063
21060.028
21070.068
> Eric Berger
> on Tue, 18 Jun 2019 16:33:40 +0300 writes:
> That's what my code does.
> On Tue, Jun 18, 2019 at 4:27 PM Jeff Newmiller
> wrote:
>> Assuming Peter's equation applies, I think a direct for loop with
>> multiplication would be a more efficient way t
That's what my code does.
On Tue, Jun 18, 2019 at 4:27 PM Jeff Newmiller
wrote:
> Assuming Peter's equation applies, I think a direct for loop with
> multiplication would be a more efficient way to obtain this answer than
> repeated use of a power operator.
>
> On June 18, 2019 8:01:09 AM CDT, M
On 18/06/2019 9:01 a.m., Eric Berger wrote:
Very nice, Peter.
Here is one version of Peter's suggestion expressed in R code
M <- M | t(M) # first step as symmetric matrix as stated by OP
Q <- M
for ( i in 2:(ncol(Q)-1) )
Q <- Q + Q %*% M
R <- (Q > 0)
R
That's not quite the same calculat
Assuming Peter's equation applies, I think a direct for loop with
multiplication would be a more efficient way to obtain this answer than
repeated use of a power operator.
On June 18, 2019 8:01:09 AM CDT, Martin Maechler
wrote:
>> peter dalgaard
>> on Tue, 18 Jun 2019 11:45:39 +02
Very nice, Peter.
Here is one version of Peter's suggestion expressed in R code
M <- M | t(M) # first step as symmetric matrix as stated by OP
Q <- M
for ( i in 2:(ncol(Q)-1) )
Q <- Q + Q %*% M
R <- (Q > 0)
R
HTH,
Eric
On Tue, Jun 18, 2019 at 12:46 PM peter dalgaard wrote:
> Sounds like
> peter dalgaard
> on Tue, 18 Jun 2019 11:45:39 +0200 writes:
> Sounds like this is isomorphic to reachability in graph
> theory. I wonder if
> (sum_1^n M^i) > 0
> would suffice?
neat! (and I guess correct)
> -pd
Which reminds me that in the relatively dista
Sounds like this is isomorphic to reachability in graph theory. I wonder if
(sum_1^n M^i) > 0
would suffice?
-pd
> On 18 Jun 2019, at 02:08 , Duncan Murdoch wrote:
>
> On 17/06/2019 7:34 p.m., Bert Gunter wrote:
>> Depends on what you mean by "simple" of course, but suppose that:
>> M[i,j]
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